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Bidri is a popular and traditional art form in India. Bidri articles (bowls, vessels, and so on) are made by casting from an alloy containing primarily zinc along with some copper. Consider the following observations on copper content \((\%)\) for a sample of Bidri artifacts in London's Victoria and Albert Museum ("Enigmas of Bidri," Surface Engineering [2005]: 333-339), listed in increasing order: \(\begin{array}{llllllllll}2.0 & 2.4 & 2.5 & 2.6 & 2.6 & 2.7 & 2.7 & 2.8 & 3.0 & 3.1 \\ 3.2 & 3.3 & 3.3 & 3.4 & 3.4 & 3.6 & 3.6 & 3.6 & 3.6 & 3.7\end{array}\) \(\begin{array}{llllll}4.4 & 4.6 & 4.7 & 4.8 & 5.3 & 10.1\end{array}\) a. Construct a dotplot for these data. b. Calculate the mean and median copper content. c. Will an \(8 \%\) trimmed mean be larger or smaller than the mean for this data set? Explain your reasoning.

Short Answer

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a. The dotplot will have dots at each data point along the axis ranging from 2.0 to 10.1. b. The mean and median will be calculated using standard formulas. c. The 8% trimmed mean will be smaller than the mean due to a right-skewed distribution.

Step by step solution

01

Construct a Dotplot

Dotplot is a type of data representation which shows each data point as a dot along an axis. Start by drawing an axis that spans the range of the data, then place dots above each data point along the axis. For example, for the first data point \(2.0\%,\) place a dot above the corresponding point on the axis.
02

Calculate the Mean and Median

The mean (average) of the data can be calculated as: first, sum up all the data points, then divide by the number of data points. The median is the middle value when the data points are arranged in increasing order. If there is an even number of data points, the median is the average of the two middle numbers.
03

Determine if the 8% Trimmed Mean Is Larger or Smaller

An 8% trimmed mean is calculated by removing the highest 8% and lowest 8% of data points before calculating the mean. This method is often used to make the mean more robust to outliers. The trimmed mean will be smaller or larger depending on the distribution of the data. Given that the data has a right-skewed distribution (since the value \(10.1\) is significantly larger than others), removing the highest 8% of data points (which are large values) would decrease the mean, making the trimmed mean smaller than the regular mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dotplot
A dotplot is a simple visual representation of data points that helps to see the distribution and frequency of these points. To create a dotplot, you draw a horizontal axis that represents the range of the data values. Place a dot above the axis for each data point. If a certain value occurs more than once, stack the dots vertically. This a straightforward way to depict the spread and mode of the dataset visually.
  • Find the smallest and largest data points to set your axis range.
  • Above each data point value on the axis, draw a dot.
  • If a value repeats, stack the dots on top of each other.
Dotplots are incredibly useful for identifying clusters, gaps, and outliers within a dataset, which provides insights into the data's variability.
Mean Calculation
The mean, or average, is a measure of central tendency that provides a quick sense of the data set as a whole. To calculate the mean, you need to sum up all the individual data points and then divide this total by the number of data points.
  • Let the data set contain values: \(x_1, x_2, \, ..., \, x_n\).
  • The formula for mean \( \bar{x} \) is: \[\bar{x} = \frac{1}{n} \sum_{i=1}^{n} x_i\]where \( n \) is the number of data points.
The mean gives you an idea of the balance point of the distribution, but it's important to consider that outliers or extreme values can skew the mean, making it not always a perfect representation of the dataset.
Median Calculation
The median is another measurement of central tendency, providing a more robust indicator of the middle of a dataset, especially in the presence of outliers. To find the median:
  • Order the data set from smallest to largest.
  • If the number of observations \( n \) is odd, the median is the middle number in the ordered list.
  • If \( n \) is even, the median is the arithmetic average of the two middle numbers.
The median is particularly useful for datasets with skewed distributions because it is not affected by extremely large or small values.
Trimmed Mean
The trimmed mean is a method used to calculate the average of a dataset while reducing the effect of outliers. By trimming the highest and lowest percentage of data points, you can achieve a more reliable measure of central tendency, especially for skewed data.
  • For an 8% trimmed mean on a dataset with \( n \) observations, remove the lowest and highest 4% of data points (because together they make 8%) from the dataset.
  • Calculate the mean of the remaining data points.
This approach is beneficial in skewed distributions, as it reduces the influence of extreme values, providing a more "typical" value reflective of the dataset. It's worth noting that trimmed means are generally smaller in right-skewed distributions due to the removal of large values.

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Most popular questions from this chapter

A student took two national aptitude tests. The national average and standard deviation were 475 and 100 , respectively, for the first test and 30 and 8 , respectively, for the second test. The student scored 625 on the first test and 45 on the second test. Use \(z\) scores to determine on which exam the student performed better relative to the other test takers.

The paper "Answer Changing on Multiple-Choice Tests" (Journal of Experimental Education \([1980]: 18-21)\) reported that for a group of 162 college students, the average number of responses changed from the correct answer to an incorrect answer on a test containing 80 multiplechoice items was \(1.4\). The corresponding standard deviation was reported to be \(1.5 .\) Based on this mean and standard deviation, what can you tell about the shape of the distribution of the variable number of answers changed from right to wrong? What can you say about the number of students who changed at least six answers from correct to incorrect?

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The Highway Loss Data Institute reported the following repair costs resulting from crash tests conducted in October 2002 . The given data are for a 5 -mph crash into a flat surface for both a sample of 10 moderately priced midsize cars and a sample of 14 inexpensive midsize cars. \(\begin{array}{lrrrrr}\text { Moderately Priced } & 296 & 0 & 1085 & 148 & 1065 \\ \text { Midsize Cars } & 0 & 0 & 341 & 184 & 370 \\ \text { Inexpensive } & 513 & 719 & 364 & 295 & 305 \\ \text { Midsize Cars } & 335 & 353 & 156 & 209 & 288 \\ & 0 & 0 & 397 & 243 & \end{array}\) a. Compute the standard deviation and the interquartile range for the repair cost of the moderately priced midsize cars. b. Compute the standard deviation and the interquartile range for the repair cost of the inexpensive midsize cars. c. Is there more variability in the repair cost for the moderately priced cars or for the inexpensive midsize cars? Justify your choice. d. Compute the mean repair cost for each of the two types of cars. e. Write a few sentences comparing repair cost for moderately priced and inexpensive midsize cars. Be sure to include information about both center and variability.

The paper "The Pedaling Technique of Elite Endurance Cyclists" (International Journal of Sport Biomechanics [1991]: \(29-53\) ) reported the following data on single-leg power at a high workload: \(\begin{array}{lllllllll}244 & 191 & 160 & 187 & 180 & 176 & 174 & 205 & 211 \\\ 183 & 211 & 180 & 194 & 200 & & & & \end{array}\) a. Calculate and interpret the sample mean and median. b. Suppose that the first observation had been 204 , not 244\. How would the mean and median change? c. Calculate a trimmed mean by eliminating the smallest and the largest sample observations. What is the corresponding trimming percentage? d. Suppose that the largest observation had been 204 rather than 244 . How would the trimmed mean in Part (c) change? What if the largest value had been 284 ?

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