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Binomial needs fixed \(n\) For the binomial distribution, the number of trials \(n\) is a fixed number. Let \(X\) denote the number of girls in a randomly selected family in Canada that has three children. Let \(Y\) denote the number of girls in a randomly selected family in Canada (that is, the number of children could be any number). A binomial distribution approximates well the probability distribution for one of \(X\) and \(Y\), but not for the other. a. Explain why. b. Identify the case for which the binomial applies and identify \(n\) and \(p\).

Short Answer

Expert verified
The binomial distribution applies to X with n = 3 and p = 0.5. Y does not satisfy the binomial conditions.

Step by step solution

01

Understand the Binomial Distribution

The binomial distribution describes the number of successes (here, the number of girls) in a fixed number of independent trials, each with the same probability of success. This means we need a fixed number of children (trials).
02

Analyze Situation X

For X, we have a fixed number of trials, as there are exactly 3 children. Here, the number of trials n is 3. Each child independently has a probability of being a girl, denoted by p.
03

Analyze Situation Y

For Y, the number of children is not fixed; it can be any number. This setup does not satisfy the fixed number of trials condition needed for a binomial distribution, as n is not fixed.
04

Apply Binomial Distribution to X

Since X has a fixed number of trials (n = 3), it follows the binomial distribution. We need to choose a probability p for a child being a girl. Assuming p = 0.5 (equal chance of being a boy or girl), the binomial distribution is applicable to X.
05

Conclude for Y

Y does not follow a binomial distribution since there is no fixed number n of trials (children). Each family could have a different number of children.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
A probability distribution is a mathematical function that provides the probabilities of occurrence of different possible outcomes in an experiment. It is a fundamental concept in statistics that describes how probabilities are distributed over the values of a random variable. In the case of the binomial distribution, it specifically gives the probability of achieving a certain number of successes in a fixed number of trials.
For example, if you want to know the probability of having a specific number of girls in a family of three children, the binomial distribution can help. It will tell you the probabilities for 0, 1, 2, or 3 girls, assuming each child is independently a girl with a given probability.
Fixed Trials
For a binomial distribution to be applicable, one essential requirement is the concept of fixed trials. "Fixed Trials" means that the number of trials, denoted by \(n\), is set in advance and does not change. This is crucial because without a fixed number of trials, the probability calculation cannot be consistently applied.
  • In the exercise, the random variable \(X\), where there are exactly three children, satisfies this condition as the number of children is fixed at three.
  • Conversely, the random variable \(Y\), where the number of children can vary, does not satisfy the fixed trials requirement, making the binomial distribution inapplicable.
Fixed trials ensure that the binomial model's assumptions hold, allowing us to calculate the probabilities accurately using the definition of the binomial probability formula.
Independent Trials
"Independent Trials" is another key concept in understanding binomial distribution. This concept means that the outcome of one trial does not affect the outcome of another. This impartiality is crucial because it allows systematic probability calculations.
For binomial distributions, every trial must be independent. In our exercise, each child being a girl or not is independent of the others; the gender of one child does not influence that of the other children in the family.
  • When trials are independent, it permits clear probability calculations. This quality keeps the computations straightforward because the result of one trial doesn't alter or bias the next.
  • This concept helps simplify our model to make it workable and applicable for practical problem solving, like figuring out the likelihood of a specific gender makeup in a small family.
By maintaining independence between trials, the binomial distribution remains a practical tool for predicting outcomes when conditions are met.
Probability of Success
In binomial distribution, the "Probability of Success" is a term used to denote the chance that a single trial results in the desired outcome. Here, success relates to our specific interest, like determining the likelihood of each child being a girl.
  • The symbol \(p\) represents this probability in binomial probability calculations. Using the exercise example, assume each child independently has a 50% chance of being a girl, so \(p = 0.5\).
  • This probability of success \(p\) is utilized in the binomial formula to compute the overall likelihood of a set of successes across all trials.
The concept of probability of success allows us to meaningfully apply the binomial distribution, transforming intuitive assumptions of success into calculable predictions. By knowing \(p\), you can confidently determine the probability of realizing certain outcomes across multiple trials.

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Most popular questions from this chapter

San Francisco Giants hitting The table shows the probability distribution of the number of bases for a randomly selected time at bat for a San Francisco Giants player in 2010 (excluding times when the player got on base because of a walk or being hit by a pitch). In \(74.29 \%\) of the at-bats the player was out, \(17.04 \%\) of the time the player got a single (one base), \(5.17 \%\) of the time the player got a double (two bases), \(0.55 \%\) of the time the player got a triple, and \(2.95 \%\) of the time the player got a home run. a. Verify that the probabilities give a legitimate probability distribution. b. Find the mean of this probability distribution. c. Interpret the mean, explaining why it does not have to be a whole number, even though each possible value for the number of bases is a whole number. $$ \begin{array}{cc} \hline {\text { San Francisco Giants Hitting }} \\ \hline \text { Number of Bases } & \text { Probability } \\ \hline 0 & 0.7429 \\ 1 & 0.1704 \\ 2 & 0.0517 \\ 3 & 0.0055 \\ 4 & 0.0295 \\ \hline \end{array} $$

Checking guidelines In a village having more than 100 adults, eight are randomly selected in order to form a committee of residents. \(40 \%\) of adults in the village are connected with agriculture. a. Verify that the guidelines have been satisfied about the relative sizes of the population and the sample, thus allowing the use of a binomial probability distribution for the number of selected adults connected with agriculture. b. Check whether the guideline was satisfied for this binomial distribution to be reasonably approximated by a normal distribution.

Suppose your favorite coffee machine offers 12 ounce cups of coffee. The actual amount of coffee put in the cup by the machine varies according to a normal distribution, with mean equal to 13 ounces and standard deviation equal to 0.6 ounces. For each question below, sketch a graph, mark the mean, shade the area to which the answer refers and compute the percentage. a. What percentage of cups will be filled with less than 12 ounces? b. What percentage of cups will be filled with more than 12.5 ounces? c. What percentage of cups will have in between 12 and 13 ounces of coffee?

Ideal number of children Let \(X\) denote the response of a randomly selected person to the question, "What is the ideal number of children for a family to have?" The probability distribution of \(X\) in the United States is approximately as shown in the table, according to the gender of the person asked the question. $$ \begin{array}{lcc} \hline \begin{array}{l} \text { Probability Distribution of } \boldsymbol{X}=\text { Ideal Number } \\\ \text { of Children } \end{array} \\ \hline \boldsymbol{x} & \mathbf{P}(\boldsymbol{x}) \text { Females } & \mathbf{P}(\boldsymbol{x}) \text { Males } \\ \hline 0 & 0.01 & 0.02 \\ 1 & 0.03 & 0.03 \\ 2 & 0.55 & 0.60 \\ 3 & 0.31 & 0.28 \\ 4 & 0.11 & 0.08 \\ \hline \end{array} $$ a. Show that the means are similar, 2.50 for females and 2.39 for males. b. The standard deviation for the females is 0.770 and 0.758 for the males. Explain why a practical implication of the values for the standard deviations is that males hold slightly more consistent views than females about the ideal family size.

For a normal distribution, a. Find the \(z\) -score for which a total probability of 0.04 falls more than \(z\) standard deviations (in either direction) from the mean, that is, below \(\mu-z \sigma\) or above \(\mu+z \sigma\) b. For this \(z\) -score, explain why the probability of values more than \(z\) standard deviations below the mean is 0.02 . c. Explain why \(\mu+z \sigma\) is the 2 nd percentile.

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