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Diamond weight and price The weight (in carats) and the price (in millions of dollars) of the 9 most expensive diamonds in the world was collected from www.elitetraveler.com. Let the explanatory variable \(x=\) weight and the response variable \(y=\) price. The regression equation is \(\hat{y}=109.618+0.043 x\). a. Princie is a diamond whose weight is 34.65 carats. Use the regression equation to predict its price. b. The selling price of Princie is \(\$ 39.3\) million. Calculate the residual associated with the diamond and comment on its value in the context of the problem. c. The correlation coefficient is \(0.053 .\) Does it mean that a diamond's weight is a reliable predictor of its price?

Short Answer

Expert verified
a. Predicted price: $111.11 million. b. Residual: -$71.81 million (predicted price is higher). c. Weight is not a reliable predictor of price (correlation is weak).

Step by step solution

01

Identify the Variables

For part (a), we know that the weight of the diamond, which is our explanatory variable, is 34.65 carats. We have a regression equation: \( \hat{y} = 109.618 + 0.043x \). Here, \(x\) stands for the diamond's weight, and \(\hat{y}\) is the predicted price in millions.
02

Substitute and Solve (a)

Substitute \( x = 34.65 \) into the regression equation to predict the price:\[ \hat{y} = 109.618 + 0.043 \times 34.65 \]Calculate:\[ \hat{y} = 109.618 + 1.48995 = 111.10795 \]The predicted price of the Princie diamond is approximately $111.11 million.
03

Define Residual (b)

Residual is the difference between the observed price and the predicted price. For Princie, it is given that the observed price \( y = 39.3 \) million.
04

Calculate the Residual (b)

The residual for Princie is calculated as follows:\[ \text{Residual} = y - \hat{y} = 39.3 - 111.10795 \approx -71.80795 \]The residual is approximately -71.81 million, meaning the predicted price is much higher than the actual price.
05

Analyze Correlation (c)

The correlation coefficient \( r = 0.053 \) indicates a very weak correlation between the weight and price. This low value suggests that weight is not a reliable predictor of price.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Regression Analysis
Regression analysis is a statistical tool used to examine the relationship between two or more variables. In simple linear regression, this involves an explanatory variable (independent) and a response variable (dependent).

For example, in our exercise, the explanatory variable is the diamond's weight (\(x\)), and the response variable is its price (\(y\)). The goal is to determine how the explanatory variable influences the response variable. The relationship is represented by a regression equation, such as \(\hat{y} = 109.618 + 0.043x\). This equation suggests that for every additional carat in weight, the price increases by 0.043 million dollars.
  • Regression equations help predict value changes based on variable changes.
  • They offer insights into trends and data patterns, aiding in decision-making.
Correlation Coefficient
The correlation coefficient, denoted by \(r\), measures the strength and direction of a linear relationship between two variables on a scatter plot. This value ranges between -1 and 1.

In our diamond example, the correlation coefficient was \(r = 0.053\), indicating a very weak positive linear relationship between weight and price. A correlation so close to zero suggests that there’s almost no linear relationship.
  • If \(r = 1\) or \(-1\), there's a perfect linear relationship.
  • \(r = 0\) suggests no linear relationship at all.
  • A weak correlation might imply other factors influence the response variable.

Thus, using weight alone to predict price isn't reliable, as evidenced by the low correlation.
Residuals
Residuals are the differences between observed values and the values predicted by a model. These provide insight into the model's accuracy in predicting outcomes.

Mathematically, it's calculated as: \[\text{Residual} = y - \hat{y}\], where \(y\) is the observed value, and \(\hat{y}\) is the predicted value. For the Princie diamond, the residual was calculated as \(-71.81\) million dollars, which indicates the prediction was much higher than the actual price.
  • Large residuals highlight discrepancies or variability not captured by the model.
  • Consistently large residuals could imply a model isn't the best fit.

Analyzing residuals helps in refining models and recognizing trends or outliers.
Predictive Modeling
Predictive modeling uses statistical techniques to define relationships and predict future outcomes based on datasets. Regression analysis often forms the backbone of these models.

