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The Mental Development Index (MDI) of the Bayley Scales of Infant Development is a standardized measure used in observing infants over time. It is approximately normal with a mean of 100 and a standard deviation of 16 a. What proportion of children has an MDI of (i) at least \(120 ?\) (ii) at least \(80 ?\) b. Find the MDI score that is the 99 th percentile. c. Find the MDI score such that only \(1 \%\) of the population has MDI below it.

Short Answer

Expert verified
10.56% have MDI ≥ 120; 89.44% have MDI ≥ 80; 99th percentile: 137.28; 1st percentile: 62.72.

Step by step solution

01

- Identify Given Information

The problem states that the MDI follows a normal distribution with a mean \( \mu = 100 \) and a standard deviation \( \sigma = 16 \). The relevant tasks involve calculating proportions and percentile scores for this distribution.
02

- Calculate Proportion for MDI At Least 120

For an MDI of at least 120, we need to calculate the probability of a score above 120. Use the Z-score formula \( Z = \frac{X - \mu}{\sigma} \) where \( X = 120 \). This gives \( Z = \frac{120 - 100}{16} = 1.25 \). Look up \( Z = 1.25 \) in the standard normal distribution table or use a calculator: \( P(Z > 1.25) \approx 0.1056 \). Hence, about 10.56% of children have an MDI of at least 120.
03

- Calculate Proportion for MDI At Least 80

For an MDI of at least 80, calculate the probability of a score above 80. Find the Z-score: \( Z = \frac{80 - 100}{16} = -1.25 \). Look up \( Z = -1.25 \) in the standard normal distribution table or in a calculator: \( P(Z > -1.25) \approx 0.8944 \). Therefore, about 89.44% of children have an MDI of at least 80.
04

- Determine the 99th Percentile MDI Score

The 99th percentile corresponds to a Z-score such that 99% of the population is below it. From Z-tables, this corresponds to approximately \( Z = 2.33 \). Convert this back to an MDI score using \( X = \mu + Z \times \sigma = 100 + 2.33 \times 16 \approx 137.28 \). So, the MDI score at the 99th percentile is approximately 137.28.
05

- Determine MDI Score with 1% Below It

For the 1st percentile, use a negative Z-score, reflecting that low a percentage. The corresponding Z-score is around \( Z = -2.33 \). Convert this to an MDI score: \( X = 100 + (-2.33) \times 16 \approx 62.72 \). Thus, approximately 1% of children have an MDI below 62.72.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bayley Scales of Infant Development
The Bayley Scales of Infant Development are crucial tools in child psychology. They provide a standardized measure to evaluate the development of infants and toddlers. These scales help assess developmental progress in areas such as cognitive, emotional, and motor skills.
One key indicator from the Bayley Scales is the Mental Development Index (MDI). It reflects a child's mental development and provides a score that can be compared across a population of infants. The MDI is designed to follow a normal distribution, making statistical analysis feasible and reliable. The mean is typically set at 100, with a standard deviation of 16. This setup allows healthcare professionals to quickly identify children who are developing typically and those who might require further evaluation or intervention.
Using these scales, researchers and clinicians can monitor an infant's development over time, ensuring timely support and interventions when necessary.
Z-score
A Z-score is an essential statistical measure showing how many standard deviations an element is from the mean. If you picture a normal distribution curve, the mean is always in the center. The Z-score tells you if a particular score is above or below this mean and by how much.
For example, in the context of the MDI from the Bayley Scales, a Z-score is calculated using the formula: \[ Z = \frac{X - \mu}{\sigma} \] where \(X\) is the score, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
If you have an MDI of 120 with a mean of 100 and a standard deviation of 16, the corresponding Z-score would be 1.25. This means the score of 120 is 1.25 standard deviations above the mean. Understanding Z-scores helps interpret how unusual or typical a particular score is within any given distribution.
Percentile
Percentiles help describe the relative position of a score within a distribution. When a score is at the 99th percentile, for example, it means that 99% of the scores are below this value. It is a useful measure to understand how an individual score compares to the rest of a population.
In the context of the Bayley Scales' MDI, to find the score that is the 99th percentile, you look for a Z-score that correlates to 0.99. This Z-score is approximately 2.33. Plug this Z-score back into the formula to find the corresponding MDI score: \[ X = \mu + Z \times \sigma \] which results in an MDI score of approximately 137.28. Similarly, the 1st percentile, which indicates that only 1% of scores are below it, corresponds to a Z-score of approximately -2.33, yielding an MDI score of around 62.72.
Understanding percentiles is key for comparing individual performance to broader norms and identifying outliers in developmental assessments.
Standard Deviation
Standard deviation is a key concept when working with data, especially in a normal distribution. It measures the amount of variation or dispersion of a set of values. In simpler terms, it indicates how spread out the numbers are in a data set.
For the Bayley Scales' MDI, the standard deviation is 16. This value tells us how far the scores typically vary from the mean score of 100. A smaller standard deviation would mean the scores are closely clustered around the mean, while a larger value signifies that the scores are more spread out.
Standard deviation is crucial for calculating Z-scores, which then help to find proportions and percentiles within any normally distributed data set. It provides context for interpreting how significant a departure from the mean really is, enabling us to make meaningful inferences about individual scores compared to the entire population.

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