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What is the difference between \(\bar{x}\) and \(\mu ?\) between \(s\) and \(\sigma\) ?

Short Answer

Expert verified
The sample mean \( \bar{x} \) and sample standard deviation \( s \) are calculated from a sample of data, and provide estimates for the population mean \( \mu \) and population standard deviation \( \sigma \), respectively, which are calculated from all data points in the population.

Step by step solution

01

Definition of Sample Mean \( \bar{x} \)

The sample mean is the average of a set of data from a sample taken from a larger population. It provides an estimate of the population mean. It is calculated by summing up all the values in the sample and then dividing by the number of data points in the sample.
02

Definition of Population Mean \( \mu \)

The population mean on the other hand, is the exact average of every single data point in a population. It is calculated the same way as the sample mean but includes every data point in the entire population.
03

Definition of Sample Standard Deviation \( s \)

The sample Standard Deviation is a measure of the amount of variation or dispersion of a set of values in a sample. It is calculated by taking the square root of the variance of the sample.
04

Definition of Population Standard Deviation \( \sigma \)

The population Standard Deviation, is a measure of the amount of variation or dispersion of a set of values in the entire population. It is also calculated as the square root of the variance, but the variance here includes all data points in the entire population.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, denoted by \( \bar{x} \), is a statistical measure used to estimate the central tendency of a sample taken from a larger population. To find the sample mean, add up all the sample values and divide the total by the number of values in the sample. This is often used when it is impractical to measure every item in an entire population. Sampling allows researchers to make inferences about the overall population based on a smaller, manageable dataset. For example, if we have three test scores: 85, 90, and 95, the sample mean is calculated as \( \bar{x} = \frac{85 + 90 + 95}{3} = \frac{270}{3} = 90 \). This gives us the average score of these few individuals, suggesting what the average might be for the entire group if further scores followed the same trend.
Population Mean
The population mean, represented by the symbol \( \mu \), is the true average of every data point in an entire population. Unlike the sample mean, which is based on a small part of the population, the population mean involves computing the mean with all possible data points. This makes it an ideal measure in theoretical studies or when you can examine the entire population. To compute it, sum all data points and divide by the total number of data points. Suppose an entire population consists of the following ages: 22, 24, 26, 28, and 30. The population mean \( \mu \) is calculated as \( \mu = \frac{22 + 24 + 26 + 28 + 30}{5} = \frac{130}{5} = 26 \). It gives us the actual central value of this demographic group.
Standard Deviation
Standard deviation is a vital statistical tool that measures the amount of variance or dispersion in a set of values. When applied to a sample, it's known as the sample standard deviation, denoted by \( s \). For a population, it's called the population standard deviation, represented as \( \sigma \).
The standard deviation tells us how much the data values deviate from the mean. A lower standard deviation indicates that the values are closer to the mean, while a higher standard deviation suggests more spread out data. To calculate it, first find the variance (the average of squared differences from the mean), then take the square root. Suppose the set of sample values is 2, 4, and 6. The sample mean \( \bar{x} \) is 4, variance \( s^2 \) is 2.66, and so the sample standard deviation is \( s = \sqrt{2.66} \approx 1.63 \). This tells us the data typically lies 1.63 units away from the mean.
Variance
Variance is a statistical measure that quantifies the extent of data dispersion from the mean. It plays an essential role in statistics, as it helps us understand how spread out a data set is. For a sample, the variance is denoted as \( s^2 \), and for a population, it is \( \sigma^2 \).
To compute variance, first find the mean of the dataset, then subtract the mean from each data point and square the result. Sum these squared differences and divide by the number of data points for a population, or by the number of data points minus one for a sample (to correct bias).
  • An example: suppose you have a sample of 4, 5, and 8. The sample mean \( \bar{x} \) is 5.67.
  • Subtract the mean from each: \( (4 - 5.67)^2, (5 - 5.67)^2, (8 - 5.67)^2 \)
  • Square the results and sum them: \( 2.79 + 0.45 + 5.45 = 8.69 \)
  • Divide by sample size minus one: \( \frac{8.69}{2} = 4.345 \).
Variance gives us insight into data variability, just like standard deviation, but squares the units, influencing interpretation.

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Most popular questions from this chapter

The article "Unmarried Couples More Likely to Be Interracial" ( \mathrm{\\{} S a n ~ Luis Obispo Tribune, March 13,2002 ) reported that \(7 \%\) of married couples in the United States are mixed racially or ethnically. Consider the population consisting of all married couples in the United States. a. A random sample of \(n=100\) couples will be selected from this population and \(p\), the proportion of couples that are mixed racially or ethnically, will be computed. What are the mean and standard deviation of the sampling distribution of \(p\) ? b. Is it reasonable to assume that the sampling distribution of \(p\) is approximately normal for random samples of size \(n=100\) ? Explain. c. Suppose that the sample size is \(n=200\) rather than \(n=100\), as in Part (b). Does the change in sample size change the mean and standard deviation of the sampling distribution of \(p ?\) If so, what are the new values for the mean and standard deviation? If not, explain why not. d. Is it reasonable to assume that the sampling distribution of \(p\) is approximately normal for random samples of size \(n=200\) ? Explain. e. When \(n=200\), what is the probability that the proportion

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Consider the following population: \(\\{1,2,3,4\\}\). Note that the population mean is $$ \mu=\frac{1+2+3+4}{4}=2.5 $$ a. Suppose that a random sample of size 2 is to be selected without replacement from this population. There are 12 possible samples (provided that the order in which observations are selected is taken into account): \(\begin{array}{cccccc}1,2 & 1,3 & 1,4 & 2,1 & 2,3 & 2,4 \\ 3,1 & 3,2 & 3,4 & 4,1 & 4,2 & 4,3\end{array}\) Compute the sample mean for each of the 12 possible samples. Use this information to construct the sampling distribution of \(\bar{x}\). (Display the sampling distribution as a density histogram.) b. Suppose that a random sample of size 2 is to be selected, but this time sampling will be done with replacement. Using a method similar to that of Part (a), construct the sampling distribution of \(\bar{x}\). (Hint: There are 16 different possible samples in this case.) c. In what ways are the two sampling distributions of Parts (a) and (b) similar? In what ways are they different?

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