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To determine whether the pipe welds in a nuclear power plant meet specifications, a random sample of welds is selected and tests are conducted on each weld in the sample. Weld strength is measured as the force required to break the weld. Suppose that the specifications state that the mean strength of welds should exceed 100 \(\mathrm{lb} / \mathrm{in} .^{2} .\) The inspection team decides to test \(H_{0}: \mu=100\) versus \(H_{a}: \mu>100 .\) Explain why this alternative hypothesis was chosen rather than \(\mu<100\).

Short Answer

Expert verified
The alternative hypothesis \(\mu>100\) was chosen as it aligns with the aim of the inspection team to confirm that weld strengths meet or exceed the specified standard. Also, choosing a hypothesis of \(\mu<100\) would indicate the testing of a potentially unsafe scenario which is not the team's objective.

Step by step solution

01

Identification of Null and Alternative Hypotheses

In this exercise, the null hypothesis, denoted by \(H_0\), is that the mean weld strength \(\mu\) equals 100 lbs/in^2. The alternative hypothesis, denoted by \(H_a\), is that the mean weld strength \(\mu\) is greater than 100 lbs/in^2. The alternative hypothesis could, theoretically, have been set as \(\mu<100\).
02

The Implications of the Alternative Hypothesis

If the alternative hypothesis was \(\mu<100\), this would suggest that the inspection team is looking to verify a weld strength weaker than specified. This does not align with the team's goal of confirming that the weld strength meets or exceeds the specified standard of 100 lbs/in^2. Therefore, the hypothesis of \(\mu>100\) is logically chosen as the alternative hypothesis, as it checks if the weld strength surpasses the required criteria.
03

Consideration of Safety Implications and Standards

From a safety perspective, it is crucial for the weld strength to meet or exceed the specified standard - anything less could be potentially dangerous. Hence, the team should be concerned about proving a situation where the strength is greater than the standard, rather than one where it is lesser.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis, often represented as \(H_0\), serves as the default or initial claim that there is no effect or no difference. It's a statement that indicates there is no change or improvement, and in many cases, it represents the idea that a parameter, such as the mean, equals a specific value. In our exercise dealing with the weld strength of nuclear power plant pipe welds, the null hypothesis is \(H_0: \mu = 100\ lb/in^2\). This indicates that the inspection team assumes, until proven otherwise, that the mean weld strength is exactly 100 lbs/in², as per specifications.

Identifying the null hypothesis is crucial because it sets the stage for statistical testing. At this point, researchers are essentially working to disprove or reject this hypothesis, showing that the observed data presents enough evidence to support a particular alternative claim. The null hypothesis acts as a starting point - the solid ground where the inspection team begins their investigation.
Alternative Hypothesis
The alternative hypothesis is what researchers aim to support when conducting their test. It is represented by \(H_a\) and suggests that there is an effect or a difference contrary to what is stated in the null hypothesis. In the context of the weld strength test, the alternative hypothesis is stated as \(H_a: \mu > 100\), which implies that the mean weld strength exceeds 100 lbs/in².

This choice of the alternative hypothesis reflects the objective of the inspection team. They intend to demonstrate that the weld strength meets or surpasses the safety specifications. Given that the plant's operations depend on meeting safety standards, the team needs to verify that welds exceed the minimum strength threshold, ensuring more than just adequacy but a margin above the bare minimum specification.

Choosing ">" rather than a different alternative like "<" serves to highlight the context of the problem, which focuses on safety and performance. In this setting, demonstrating an excess in strength aligns better with operational safety goals, making it a reasonable and preferable hypothesis.
Statistical Significance
Statistical significance is a key consideration in hypothesis testing that helps determine whether the observed results can be attributed to chance or if they provide sufficient evidence to reject the null hypothesis. When test results are statistically significant, it implies that the findings are unlikely to have occurred due to random variation alone.

In the weld strength problem, determining statistical significance would involve analyzing the data collected from testing the sample welds. The team would calculate a test statistic and p-value, which measures the probability of observing such data if the null hypothesis is true. If this p-value is less than a predetermined significance level (often set at 0.05), the results can be considered statistically significant.

This statistical significance indicates enough evidence to reject \(H_0: \mu = 100\ lb/in^2\) in favor of the alternative \(H_a: \mu > 100\). Reaching this conclusion suggests that the mean weld strength does indeed surpass the specified threshold, underscoring a level of confidence that the welds meet or exceed the safety standards required by the nuclear power plant.

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