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Suppose that a sample of size 100 is to be drawn from a population with standard deviation \(10 .\) a. What is the probability that the sample mean will be within 2 of the value of \(\mu\) ? b. For this example \((n=100, \sigma=10)\), complete each of the following statements by computing the appropriate value: i. Approximately \(95 \%\) of the time, \(\bar{x}\) will be within ____ of \(\mu .\) ii. Approximately \(0.3 \%\) of the time, \(\bar{x}\) will be farther than ____ from \(\mu\).

Short Answer

Expert verified
a) Approximately 97.72% of the time the sample mean will be within 2 of the population mean. b) i) Approximately 95% of the time, the sample mean will be within 1.96 of the population mean. ii) Approximately 0.3% of the time, the sample mean will be farther than 2.58 from the population mean.

Step by step solution

01

Understand the notation

To begin with, it is important to understand the notation given. Here we have \(n = 100\), which indicates the size of the sample to be drawn, and \(\sigma = 10\), which is the standard deviation of the population. Also, \(\mu\) refers to the population mean.
02

Calculate the standard error

Firstly, we need to find the standard error (SE) which is calculated as the standard deviation \(\sigma\) divided by the square root of the number of samples \(n\). SE = 10 / sqrt(100) = 10 / 10 = 1.
03

Find the z-score

Next, we have to calculate the z-scores corresponding to the probabilities in the question. A z-score is a measure of how many standard deviations away a value is from the mean. For the first part a, we want to find the probability that the sample mean is within 2 of \(\mu\). The z-score is calculated as the difference between the observed value and the mean, divided by the standard error. So the z-score is 2 / SE = 2 / 1 = 2. Looking this value up in a standard z-score table, we find that the probability is 0.9772, or 97.72%.
04

Calculate the values for part b

For part b, we use the z-scores that correspond to 95% and 99.7% (the complement of 0.3%) probability. In a standard normal distribution, 95% of the time, the value will be within 1.96 standard deviations of the mean, and 99.7% of the time, the value will be within 2.58 standard deviations of the mean. Part (i): So, 1.96 times our SE (1) equals 1.96. This means that 95% of the time, \(\overline{x}\) will be within 1.96 of \(\mu\). Part (ii): Similarly, 2.58 times our SE (1) equals 2.58. This means that 0.3% of the time, \(\overline{x}\) will be farther than 2.58 from \(\mu\).
05

Conclusion

In conclusion, for a sample size of 100 and a standard deviation of 10, approximately 97.72% of the time the sample mean will be within 2 of the population mean. Also, 95% of the time, the sample mean will be within 1.96 of the population mean, and 0.3% of the time, it will be farther than 2.58 from the population mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is one of the most important concepts in statistics and signifies the amount of variation or spread that exists in a set of data values. It tells us how much the values in a dataset differ from the mean (average) of the data.

When the standard deviation is low, it indicates that the data points are close to the mean, showing less variability. Conversely, a high standard deviation means that the data points are spread out over a wider range of values. This is crucial in understanding the overall distribution of data and is represented by the symbol \( \sigma \) for population standard deviation and \( s \) for sample standard deviation.

To calculate the standard deviation, you typically find the average of all data points, subtract the average from each data point to find the difference (the deviation), square each of these deviations, average those squared deviations (this is called the variance), and then take the square root of that average (the variance). Mathematically, standard deviation for a population is calculated as:
Z-score
A z-score is a statistical measure that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. It is a way of standardizing scores on the same scale, allowing comparison between different data sets.

The formula for calculating a z-score is given by \( z = \frac{{x - \mu}}{{\sigma}} \), where \( x \) is the value being considered, \( \mu \) is the mean of the data set, and \( \sigma \) is the standard deviation. A z-score tells us how many standard deviations away from the mean a value is.

For instance, a z-score of 2 means the value is two standard deviations above the mean, while a z-score of -2 means the value is two standard deviations below the mean. Z-scores make it possible to compare measurements from different data sets that have different means and standard deviations, and are a fundamental component of the standard normal distribution.
Standard Error
Standard error is a statistical term that measures the accuracy with which a sample distribution represents a population by using standard deviation. It is essentially the standard deviation of the sampling distribution of a statistic, most commonly the mean. The standard error gives us an idea of how far the sample mean is likely to be from the population mean.

