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A null hypothesis states that the population proportion \(p\) of headache sufferers who have better pain relief with aspirin than with another pain reliever equals \(0.50 .\) For a crossover study with 10 subjects, all 10 have better relief with aspirin. If the null hypothesis were true, by the binomial distribution the probability of this sample result (which is the most extreme) equals \((0.50)^{10}=0.001 .\) In fact, this is the small-sample P-value for testing \(\mathrm{H}_{0}: p=0.50\) against \(\mathrm{H}_{a}: p>0.50 .\) Does this P-value give (a) strong evidence in favor of \(\mathrm{H}_{0}\) or (b) strong evidence against \(\mathrm{H}_{0}\) ? Explain why.

Short Answer

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(b) The P-value gives strong evidence against \(H_0\), suggesting more than 50% have better relief with aspirin.

Step by step solution

01

Understand the Null Hypothesis

The null hypothesis (\(H_0\)) claims that the population proportion of headache sufferers getting better relief with aspirin than with another pain reliever is 0.50. This assumes no preference between aspirin and the alternative in terms of relief.
02

Recognize the Alternative Hypothesis

The alternative hypothesis (\(H_a\)) suggests that more than 50% of headache sufferers experience better relief with aspirin than with another pain reliever. Mathematically, this is expressed as \(H_a: p > 0.50\).
03

Test the Result with the Binomial Distribution

In the study, all 10 subjects preferred aspirin for better relief. Assuming the null hypothesis is true, the probability of this specific outcome (all 10 having better relief from aspirin) is given by \((0.50)^{10} = 0.001\). This value represents the likelihood of occurring if the null hypothesis were true.
04

Define the P-value

The P-value measures the probability of observing a result as extreme or more extreme than the outcome obtained under the assumption that the null hypothesis is true. Here, the small-sample P-value is 0.001.
05

Interpret the P-value

A P-value of 0.001 is very small, suggesting that such an extreme result is highly unlikely if the null hypothesis were true. A common threshold for considering evidence strong against the null hypothesis is a P-value less than 0.05.
06

Make a Conclusion Based on the P-value

Since the P-value (0.001) is much less than 0.05, this provides strong evidence against the null hypothesis \(H_0\). We conclude there is significant evidence to suggest more than 50% prefer aspirin for relief.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis is a statement about a population parameter that we assume to be true until evidence suggests otherwise. It serves as a starting point for any hypothesis test. Simply put, the null hypothesis, denoted by \(H_0\), represents a default position that indicates no effect or no difference. In the context of our exercise, \(H_0: p = 0.50\) suggests that there is no significant difference in the effectiveness of aspirin compared to another pain reliever among headache sufferers. It implies that only half, or 50%, would find aspirin to be more effective, just like the alternative pain reliever.

The null hypothesis is crucial because it offers a baseline or reference point to test against, using sample data. If the data we observe or gather is very unlikely under this hypothesis, it indicates that the assumption might not hold true in our population. This allows us to consider whether the alternative hypothesis might be more believable.
Alternative Hypothesis
The alternative hypothesis challenges the presumption set by the null hypothesis. It is what we aim to support through our research and data. In statistical terms, the alternative hypothesis, represented as \(H_a\), proposes that there is an effect or a difference. For our exercise, \(H_a: p > 0.50\) posits that more than 50% of headache sufferers find aspirin to be more effective than the alternative pain reliever.

Here are some key points regarding the alternative hypothesis:
  • It is the claim that will be accepted if the null is rejected.
  • In our case, it's a directional hypothesis since we are looking for a difference in a specific direction (greater than 50% effectiveness).
  • The results of our test are interpreted in terms of supporting the alternative hypothesis, not proving it, because statistical tests do not offer absolute proofs.
P-value
A P-value is a critical concept in hypothesis testing that helps us decide whether to reject the null hypothesis. It measures the probability of obtaining a sample result, or one more extreme, assuming the null hypothesis is true. In the given exercise, the P-value is calculated as 0.001, meaning there is a very small chance of observing such extreme results (all 10 subjects preferring aspirin) if \(H_0\) were true.