In our scenario, predictive modeling aims to forecast diamond prices based on weight. With the regression equation, we predict how changes in weight affect prices. However, the weak correlation coefficient suggests weight alone is inadequate for accurate predictions.
  • Reliable predictive models account for multiple influencing factors, enhancing accuracy.
  • Models improve over time with more data and better statistical methods.
  • They are crucial in various industries for planning and strategy.

Consistently improving models ensures they stay relevant and useful for predictions.

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Most popular questions from this chapter

Each month, the owner of Fay's Tanning Salon records in a data file the monthly total sales receipts and the amount spent that month on advertising. a. Identify the two variables. b. For each variable, indicate whether it is quantitative or categorical. c. Identify the response variable and the explanatory variable.

NAEP scores In 2015 , eighth-grade math scores on the National Assessment of Educational Progress had a mean of 283.56 in Maryland compared to a mean of 284.37 in Connecticut (Source: http://nces.ed.gov/nationsreportcard/ naepdata/dataset.aspx). a. Identify the response variable and the explanatory variable. b. The means in Maryland were respectively \(274,284,285,\) 291 and 294 for people who reported the number of pages read in school and for homework, respectively as \(0-5,6-10,11-15,15-20\) and 20 or more. These means were 270,281,284,289 and 293 in Connecticut. Identify the third variable given here. Explain how it is possible for Maryland to have the higher mean for each class, yet for Connecticut to have the higher mean when the data are combined. (This is a case of Simpson's paradox for a quantitative response.)

The figure shows recent data on \(x=\) the number of televisions per 100 people and \(y=\) the birth rate (number of births per 1000 people) for six African and Asian nations. The regression line, \(\hat{y}=29.8-0.024 x,\) applies to the data for these six countries. For illustration, another point is added at \((81,15.2),\) which is the observation for the United States. The regression line for all seven points is \(\hat{y}=31.2-0.195 x\). The figure shows this line and the one without the U.S. observation. a. Does the U.S. observation appear to be (i) an outlier on \(x,\) (ii) an outlier on \(y,\) or (iii) a regression outlier relative to the regression line for the other six observations? b. State the two conditions under which a single point can have a dramatic effect on the slope and show that they apply here. c. This one point also drastically affects the correlation, which is \(r=-0.051\) without the United States but \(r=-0.935\) with the United States. Explain why you would conclude that the association between birth rate and number of televisions is (i) very weak without the U.S. point and (ii) very strong with the U.S. point. d. Explain why the U.S. residual for the line fitted using that point is very small. This shows that a point can be influential even if its residual is not large.

NL baseball Example 9 related \(y=\) team scoring (per game) and \(x=\) team batting average for American League teams. For National League teams in 2010 , \(\hat{y}=-6.25+41.5 x\). (Data available on the book's website in the NL team statistics file.) a. The team batting averages fell between 0.242 and \(0.272 .\) Explain how to interpret the slope in context. b. The standard deviations were 0.00782 for team batting average and 0.3604 for team scoring. The correlation between these variables was 0.900 . Show how the correlation and slope of 41.5 relate in terms of these standard deviations. c. Software reports \(r^{2}=0.81 .\) Explain how to interpret this measure.

Advertising and sales Each month, the owner of Fay's Tanning Salon records in a data file \(y=\) monthly total sales receipts and \(x=\) amount spent that month on advertising, both in thousands of dollars. For the first three months of operation, the observations are as shown in the table. \begin{tabular}{cc} \hline Advertising & Sales \\ \hline 0 & 4 \\ 1 & 6 \\ 2 & 8 \\ \hline \end{tabular} a. Sketch a scatterplot. b. From inspection of the scatterplot, state the correlation and the regression line. (Note: You should be able to figure them out without using software or formulas.) c. Find the mean and standard deviation for each variable. d. Using part c, find the regression line, using the formulas for the slope and the \(y\) -intercept. Interpret the \(y\) -intercept and the slope.

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