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The average reading speed of students completing a speed-reading course is 450 words per minute (wpm). If the standard deviation is \(70 \mathrm{wpm}\), find the \(z\) score associated with each of the following reading speeds. a. \(320 \mathrm{wpm}\) c. \(420 \mathrm{wpm}\) b. 475 wpm d. 610 wpm

Short Answer

Expert verified
The z-scores for reading speeds 320 wpm, 420 wpm, 475 wpm, and 610 wpm are approximately -1.86, -0.43, 0.36, and 2.29 respectively.

Step by step solution

01

Identify the Mean and Standard Deviation

Given in the problem, the average (mean) reading speed is \( 450 \) words per minute, and the standard deviation is \( 70 \) words per minute.
02

Calculate the Z-score for 320 wpm

Use the formula \[ z = \frac{x - \mu}{\sigma} \]. Substitute \( x = 320 \), \( \mu = 450 \), and \( \sigma = 70 \) into the formula to get \[ z = \frac{320 - 450}{70} \].
03

Calculate the Z-score for 420 wpm

Substitute \( x = 420 \), \( \mu = 450 \), and \( \sigma = 70 \) into the formula to get \[ z = \frac{420 - 450}{70} \].
04

Calculate the Z-score for 475 wpm

Substitute \( x = 475 \), \( \mu = 450 \), and \( \sigma = 70 \) into the formula to get \[ z = \frac{475 - 450}{70} \].
05

Calculate the Z-score for 610 wpm

Substitute \( x = 610 \), \( \mu = 450 \), and \( \sigma = 70 \) into the formula to get \[ z = \frac{610 - 450}{70} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Understanding the concept of standard deviation is crucial when dealing with any form of data that varies. It measures how spread out the numbers in a data set are. In a more technical term, standard deviation is the average distance from the mean of the data set. A small standard deviation indicates that the values in a data set are close to the mean of the data set, while a large standard deviation indicates that the values are spread out over a wider range.

Regarding the z score calculation exercise, knowing the standard deviation allows us to determine how far a particular reading speed is from the average speed, which is essential for finding the z score. If a student reads at 320 wpm, and the standard deviation is 70 wpm, this means the student's speed is more than one standard deviation below the average. Recognizing this helps to contextualize the student's performance.
Normal Distribution
The concept of normal distribution, often referred to as the 'bell curve', is a foundational idea in statistics. It represents a distribution where most of the data points cluster around a central point, known as the mean, with values tapering off symmetrically on both sides as they move away from the mean.

In terms of our exercise, the reading speeds of students are likely to follow a normal distribution, assuming a large and random sample of students. This is important because the z score calculation assumes that the distribution of the variable (reading speed, in this case) is normal. Under a normal distribution, specific z scores correspond to percentages that represent the likelihood of observing a value at or below a given point; an important concept in statistical analysis and interpretation of the z score.
Statistical Analysis
Statistical analysis involves collecting, reviewing, and interpreting data to discover underlying patterns and trends. It is an essential tool for making informed decisions based on quantitative data. In our z score exercise, statistical analysis would involve examining how different reading speeds compare to the average reading speed once the z scores are calculated.

By calculating the z score, we can perform a statistical analysis to identify how individual students' reading speeds differ from the average or expected speed. A z score tells us how many standard deviations an observation is from the mean, which is critical information in understanding whether a reading speed is typical, exceptionally high, or low. This information can be used to assess students' progress and even tailor instruction to improve reading skills.

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Most popular questions from this chapter

Mobile homes are tightly constructed for energy conservation. This can lead to a buildup of indoor pollutants. The paper "A Survey of Nitrogen Dioxide Levels Inside Mobile Homes" (Journal of the Air Pollution Control Association \([1988]: 647-651\) ) discussed various aspects of NO, concentration in these structures. a. In one sample of mobile homes in the Los Angeles area, the mean \(\mathrm{NO}_{2}\) concentration in kitchens during the summer was \(36.92 \mathrm{ppb}\), and the standard deviation was 11.34. Making no assumptions about the shape of the \(\mathrm{NO}_{2}\) distribution, what can be said about the percentage of observations between \(14.24\) and \(59.60 ?\) b. Inside what interval is it guaranteed that at least \(89 \%\) of the concentration observations will lie? c. In a sample of non-Los Angeles mobile homes, the average kitchen \(\mathrm{NO}_{2}\) concentration during the winter was \(24.76 \mathrm{ppb}\), and the standard deviation was \(17.20 .\) Do these values suggest that the histogram of sample observations did not closely resemble a normal curve? (Hint: What is \(\bar{x}-2 s ?\)

Based on a large national sample of working adults, the U.S. Census Bureau reports the following information on travel time to work for those who do not work at home: lower quartile \(=7 \mathrm{~min}\) median \(=18 \mathrm{~min}\) upper quartile \(=31 \mathrm{~min}\) Also given was the mean travel time, which was reported as \(22.4 \mathrm{~min}\). a. Is the travel time distribution more likely to be approximately symmetric, positively skewed, or negatively skewed? Explain your reasoning based on the given summary quantities. b. Suppose that the minimum travel time was \(1 \mathrm{~min}\) and that the maximum travel time in the sample was \(205 \mathrm{~min}\). Construct a skeletal boxplot for the travel time data. c. Were there any mild or extreme outliers in the data set? How can you tell?

The San Luis Obispo Telegram-Tribune (November 29,1995 ) reported the values of the mean and median salary for major league baseball players for \(1995 .\) The values reported were \(\$ 1,110,766\) and \(\$ 275,000\). a. Which of the two given values do you think is the mean and which is the median? Explain your reasoning. b. The reported mean was computed using the salaries of all major league players in \(1995 .\) For the 1995 salaries, is the reported mean the population mean \(\mu\) or the sample mean \(\bar{x}\) ? Explain.

An instructor has graded 19 exam papers submitted by students in a class of 20 students, and the average so far is 70 . (The maximum possible score is \(100 .\) ) How high would the score on the last paper have to be to raise the class average by 1 point? By 2 points?

Suppose that the distribution of scores on an exam is closely described by a normal curve with mean 100 . The 16 th percentile of this distribution is 80 . a. What is the 84 th percentile? b. What is the approximate value of the standard deviation of exam scores? c. What \(z\) score is associated with an exam score of 90 ? d. What percentile corresponds to an exam score of \(140 ?\) e. Do you think there were many scores below 40 ? Explain.

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