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Public Agenda conducted a survey of 1379 parents and 1342 students in grades \(6-12\) regarding the importance of science and mathematics in the school curriculum (Associated Press, February 15,2006 ). It was reported that \(50 \%\) of students thought that understanding science and having strong math skills are essential for them to succeed in life after school, whereas \(62 \%\) of the parents thought it was crucial for today's students to learn science and higher-level math. The two samples - parents and students-were selected independently of one another. Is there sufficient evidence to conclude that the proportion of parents who regard science and mathematics as crucial is different than the corresponding proportion for students in grades \(6-12 ?\) Test the relevant hypotheses using a significance level of \(.05 .\)

Short Answer

Expert verified
The answer requires completing a hypothesis test, which includes formulating the null and alternative hypotheses, computing the test statistic (z-score), and comparing it to the critical z-value.

Step by step solution

01

Identify the parameters

First, identify the number of parents and students surveyed and the respective proportions who believe that understanding science and having strong maths skills is crucial for success. In this case, the number of parents is 1379 and the number of students is 1342. The proportion of parents who hold the positive view is 62\%, and for students, it's 50\%.
02

Formulate the null and alternative hypotheses

The null hypothesis (H0) is that the proportion of parents who view science and maths as crucial (P_parent) is equal to the proportion of students who hold the same belief (P_student). So, H0: P_parent = P_student. The alternative hypothesis (Ha) is that the proportions are not equal, so Ha: P_parent ≠ P_student.
03

Calculate the pooled proportion

The pooled proportion is calculated by adding the number of successes (those who view science and maths as crucial) in both groups and dividing by the total number in both groups. The pooled proportion is therefore: \((0.62 * 1379 + 0.5 * 1342) / (1379 + 1342)\).
04

Compute the test statistic

The test statistic for hypothesis testing of two proportions is the z-score, which is calculated using the formula: z = (P_parent - P_student) - 0 / sqrt( P_pooled * (1 - P_pooled) * (1/n_parent + 1/n_student) ). The denominator is the standard error of the difference of two proportions.
05

Determine the critical z-value and make a decision

At a significance level of .05, the critical z-values for a two-sided test are -1.96 and 1.96. If the computed z-score is outside this range, then we reject the null hypothesis. If it is within this range, we fail to reject the null hypothesis.
06

Conclude

Based on whether we rejected or failed to reject the null hypothesis, we will conclude that there is, or is not, sufficient evidence to say that there is a significant difference in the proportion of parents and students who view science and maths as crucial.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Statistical significance helps us understand whether the results we observe in our data, such as survey responses, could have occurred by chance. When we conduct hypothesis testing, we often look for statistical significance to support our conclusions.

In the survey conducted by Public Agenda, we are interested in determining if there is a real difference between the views of parents and students regarding the importance of science and mathematics. To do this, we set a significance level, noted as \(\alpha\), which is the probability of rejecting the null hypothesis when it is true. In this case, \(\alpha = 0.05\), meaning we accept a 5% chance that we might mistakenly find a difference that doesn't exist.

During hypothesis testing, if our test statistic falls into the critical region (furthest ends of the distribution), we say our results are statistically significant at the \(0.05 \) level. This would imply that any observed difference in the proportions is not likely due to random chance. Thus, understanding statistical significance allows us to make informed decisions based on our data.
Proportion Comparison
Proportion comparison is a key technique when analyzing survey data, especially when we want to compare two distinct groups, like parents and students in this case.

Here, we compare the proportions of parents and students who believe that science and math are crucial for future success. Parents have a proportion of \(62\%\), and students have \(50\%\). The aim is to determine whether this difference in viewing the importance of these subjects is statistically meaningful or not.

To facilitate this comparison, we calculate a 'pooled proportion'. This gives us a combined measure of success across both groups and helps in further calculations for testing our hypotheses. The formula for the pooled proportion is:
  • \[ P_{\text{pooled}} = \frac{(0.62 \times 1379) + (0.50 \times 1342)}{1379 + 1342} \]
By using the pooled proportion, we can effectively compare the proportions of the two groups with greater accuracy and draw meaningful conclusions.
Z-Score Calculation
The z-score calculation is at the core of hypothesis testing for proportions and helps quantify the difference between observed proportions in standardized units.

In this exercise, we calculate the z-score to test if the proportion of parents who find science and math essential is different from the student proportion. The z-score measures how many standard deviations the observed proportion difference is from the null hypothesis that these proportions are equal.

The formula for calculating the z-score is:
  • \[ z = \frac{P_{\text{parent}} - P_{\text{student}}}{\sqrt{P_{\text{pooled}} \times (1 - P_{\text{pooled}}) \times \left(\frac{1}{n_{\text{parent}}} + \frac{1}{n_{\text{student}}}\right)}} \]
This computation gives us a z-value, which we compare against critical values \([-1.96, 1.96]\) for a significance level of \(.05\). If the calculated z-score falls outside this range, it signifies a statistically significant difference.

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