/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 A poll was conducted between 18 ... [FREE SOLUTION] | 91Ó°ÊÓ

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A poll was conducted between 18 and 20 April, \(2016,\) by the Egyptian Center for Public Opinion Research on the performance of President Abdel Fattah el- Sisi at the end of his 22 nd month in office. Out of all the respondents, \(51 \%\) strongly approved his performance. The poll consisted of 709 responses obtained by randomly sampling citizens aged 18 years and above, covering all governorates. Test that the population proportion of those who approve highly of the president's performance was 0.50 against the alternative that it differed from 0.50 . Carry out the five steps of a significance test, at the significance level of 0.05 , reporting and interpreting the P-value in context.

Short Answer

Expert verified
The test shows no significant evidence to state that approval proportion differs from 0.50.

Step by step solution

01

State the Hypotheses

We begin by defining the null hypothesis \((H_0)\) and the alternative hypothesis \((H_a)\):- Null hypothesis \(H_0\): The population proportion \(p\) of those who approve highly of the president's performance is 0.50. \ \(H_0: p = 0.50\)- Alternative hypothesis \(H_a\): The population proportion \(p\) differs from 0.50. \ \(H_a: p eq 0.50\)
02

Choose the Significance Level

The given significance level for this test is \(\alpha = 0.05\). This level indicates the probability of rejecting the null hypothesis when it is actually true.
03

Calculate the Test Statistic

The test statistic for a proportion test is calculated using:\[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}\]where:- \(\hat{p} = 0.51\) is the sample proportion,- \(p_0 = 0.50\) is the hypothesized population proportion,- \(n = 709\) is the sample size.Substituting in the values:\[ z = \frac{0.51 - 0.50}{\sqrt{\frac{0.50(1 - 0.50)}{709}}} = \frac{0.01}{0.0188} \approx 0.53\]
04

Determine the P-value

Using the standard normal distribution and the test statistic \(z = 0.53\), we find the P-value. Since this is a two-tailed test (\(H_a: p eq 0.50\)), we need to consider both tails of the distribution. Looking up \(z = 0.53\) on a standard normal distribution table, or using a calculator, we get that \ P(Z > 0.53) \approx 0.2981 The P-value for the two-tailed test is \ P = 2 \times 0.2981 = 0.5962.
05

Make a Decision and Interpret Results

Since the P-value \(0.5962\) is greater than the significance level \(\alpha = 0.05\), we do not reject the null hypothesis. This means there is not enough evidence to conclude that the proportion who approve highly differs from 0.50.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion is a fundamental concept in statistics, particularly when conducting hypothesis tests. It represents the fraction of the total population that exhibits a certain characteristic or trait. In our example, we are interested in the population proportion of people who strongly approve of the president’s performance.
This is often denoted by the symbol \(p\). In this case, the hypothesized population proportion is \(p_0 = 0.50\), meaning we initially assume that 50% of the population strongly approves of the president’s performance.
Understanding this concept is crucial because hypothesis testing often involves making claims or assumptions about the population proportion and then using sample data to evaluate the validity of those claims.
P-value
The P-value is a key concept in hypothesis testing that helps determine the significance of your results. It measures the probability of obtaining test results at least as extreme as the observed results, assuming that the null hypothesis is true.
In simpler terms, the P-value helps you decide if you should support or refute your initial assumption (the null hypothesis). A smaller P-value suggests that the observed data were unlikely under the assumption of the null hypothesis, indicating stronger evidence against it.
In our specific example, the test statistic calculated was \(z = 0.53\), and the resulting P-value was approximately 0.5962. Since this P-value is larger than the typical significance level of 0.05, it suggests that the observed proportion is not significantly different from the hypothesized 0.50, meaning we lack strong evidence to reject the null hypothesis.
Significance Level
The significance level, denoted by \(\alpha\), is a threshold used in hypothesis testing to determine whether an observed result is statistically significant. It is the probability of rejecting the null hypothesis when it is actually true.
Commonly used significance levels are 0.05, 0.01, and 0.10, with 0.05 being the most popular choice, representing a 5% risk of concluding that a difference exists when there is none.
In our example, the significance level is set at \(\alpha = 0.05\). This means we are willing to accept a 5% probability of incorrectly rejecting the null hypothesis. By comparing our calculated P-value (0.5962) with this significance level, we conclude there is not enough evidence to declare a significant difference in the population proportion.
Alternative Hypothesis
The alternative hypothesis \((H_a)\) is the statement that we aim to find evidence for, contrary to the null hypothesis. It offers a different assumption about the population parameter in question.
In hypothesis testing, the null hypothesis (\(H_0\)) represents the status quo or the default assumption. In our case study, the null hypothesis states that the population proportion \(p\) is 0.50. On the other hand, the alternative hypothesis (\(H_a\)) suggests that the population proportion \(p\) is not equal to 0.50.
The alternative hypothesis is critical because it guides the direction and focus of the analysis. In two-tailed tests like ours, \(H_a: p eq 0.50\), we consider both possibilities where the proportion could either be less than or greater than 0.50, requiring us to examine both ends of the distribution. Understanding and correctly setting up the alternative hypothesis is an essential step in robust hypothesis testing.

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Most popular questions from this chapter

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