The formula for standard error of the mean (SEM) is \( SE = \frac{{\sigma}}{{\sqrt{n}}} \), where \( \sigma \) is the standard deviation of the population and \( n \) is the sample size. A smaller standard error indicates that the sample mean is a more accurate reflection of the population mean.

In many cases, we use the standard error to calculate confidence intervals, which give us a range that has a certain probability of containing the population mean. It is also an essential component in computing z-scores for hypothesis testing.
Normal Distribution
The normal distribution, also known as the Gaussian distribution, is a continuous probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

In graph form, this distribution will appear as the familiar bell curve, which has a peak at the mean, and the probabilities for values further from the mean taper off symmetrically in both directions. Most scores are around the average, making it a popular distribution in statistics for natural and social phenomena.

The standard normal distribution is a special case of the normal distribution. It has a mean of 0 and a standard deviation of 1. It is used to convert any normal distribution to a standard form, so z-scores can be easily found. This can be helpful for calculating probabilities and for hypothesis testing.

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Most popular questions from this chapter

Consider a population consisting of the following five values, which represent the number of video rentals during the academic year for each of five housemates: \(\begin{array}{lllll}8 & 14 & 16 & 10 & 11\end{array}\) a. Compute the mean of this population. b. Select a random sample of size 2 by writing the numbers on slips of paper, mixing them, and then selecting 2 . Compute the mean of your sample. c. Repeatedly select samples of size 2, and compute the \(\bar{x}\) value for each sample until you have the results of 25 samples. d. Construct a density histogram using the \(25 \bar{x}\) values. Are most of the \(\bar{x}\) values near the population mean? Do the \(\bar{x}\) values differ a lot from sample to sample, or do they tend to be similar?

The nicotine content in a single cigarette of a particular brand has a distribution with mean \(0.8 \mathrm{mg}\) and standard deviation \(0.1 \mathrm{mg}\). If 100 of these cigarettes are analyzed, what is the probability that the resulting sample mean nicotine content will be less than 0.79? less than 0.77?

Consider the following population: \(\\{2,3,3,4,4\\}\). The value of \(\mu\) is \(3.2\), but suppose that this is not known to an investigator, who therefore wants to estimate \(\mu\) from sample data. Three possible statistics for estimating \(\mu\) are Statistic \(1:\) the sample mean, \(\bar{x}\) Statistic 2: the sample median Statistic 3 : the average of the largest and the smallest values in the sample A random sample of size 3 will be selected without replacement. Provided that we disregard the order in which the observations are selected, there are 10 possible samples that might result (writing 3 and \(3^{*}, 4\) and \(4^{*}\) to distinguish the two 3 's and the two 4 's in the population): \(\begin{array}{rllll}2,3,3^{*} & 2,3,4 & 2,3,4^{*} & 2,3^{*}, 4 & 2,3^{*}, 4^{*} \\ 2,4,4^{*} & 3,3^{*}, 4 & 3,3^{*}, 4^{*} & 3,4,4^{*} & 3^{*}, 4,4^{*}\end{array}\) For each of these 10 samples, compute Statistics 1,2, and 3. Construct the sampling distribution of each of these statistics. Which statistic would you recommend for estimating \(\mu\) and why?

A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, a random sample of 200 cartridges is selected, and each cartridge is inspected. If the sample proportion of defective cartridges is more than \(.02\), the entire shipment is returned to the vendor. a. What is the approximate probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is .05? b. What is the approximate probability that a shipment will not be returned if the true proportion of defective cartridges in the shipment is . 10 ?

Suppose that the mean value of interpupillary distance (the distance between the pupils of the left and right eyes) for adult males is \(65 \mathrm{~mm}\) and that the population standard deviation is \(5 \mathrm{~mm}\). a. If the distribution of interpupillary distance is normal and a sample of \(n=25\) adult males is to be selected, what is the probability that the sample average distance \(\bar{x}\) for these 25 will be between 64 and \(67 \mathrm{~mm}\) ? at least \(68 \mathrm{~mm}\) ? b. Suppose that a sample of 100 adult males is to be obtained. Without assuming that interpupillary distance is normally distributed, what is the approximate probability that the sample average distance will be between 64 and \(67 \mathrm{~mm}\) ? at least \(68 \mathrm{~mm}\) ?

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