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A machine producing vitamin \(E\) capsules operates in such a way that the distribution of \(x=\) actual amount of vitamin \(\mathrm{E}\) in a capsule can be modeled by a normal curve with mean \(5 \mathrm{mg}\) and standard deviation \(0.05 \mathrm{mg}\). What is the probability that a randomly selected capsule contains less than \(4.9 \mathrm{mg}\) of vitamin \(\mathrm{E}\) ? at least \(5.2 \mathrm{mg}\) ?

Short Answer

Expert verified
The probability that a randomly selected capsule contains less than 4.9 mg of Vitamin E is 2.28% and that a randomly selected capsule contains at least 5.2mg of Vitamin E is 0.01%.

Step by step solution

01

Find the Z Score for 4.9mg

Use the formula for calculating the Z score \( Z = (X - μ) / σ \) where X = Random Variable = 4.9mg, μ = Mean = 5mg and σ = Standard Deviation = 0.05mg. After putting the values, we get Z = -2.
02

Calculate the Probability component for less than 4.9 mg

The Z Score -2 in Z-table corresponds to 0.0228 (or 2.28% when converted in percentage terms). Hence, the probability that a randomly selected capsule contains less than 4.9 mg of Vitamin E is 0.0228 or 2.28%.
03

Find the Z Score for 5.2mg

Again, use the formula for calculating the Z score \( Z = (X - μ) / σ \) where X = Random Variable = 5.2mg. After putting the values, we get Z = 4.
04

Calculate the Probability component for at least 5.2 mg

For Z = 4, if we look in the Z-table, the value correlates to 0.9999 (or 99.99% when converted in percentage terms). But since we have to calculate for at least 5.2 mg, we'll look at the other end of the curve so, 1-0.9999 = 0.0001 or 0.01% as the required probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z Score
The Z Score is an important statistical measure that helps us understand where a particular data point lies in relation to the mean of a data set. Think of it as a way to standardize individual scores on a distribution, like vitamin E capsule weights, by accounting for the spread of the distribution, known as the standard deviation.

To calculate the Z Score, one uses the formula: \( Z = \frac{X - μ}{σ} \). Here:
  • \(X\) is the value you are examining - in our example, it's the amount of vitamin E, such as 4.9 mg or 5.2 mg.
  • \(μ\) is the mean of the distribution. In the context of vitamin E capsules, this is given as 5 mg.
  • \(σ\) is the standard deviation, which tells us how much the values can vary around the mean. For these capsules, it's 0.05 mg.
By plugging the values into the formula, we computed the Z Scores: \(-2\) for 4.9 mg and \(4\) for 5.2 mg. These Z Scores are then used to determine probabilities related to these values.
Probability Calculation
Probability calculation using the Z Score involves using a Z-table, which provides the probability that a normally distributed random variable will be less than a given value. In a normally distributed set like the vitamin E capsule weights, probabilities help us determine the likelihood of a capsule having a certain amount of vitamin E.

For 4.9 mg, we calculated the Z Score as \(-2\). Referring to a Z-table, the probability value is 0.0228. This means there's a 2.28% chance that a randomly selected capsule will contain less than 4.9 mg of vitamin E.

Conversely, for capsules to contain at least 5.2 mg of vitamin E, the Z Score is \(4\). The Z-table gives us 0.9999 for this score, indicating the probability that a capsule has up to 5.2 mg. To find the probability of having more than 5.2 mg, we subtract from 1, resulting in a probability of 0.0001 or 0.01%. These probabilities illustrate the rarity or commonness of extreme values in a distribution.
Standard Deviation
Standard deviation is a critical concept in statistics that measures the amount of variation or dispersion in a set of values. In the context of vitamin E capsules, the standard deviation tells us how much the actual amount of vitamin E in the capsules differs from the mean amount of 5 mg.

A smaller standard deviation, like the 0.05 mg in this scenario, indicates that the capsule vitamin E content is clustered closely around the mean. This tight clustering suggests high precision in manufacturing.

Understanding standard deviation helps in interpreting Z Scores. Since Z Scores are expressed in terms of how many standard deviations a particular value is from the mean, the smaller the standard deviation, the more significant even small deviations from the mean become. For example, a Z Score of 2 indicates that the value is two standard deviations away from the mean, which involves a specific range of probabilities as demonstrated in our example calculations.

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