Understanding the significance of the P-value:
  • A small P-value (typically \(<0.05\)) indicates strong evidence against the null hypothesis, suggesting that the observed data is highly unusual under the null.
  • Conversely, a large P-value suggests that the observed data is not unusual if the null hypothesis is true, and there is not enough evidence to favor the alternative hypothesis.
  • In this exercise, a P-value of 0.001 strongly suggests rejecting the null hypothesis in favor of the assertion that more than 50% find aspirin more effective.
Binomial Distribution
The binomial distribution is a probability distribution that applies to experiments with two possible outcomes: success or failure. It is particularly useful when we want to calculate the probabilities of different outcomes in a fixed number of trials, each of which has the same probability of success.

In the exercise, we have 10 trials (each subject preferring aspirin), with each being a success if aspirin is preferred over the alternative. Assuming the null hypothesis is true and \(p = 0.50\), the probability of all subjects preferring aspirin (an extreme outcome) is calculated using the binomial probability formula. In this case, \[(0.50)^{10} = 0.001\] This means there is only a 0.1% chance of this outcome occurring if there's no preference in effectiveness between aspirin and another pain reliever.

The binomial distribution helps us quantify and test how likely different outcomes are, assisting in forming conclusions about our hypotheses based on our observed data.

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Most popular questions from this chapter

A recent study \(^{4}\) considered whether dogs could be trained to detect whether a person has lung cancer or breast cancer by smelling the subject's breath. The researchers trained five ordinary household dogs to distinguish, by scent alone, exhaled breath samples of 55 lung and 31 breast cancer patients from those of 83 healthy controls. A dog gave a correct indication of a cancer sample by sitting in front of that sample when it was randomly placed among four control samples. Once trained, the dogs' ability to distinguish cancer patients from controls was tested using breath samples from subjects not previously encountered by the dogs. (The researchers blinded both dog handlers and experimental observers to the identity of breath samples.) Let \(p\) denote the probability a dog correctly detects a cancer sample placed among five samples when the other four are controls. a. Set up the null hypothesis that the dog's predictions correspond to random guessing. b. Set up the alternative hypothesis to test whether the probability of a correct selection differs from random guessing. c. Set up the alternative hypothesis to test whether the probability of a correct selection is greater than with random guessing. d. In one test with 83 Stage I lung cancer samples, the dogs correctly identified the cancer sample 81 times. The test statistic for the alternative hypothesis in part \(\mathrm{c}\) was \(z=17.7 .\) Report the \(\mathrm{P}\) -value to three decimal places and interpret. (The success of dogs in this study made researchers wonder whether dogs can detect cancer at an earlier stage than conventional methods such as MRI scans.

In the webcomic on the link http://xkcd.com/882/, a girl claims that jelly beans cause acne. Scientists investigate and find no link between the two \((p>0.05)\). They are asked to check if jelly beans of a particular color cause acne. They test 20 different colors each at a significance level of \(5 \%\) and find a link between green jelly beans and acne. This leads to a newspaper headline, "Green Jellybeans Cause Acne" where the \(5 \%\) chance of the link is mentioned as \(95 \%\) confidence. When the scientists repeat the same experiment, they are unable to find any link between acne and color of jelly beans. They conclude that the earlier result might be coincidental. Using this example, explain why you need to have some skepticism when research suggests that some therapy or drug has an impact in treating a disease.

A significance test about a mean is conducted using a significance level of \(0.05 .\) The test statistic equals \(10.52 .\) The \(\mathrm{P}\) -value is \(0.003 .\) a. If \(\mathrm{H}_{0}\) was true, for what probability of a Type I error was the test designed? b. If the P-value was 0.3 and the test resulted in a decision error, what type of error was it?

Burden of proof For a new pesticide, should the Environmental Protection Agency (EPA) bear the burden of proof to show that it is harmful to the environment, or should the producer of the pesticide have to show that it is not harmful to the environment? The pesticide is considered harmful if its toxicity level exceeds a certain threshold and not harmful if its toxicity level is below the threshold. Consider the statements, "The mean toxicity level equals the threshold," "The mean toxicity level exceeds the threshold," and "The mean toxicity level is below the threshold." a. Which of these statements should be the null and which the alternative hypothesis when the burden of proof is on the EPA to show that the new pesticide is harmful? b. Which of these statements should be the null and which the alternative hypothesis when the burden of proof is on the producer to show that the new pesticide is not harmful?

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