/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 The state of Georgia's HOPE scho... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The state of Georgia's HOPE scholarship program guarantees fully paid tuition to Georgia public universities for Georgia high school seniors who have a B average in academic requirements as long as they maintain a B average in college. Of 137 randomly selected students enrolling in the Ivan Allen College at the Georgia Institute of Technology (social science and humanities majors) in 1996 who had a B average going into college, \(53.2 \%\) had a GPA below \(3.0\) at the end of their first year ("Who Loses HOPE? Attrition from Georgia's College Scholarship Program," Southern Economic Journal [1999]: \(379-390\) ). Do these data provide convincing evidence that a majority of students at Ivan Allen College who enroll with a HOPE scholarship lose their scholarship?

Short Answer

Expert verified
The final answer depends on the calculated p-value. If the p-value is less than 0.05, then it can be concluded that there is convincing evidence that indeed a majority of students at Ivan Allen College who enroll with a HOPE scholarship lose it. If the p-value is greater than 0.05, then there is not enough evidence to suggest that a majority of students lose their HOPE scholarship.

Step by step solution

01

State the Null and Alternative Hypothesis

The null hypothesis, denoted \(H_0\), is that the proportion of students losing the scholarship is 0.5 or less. The alternative hypothesis, denoted \(H_a\), is that the proportion of students losing the scholarship is more than 0.5. So, \(H_0: p \leq 0.5\) and \(H_a: p > 0.5\)
02

Perform a one-sample z test for proportions

Since we're dealing with a large sample size (N = 137), we can use a z-test. The test statistic formula is: \[ Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}} \] Where: \(\hat{p}\) is the observed success rate, \(p_0\) is the proportion under the null hypothesis (0.5 in this case), n is the sample size.
03

Calculate the Test Statistic

Substitute the given values into the equation to get \[ Z = \frac{0.532 - 0.5}{\sqrt{\frac{0.5 (1 - 0.5)}{137}}} \] This will generate the value for the Z statistic.
04

Determine the p-value

After calculating the Z-score, refer to a Z-table (or use an online calculator) to find the one-tailed probability according to the calculated Z-score. A smaller p-value (typically ≤ 0.05) indicates strong evidence against the null hypothesis.
05

State the conclusion

If the p-value is smaller than the significance level (α = 0.05), we reject the null hypothesis in favor of the alternate hypothesis. If the p-value is greater, we do not reject the null hypothesis. This leads to a conclusion about whether the data provides convincing evidence that a majority of students who enroll with a HOPE scholarship lose it.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

