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For a normal distribution, use Table A, software, or a calculator to find the probability that an observation is a. at least 1 standard deviation above the mean. b. at least 1 standard deviation below the mean. c. within 1 standard deviation of the mean.

Short Answer

Expert verified
(a) 0.1587 (b) 0.1587 (c) 0.6826

Step by step solution

01

Understand the Standard Normal Distribution

For a normal distribution, a random variable can be standardized using the z-score formula: \( z = \frac{x - \mu}{\sigma} \), where \( \mu \) is the mean and \( \sigma \) is the standard deviation. To find probabilities based on standard deviations, we refer to the standard normal distribution table (commonly known as Table A).
02

Calculate Probability for Part (a)

We need to find the probability that an observation is at least 1 standard deviation above the mean. This means finding \( P(Z \geq 1) \). Using the standard normal distribution table, we find that \( P(Z \geq 1) = 1 - P(Z < 1) \). From the table, \( P(Z < 1) \approx 0.8413 \). Therefore, \( P(Z \geq 1) = 1 - 0.8413 = 0.1587 \).
03

Calculate Probability for Part (b)

We need to find the probability that an observation is at least 1 standard deviation below the mean. This means finding \( P(Z \leq -1) \). From the standard normal distribution table, \( P(Z < -1) = 1 - P(Z < 1) = 1 - 0.8413 = 0.1587 \).
04

Calculate Probability for Part (c)

We need to find the probability that an observation is within 1 standard deviation of the mean. This means finding \( P(-1 \leq Z \leq 1) \). From the standard normal distribution table, \( P(Z < 1) \approx 0.8413 \) and \( P(Z < -1) = 0.1587 \). Therefore, \( P(-1 \leq Z \leq 1) = P(Z < 1) - P(Z < -1) = 0.8413 - 0.1587 = 0.6826 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
The Z-score is a crucial tool in statistics, especially when dealing with the standard normal distribution. It helps us understand how far a data point is from the mean of the distribution. The formula for the Z-score is:
\( z = \frac{x - \mu}{\sigma} \)
Where:
  • \( x \) is the value of the observation.
  • \( \mu \) is the mean of the distribution.
  • \( \sigma \) is the standard deviation.
The Z-score tells us the number of standard deviations an observation is from the mean. For example, if an observation has a Z-score of 1, it means it is one standard deviation above the mean. A Z-score of -1 implies it's one standard deviation below the mean. This standardization allows us to use the normal distribution table to find probabilities and make meaningful comparisons between different datasets.
Probability Calculation
Calculating probability using the normal distribution is an essential skill in understanding data behavior. By using the Z-score, we can determine the likelihood of different outcomes.
For instance, to find the probability of an observation being at least 1 standard deviation above the mean, we calculate \( P(Z \geq 1) \). From statistical rules and the normal distribution table:
  • \( P(Z \geq 1) = 1 - P(Z < 1) \)
  • From the table, \( P(Z < 1) \approx 0.8413 \)
Therefore, \( P(Z \geq 1) \approx 0.1587 \), which means there's about a 15.87% probability that an observation will be more than 1 standard deviation above the mean. Similarly, we can calculate other probabilities using this method, such as the probability of being more than 1 standard deviation below the mean or within 1 standard deviation of the mean.
Standard Deviation
Standard deviation is a fundamental measure in statistics that tells us how spread out the numbers in a dataset are around the mean. It's a measure of variability or diversity within a set of data points. The formula is as follows:
\( \sigma = \sqrt{\frac{1}{N} \sum_{i=1}^{N} (x_i - \mu)^2} \)
Where:
  • \( N \) is the number of observations.
  • \( x_i \) represents each observation.
  • \( \mu \) is the mean of the dataset.
A smaller standard deviation means that the values tend to be close to the mean of the dataset, while a larger standard deviation indicates the values are spread out over a wider range. In the context of the normal distribution, data is symmetrically distributed around the mean, and standard deviation provides a way to quantify the uncertainty or expected variance in the data.
Normal Distribution Table
The normal distribution table, often referred to as the Z-table, is a tool that shows the cumulative probability of a standard normal distribution up to a given Z-score. It is essential for finding probabilities associated with the standard normal distribution.
The table shows:
  • The cumulative probability from the lowest value up to a specific Z-score.
  • Values are symmetric. Therefore, \( P(Z < 0) = 0.5 \) is always true as the total area under the curve is 1.
When using this table, you can determine the probability of a certain value occurring within a normal distribution. For example, by looking up a Z-score of 1, you will find the cumulative probability up to that point is approximately 0.8413. This means about 84.13% of data lies below this Z-score. By subtracting from 1, we can find probabilities for Z-scores greater than a certain value, helping in assessing data distributions and making informed statistical decisions.

