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During a recent semester at the University of Florida, students having accounts on a mainframe computer had storage space use (in kilobytes) described by the five-number summary, minimum \(=4, \mathrm{Q} 1=256,\) median \(=530, \mathrm{Q} 3=1105\) and maximum \(=320,000\). a. Would you expect this distribution to be symmetric, skewed to the right, or skewed to the left? Explain. b. Use the \(1.5 \times\) IQR criterion to determine whether any potential outliers are present.

Short Answer

Expert verified
a. Skewed to the right. b. Yes, there are potential outliers above 2378.5.

Step by step solution

01

Identify Quartiles and Calculate IQR

First, recognize the quartiles from the five-number summary: \( Q_1 = 256 \), \( Q_3 = 1105 \). The Interquartile Range (IQR) is calculated as: \[ IQR = Q_3 - Q_1 = 1105 - 256 = 849 \]
02

Determine Lower and Upper Fences

Use the IQR to calculate potential outlier fences. Lower fence: \( Q_1 - 1.5 \times IQR \) and upper fence: \( Q_3 + 1.5 \times IQR \).\[\text{Lower fence} = 256 - 1.5 \times 849 = 256 - 1273.5 = -1017.5 \] \[\text{Upper fence} = 1105 + 1.5 \times 849 = 1105 + 1273.5 = 2378.5 \]
03

Compare Data with Fences

Compare the minimum and maximum values against the calculated fences. The minimum is 4, which is above the lower fence. The maximum is 320,000, which is above the upper fence of 2378.5, indicating outliers on the upper end.
04

Assess Skewness Based on Summary

The large gap between the median (530) and the maximum (320,000) suggests a longer tail on the right side. This indicates the distribution is skewed to the right.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Five-number summary
The five-number summary is an intuitive way to describe a dataset using five specific numbers. These numbers are:
  • Minimum
  • First Quartile (Q1)
  • Median
  • Third Quartile (Q3)
  • Maximum
This summary provides a snapshot of the distribution of the data. Imagine it as a basic structure for understanding where most of the data points fall instead of relying on a single average value.
With these five values, you can understand the spread and center of a dataset. Additionally, it helps highlight potential anomalies, such as outliers. For our dataset, we apply the five-number summary as follows: the minimum is 4, Q1 is 256, the median is 530, Q3 is 1105, and the maximum is 320,000. This information outlines the primary values separating sections of the dataset.
Interquartile Range (IQR)
The Interquartile Range (IQR) is a measure of statistical dispersion and gives insight into the variance of the dataset. It's calculated by subtracting the first quartile (Q1) from the third quartile (Q3): \( IQR = Q3 - Q1 \).
This range focuses on the middle 50% of the data, making it resistant to outliers and reflecting the central span of the dataset.
In our exercise, we find the IQR by calculating the difference between Q3 and Q1: \[ IQR = 1105 - 256 = 849 \].
This value represents the core spread of our data, leaving out possible skewness or outliers that might distort our understanding of the dataset.
Skewness
Skewness refers to the asymmetry in the distribution of data. A dataset is said to be skewed when it shows a tendency to extend more to one side than the other. In simpler terms, it indicates if more data is clustered on the left or right.
A right-skewed distribution has a longer tail on the right, suggesting more upward outliers or higher spreads. Meanwhile, a left-skewed distribution tails off to the left.
In our case, the significant distance between the median (530) and the maximum (320,000) illustrates a right skew. This means there are a few values far greater than the median, causing the distribution not to be symmetrical.
Outliers
Outliers are data points that deviate significantly from the rest of the dataset. They can be identified using specific rules, one of which is the 1.5 times IQR criterion.
For this criterion, we calculate the "fences":
  • Lower fence: \( Q1 - 1.5 \times IQR \)
  • Upper fence: \( Q3 + 1.5 \times IQR \)
If any data point lies beyond these boundaries, it's considered an outlier.
In our example, the lower fence is \(-1017.5\) and the upper fence is \(2378.5\). Since the maximum value \(320,000\) exceeds the upper fence, it is flagged as an outlier. The existence of such extreme values could indicate data entry errors or special cases necessitating closer investigation.

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Most popular questions from this chapter

In a study of graduate students who took the Graduate Record Exam (GRE), the Educational Testing Service reported that for the quantitative exam, U.S. citizens had a mean of 529 and standard deviation of \(127,\) whereas the non-U.S. citizens had a mean of 649 and standard deviation of \(129 .\) Which of the following is true? a. Both groups had about the same amount of variability in their scores, but non-U.S. citizens performed better, on the average, than U.S. citizens. b. If the distribution of scores was approximately bell shaped, then almost no U.S. citizens scored below 400 . c. If the scores range between 200 and \(800,\) then probably the scores for non-U.S. citizens were symmetric and bell shaped. d. A non-U.S. citizen who scored 3 standard deviations below the mean had a score of 200 .

Which statement about the standard deviation \(s\) is false? a. \(s\) can never be negative. b. \(s\) can never be zero. c. For bell-shaped distributions, about \(95 \%\) of the data fall within \(\bar{x} \pm 2 s\) d. \(s\) is a nonresistant (sensitive to outliers) measure of variability, as is the range.

The table in the next column shows the number of times \(20-24\) -year-old U.S. residents have been married, based on a Bureau of the Census report from 2004 . The frequencies are actually thousands of people. For instance, 8,418,000 men never married, but this does not affect calculations about the mean or median. $$\begin{array}{crr} \hline {\text { Number of Times Married, for Subjects of Age 20-24 }} \\ \hline & {\text { Frequency }} \\ \hline \text { Number Times Married } & \text { Women } & {\text { Men }} \\ \hline 0 & 7350 & 8418 \\ 1 & 2587 & 1594 \\ 2 & 80 & 10 \\\\\text { Total } & \mathbf{1 0 , 0 1 7} & \mathbf{1 0 , 0 2 2} \\\ \hline\end{array}$$ a. Find the median and mean for each gender. b. On average, have women or men been married more often? Which statistic do you prefer to answer this question? (The mean, as opposed to the median, uses the numerical values of all the observations, not just the ordering. For discrete data with only a few values such as the number of times married, it can be more informative.)

Continuous or discrete? Which of the following variables are continuous, when the measurements are as precise as possible? a. Age of mother b. Number of children in a family c. Cooking time for preparing dinner d. Latitude and longitude of a city e. Population size of a city

The U.S. Bureau of the Census reported a median sales price of new houses sold in March 2014 of \(\$ 290,000\). Would you expect the mean sales price to have been higher or lower? Explain.

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