HOPE Scholarship Program
The HOPE Scholarship Program is an initiative designed to provide financial aid to eligible students attending public colleges and universities in Georgia. To qualify for this scholarship, high school seniors must have maintained a B average and continue to sustain this average through their college education. However, not every student maintains their GPA, and some may lose the scholarship if their grades fall below the requisite threshold.
This leads us to question whether there is a trend among students, particularly at the Ivan Allen College, Georgia Institute of Technology, who received the HOPE scholarship and subsequently lost it due to falling GPAs. To answer this, statistical methods can be applied to make informed decisions based on collected data. Analyzing such data can also help to improve the program by identifying potential areas for support to prevent attrition.
Null and Alternative Hypothesis
In statistical hypothesis testing, we operate with two competing hypotheses: the null hypothesis (H0) and the alternative hypothesis (Ha). The null hypothesis usually suggests no effect or no difference, while the alternative hypothesis proposes a specific effect or difference.
In relation to the HOPE Scholarship Program, the null hypothesis asserts that 50% or fewer students lose their scholarship due to dropping below a B average. In contrast, the alternative hypothesis challenges this claim, suggesting that more than 50% of students might be losing their scholarships. These hypotheses guide our statistical test and subsequent conclusions about the program's effectiveness in retaining successful students.
One-sample z-test for Proportions
When the data observed is a proportion and we want to test whether the observed proportion significantly differs from a theoretical one, a one-sample z-test for proportions becomes the chosen method. This test is appropriate when dealing with large sample sizes, such as the group of Ivan Allen College students, which consists of 137 individuals.
A z-test provides a statistical significance measure in comparing the observed proportion to the expected proportion under the null hypothesis. By calculating the z-score, using the formula given in the solution, we can gauge how far off the observed data is from what was expected if the null hypothesis were true.
p-value Significance
Understanding the p-value is critical in hypothesis testing. It quantifies the probability of obtaining test results at least as extreme as the ones observed, given that the null hypothesis is true. It's a crucial statistic that helps to determine whether we can reject the null hypothesis.
A p-value less than or equal to the significance level (typically set at 0.05 or 5%) implies strong evidence against the null hypothesis, leading to its rejection. On the other hand, a higher p-value indicates insufficient evidence against the null hypothesis, suggesting that we keep it in place. In the context of our HOPE Scholarship analysis, a low p-value would indicate significant evidence that a majority of the students are indeed losing their scholarships, stirring considerations for program improvement.
Sample Size and Proportion
In our analysis, the sample size and the observed proportion of students who lost the HOPE scholarship are crucial. With a sample size of 137 students, the statistical methods used will yield robust and reliable conclusions. The observed proportion is the key figure being tested against an expected value; in this case, the proportion of students hypothesized under the null hypothesis to lose their scholarship (50%).
The larger the sample size, the more precise our estimates become, reducing the margin of error. A well-determined sample size ensures the validity of the z-test results and, subsequently, strengthens the p-value's implication in the decision-making process regarding the HOPE Scholarship Program's impact.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Newly purchased automobile tires of a certain type are supposed to be filled to a pressure of 30 psi. Let \(\mu\) denote the true average pressure. Find the \(P\) -value associated with each of the following given \(z\) statistic values for testing \(H_{0}: \mu=30\) versus \(H_{a}: \mu \neq 30\) when \(\sigma\) is known: a. \(2.10\) d. \(1.44\) b. \(-1.75\) e. \(-5.00\) c. \(0.58\)

For which of the following \(P\) -values will the null hypothesis be rejected when performing a level .05 test: a. 001 d. . 047 b. 021 e. \(.148\) c. 078

Optical fibers are used in telecommunications to transmit light. Current technology allows production of fibers that transmit light about \(50 \mathrm{~km}\) (Research at Rensselaer, 1984 ). Researchers are trying to develop a new type of glass fiber that will increase this distance. In evaluating a new fiber, it is of interest to test \(H_{0}: \mu=50\) versus \(H_{a}: \mu>50\), with \(\mu\) denoting the true average transmission distance for the new optical fiber. a. Assuming \(\sigma=10\) and \(n=10\), use Appendix Table 5 to find \(\beta\), the probability of a Type II error, for each of the given alternative values of \(\mu\) when a level \(.05\) test is employed: \(\begin{array}{llll}\text { i. } 52 & \text { ii. } 55 & \text { iii. } 60 & \text { iv. } 70\end{array}\) b. What happens to \(\beta\) in each of the cases in Part (a) if \(\sigma\) is actually larger than \(10 ?\) Explain your reasoning.

Are young women delaying marriage and marrying at a later age? This question was addressed in a report issued by the Census Bureau (Associated Press, June 8 , 1991). The report stated that in 1970 (based on census results) the mean age of brides marrying for the first time was \(20.8\) years. In 1990 (based on a sample, because census results were not yet available), the mean was \(23.9\). Suppose that the 1990 sample mean had been based on a random sample of size 100 and that the sample standard deviation was \(6.4\). Is there sufficient evidence to support the claim that in 1990 women were marrying later in life than in 1970 ? Test the relevant hypotheses using \(\alpha=.01\). (Note: It is probably not reasonable to think that the distribution of age at first marriage is normal in shape.)

Typically, only very brave students are willing to speak out in a college classroom. Student participation may be especially difficult if the individual is from a different culture or country. The article "An Assessment of Class Participation by International Graduate Students" (Journal of College Student Development [1995]: 132- 140) considered a numerical "speaking-up" scale, with possible values from 3 to 15 (a low value means that a student rarely speaks). For a random sample of 64 males from Asian countries where English is not the official language, the sample mean and sample standard deviation were \(8.75\) and \(2.57\), respectively. Suppose that the mean for the population of all males having English as their native language is \(10.0\) (suggested by data in the article). Does it appear that the population mean for males from non-English-speaking Asian countries is smaller than \(10.0 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.