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Most popular questions from this chapter

Playing the lottery The state of Ohio has several statewide lottery options. One is the Pick 3 game in which you pick one of the 1000 three-digit numbers between 000 and 999\. The lottery selects a three-digit number at random. With a bet of \(\$ 1,\) you win \(\$ 500\) if your number is selected and nothing (\$0) otherwise. (Many states have a very similar type of lottery.) (Source: Background information from www.ohiolottery.com.) a. With a single \(\$ 1\) bet, what is the probability that you win \(\$ 500 ?\) b. Let \(X\) denote your winnings for a \(\$ 1\) bet, so \(x=\$ 0\) or \(x=\$ 500\). Construct the probability distribution for \(X\). c. Show that the mean of the distribution equals 0.50 , corresponding to an expected return of 50 cents for the dollar paid to play. Interpret the mean. d. In Ohio's Pick 4 lottery, you pick one of the 10,000 fourdigit numbers between 0000 and 9999 and (with a \(\$ 1\) bet) win \(\$ 5000\) if you get it correct. In terms of your expected winnings, with which game are you better off \(-\) playing Pick \(4,\) or playing Pick 3 ? Justify your answer.

San Francisco Giants hitting The table shows the probability distribution of the number of bases for a randomly selected time at bat for a San Francisco Giants player in 2010 (excluding times when the player got on base because of a walk or being hit by a pitch). In \(74.29 \%\) of the at-bats the player was out, \(17.04 \%\) of the time the player got a single (one base), \(5.17 \%\) of the time the player got a double (two bases), \(0.55 \%\) of the time the player got a triple, and \(2.95 \%\) of the time the player got a home run. a. Verify that the probabilities give a legitimate probability distribution. b. Find the mean of this probability distribution. c. Interpret the mean, explaining why it does not have to be a whole number, even though each possible value for the number of bases is a whole number. $$ \begin{array}{cc} \hline {\text { San Francisco Giants Hitting }} \\ \hline \text { Number of Bases } & \text { Probability } \\ \hline 0 & 0.7429 \\ 1 & 0.1704 \\ 2 & 0.0517 \\ 3 & 0.0055 \\ 4 & 0.0295 \\ \hline \end{array} $$

A balanced die with six sides is rolled 60 times. a. For the binomial distribution of \(X=\) number of \(6 \mathrm{~s}\), what is \(n\) and what is \(p ?\) b. Find the mean and the standard deviation of the distribution of \(X\). Interpret. c. If you observe \(x=0,\) would you be skeptical that the die is balanced? Explain why, based on the mean and standard deviation of \(X\). d. Show that the probability that \(x=0\) is 0.0000177 .

A World Health Organization study (the MONICA project) of health in various countries reported that in Canada, systolic blood pressure readings have a mean of 121 and a standard deviation of \(16 .\) A reading above 140 is considered high blood pressure. a. What is the \(z\) -score for a blood pressure reading of \(140 ?\) b. If systolic blood pressure in Canada has a normal distribution, what proportion of Canadians suffers from high blood pressure? c. What proportion of Canadians has systolic blood pressures in the range from 100 to \(140 ?\) d. Find the 90 th percentile of blood pressure readings.

For an approximately normally distributed random variable \(X\) with a mean of 200 and a standard deviation of 36 , a. Find the \(z\) -score corresponding to the lower quartile and upper quartile of the standard normal distribution. b. Find and interpret the lower quartile and upper quartile of \(X\). c. Find the interquartile range (IQR) of \(X\). d. An observation is a potential outlier if it is more than \(1.5 \times\) IQR below \(\mathrm{Q} 1\) or above \(\mathrm{Q} 3\). Find the values of \(X\) that would be considered potential outliers.

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