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According to the Alzheimer's Association, \(^{2}\) as of 2014 Alzheimer's disease affects 1 in 9 Americans over the age of \(65 .\) A study is planned of health problems the elderly face. For a random sample of Americans over the age of \(65,\) report the shape, mean, and standard deviation of the sampling distribution of the proportion who suffer from Alzheimer's disease, if the sample size is (a) 200 and (b) 800 .

Short Answer

Expert verified
The sampling distribution is approximately normal with mean 0.111; std dev is 0.0220 for n=200 and 0.0110 for n=800.

Step by step solution

01

Calculate the Population Proportion

According to the information given, 1 in 9 Americans over the age of 65 suffer from Alzheimer's disease. This means the population proportion \( p \) is \( \frac{1}{9} \approx 0.111 \).
02

Determine Sample Proportions

For a sample size, the sample proportion \( \hat{p} \) is calculated from the population proportion. The approximate value is 0.111.
03

Calculate Standard Deviation for (a) n = 200

The standard deviation for the sample proportion when the sample size \( n \) is 200 is calculated using the formula: \( \sqrt{\frac{p(1-p)}{n}} \). Substituting the values, \( \sqrt{\frac{0.111(1-0.111)}{200}} \approx 0.0220 \).
04

Calculate Standard Deviation for (b) n = 800

Similarly, for a sample size \( n \) of 800, the standard deviation is calculated using the same formula: \( \sqrt{\frac{0.111(1-0.111)}{800}} \approx 0.0110 \).
05

Describe Shape of Sampling Distribution

The sampling distribution of the proportion is approximately normal if \( np \geq 10 \) and \( n(1-p) \geq 10 \). For \( n = 200 \), \( 200 \times 0.111 = 22.2 \) and \( 200 \times (1 - 0.111) = 177.8 \), both more than 10. For \( n = 800 \), \( 800 \times 0.111 = 88.8 \) and \( 800 \times (1 - 0.111) = 711.2 \), which also meet the criteria. Thus, in both cases, the sampling distribution is approximately normal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion is a fundamental concept in statistics, especially when dealing with sampling distributions. It represents the fraction of a population that holds a particular characteristic, in this case, the proportion of Americans over 65 suffering from Alzheimer's disease. Imagine we have a huge group, say all Americans over 65. In this group, according to the information provided, approximately 1 in every 9 people has Alzheimer's. So, the population proportion, denoted as \( p \), is calculated as \( \frac{1}{9} \), which approximates to 0.111.
This proportion is crucial because it serves as a starting point for calculating sample statistics. By having this proportion, we can further determine other characteristics like standard deviation and analyze sample data to draw conclusions about larger populations.
Standard Deviation
Standard deviation is a measure of how much variation or dispersion there is from the average (mean). In the context of a sampling distribution of a proportion, it tells us how much variability we might expect from sample to sample, given a particular sample size \( n \).
For example, when we look at a sample size of 200, we calculate the standard deviation of the sample proportion using the formula \( \sqrt{\frac{p(1-p)}{n}} \). This results in \( \sqrt{\frac{0.111(1-0.111)}{200}} \approx 0.0220 \). Similarly, for a larger sample size of 800, the standard deviation decreases to \( \approx 0.0110 \).
Notice how the standard deviation gets smaller as the sample size increases; this means larger samples tend to reduce variability, making our estimates more reliable.
Normal Distribution
In statistics, the normal distribution is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. It's often depicted as a bell-shaped curve.
The shape of the sampling distribution of the proportion is approximately normal if it meets two conditions: \( np \geq 10 \) and \( n(1-p) \geq 10 \). These conditions are essential because they ensure that we have a sufficiently large sample to approach the characteristics of a normal distribution. For instance, with \( n = 200 \), both \( 22.2 \) and \( 177.8 \) are greater than 10. Similarly, with \( n = 800 \), both \( 88.8 \) and \( 711.2 \) exceed 10.
This normality allows us to use various statistical tools and tests to analyze data effectively, with the understanding that many natural phenomena fit this type of distribution.
Sample Size
Sample size, denoted as \( n \), is a vital statistic as it impacts the accuracy and precision of our sample estimate. Essentially, sample size is about how many observations we include in our sample from a larger population.
Larger sample sizes tend to give more accurate results, as they better represent the underlying population. For instance, a sample size of 200 provides an adequate assessment but with more variability (higher standard deviation) than a size 800 sample. The larger sample size of 800 reduces the standard deviation, providing a more stable and precise estimate.
Choosing the right sample size is crucial in designing studies to ensure that the results are credible and capable of revealing true patterns and characteristics within the population.

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Most popular questions from this chapter

Vincenzo Baranello was diagnosed with high blood pressure. He was able to keep his blood pressure in control for several months by taking blood pressure medicine (amlodipine besylate). Baranello's blood pressure is monitored by taking three readings a day, in early morning, at midday, and in the evening. a. During this period, the probability distribution of his systolic blood pressure reading had a mean of 130 and a standard deviation of 6 . If the successive observations behave like a random sample from this distribution, find the mean and standard deviation of the sampling distribution of the sample mean for the three observations each day. b. Suppose that the probability distribution of his blood pressure reading is normal. What is the shape of the sampling distribution? Why? c. Refer to part \(\mathrm{b}\). Find the probability that the sample mean exceeds \(140,\) which is considered problematically high.

In Aunt Erma's Restaurant, the daily sales follow a probability distribution that has a mean of \(\mu=\$ 900\) and a standard deviation of \(\sigma=\$ 300\). This past week the daily sales for the seven days had a mean of \(\$ 980\) and a standard deviation of \(\$ 276\). Consider these seven days as a random sample from all days. a. Identify the mean and standard deviation of the population distribution. b. Identify the mean and standard deviation of the data distribution. What does the standard deviation describe? c. Identify the mean and the standard deviation of the sampling distribution of the sample mean for samples of seven daily sales. What does this standard deviation describe?

For a single toss of a balanced coin, let \(x=1\) for a head and \(x=0\) for a tail. a. Construct the probability distribution for \(x\) and calculate its mean. (You can think of this as the population distribution corresponding to a very long sequence of tosses.) b. The coin is flipped 10 times, yielding 6 heads and 4 tails. Construct the data distribution. c. Each student in the class should flip a coin 10 times and find the proportion of heads. Collect the sample proportion of heads from each student. Summarize the simulated sampling distribution by constructing a plot of all the proportions obtained by the students. Describe the shape and variability of the sampling distribution compared to the distributions in parts a and b. d. If you performed the experiment in part c a huge number of times, what would you expect to get for the (i) mean and (ii) standard deviation of the sample proportions?

Let \(p=0.25\) be the proportion of iPhone owners who have a given app. For a particular iPhone owner, let \(x=1\) if they have the app and \(x=0\) otherwise. For a random sample of 50 owners: a. State the population distribution (that is, the probability distribution of \(X\) for each observation). b. State the data distribution if 30 of the 50 owners sampled have the app. (That is, give the sample proportions of observed 0 s and 1 s in the sample.) c. Find the mean of the sampling distribution of the sample proportion who have the app among the 50 people. d. Find the standard deviation of the sampling distribution of the sample proportion who have the app among the 50 people. e. Explain what the standard deviation in part d describes.

The central limit theorem implies a. All variables have approximately bell-shaped data distributions if a random sample contains at least about 30 observations. b. Population distributions are normal whenever the population size is large. c. For sufficiently large random samples, the sampling distribution of \(\bar{x}\) is approximately normal, regardless of the shape of the population distribution. d. The sampling distribution of the sample mean looks more like the population distribution as the sample size increases.

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