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All graduate students who attend an Irish university must submit their math and verbal GRE scores. Both the scores have a mean of 150 and a standard deviation of \(6.5 .\) The regression equation relating \(y=\) verbal \(G R E\) score and \(x=\) math GRE score is \(\hat{y}=30+0.80 x\) a. Find the predicted verbal GRE score for a student who has the mean math GRE score of \(150 .\) (Note: At the \(x\) value equal to \(\bar{x},\) the predicted value of \(y\) equals \(\bar{y} .)\) b. Show how to find the correlation. Interpret its value as a standardized slope. (Hint: Both standard deviations are equal.) c. Find \(r^{2}\) and interpret its value.

Short Answer

Expert verified
a. Predicted verbal score is 150. b. Correlation is 0.80. c. \( r^{2} \) is 0.64, explaining 64% of the variability.

Step by step solution

01

Finding the Mean Math GRE Score

We know that the mean math GRE score, \( x \), is given as 150. We will use this mean value in the regression equation to find the predicted verbal GRE score.
02

Using the Regression Equation

Substitute the mean math GRE score into the regression equation: \( \hat{y} = 30 + 0.80 \times 150 \). This will give us the predicted verbal GRE score.
03

Calculating the Predicted Score

Calculate \( \hat{y} = 30 + 0.80 \times 150 \). This simplifies to \( \hat{y} = 30 + 120 = 150 \). Therefore, the predicted verbal GRE score is 150.
04

Understanding Correlation

The correlation coefficient \( r \) indicates the strength and direction of the linear relationship between two variables. Given that both standard deviations are equal, the correlation can be interpreted as the standardized slope in our regression equation.
05

Relating Slope to Correlation

Since standard deviations for math and verbal GRE scores are equal, the correlation \( r \) equals the slope of the regression equation. Therefore, \( r = 0.80 \).
06

Calculating Coefficient of Determination \( r^{2} \)

The coefficient of determination \( r^{2} \) is found by squaring the correlation coefficient: \( r^{2} = (0.80)^{2} = 0.64 \).
07

Interpretation of \( r^{2} \)

The \( r^{2} \) value of 0.64 implies that 64% of the variability in the verbal GRE scores can be explained by the linear relationship with the math GRE scores.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Correlation Coefficient
The correlation coefficient gives us a way to understand the linear relationship between two variables. In this case, the math and verbal GRE scores are our variables. The correlation coefficient, denoted as \( r \), tells us three key things:
  • Whether the relationship between the variables is positive or negative.
  • How strong that relationship is.
  • Simply put, it ranges between -1 and 1. A value of 1 indicates a perfect positive relationship, while -1 indicates a perfect negative one.
In our example, the correlation coefficient \( r \) is 0.80. This value is given by the slope of the regression equation \( \hat{y} = 30 + 0.80x \). Because both the standard deviations of math and verbal GRE scores are the same, \( r \) directly equates to the slope.

In essence, an \( r \) of 0.80 suggests a strong positive relationship between the math and verbal GRE scores. This means that generally, as math scores increase, verbal scores also increase at a consistent rate. Thus, understanding and calculating the correlation is crucial for interpreting data relationships confidently.
Coefficient of Determination
The coefficient of determination, represented as \( r^2 \), is a handy measure to understand how much of the variation in one variable can be predicted from another.
  • If you think of \( r \) as describing the strength and direction of a linear relationship, \( r^2 \) tells us about the predictive power of that relationship.
  • This value ranges from 0 to 1, where higher values denote a stronger ability of the model to explain variability in the data.
In our GRE scores example, we calculated the \( r^2 \) to be 0.64, which is simply the square of the correlation coefficient (0.80).

This indicates that 64% of the variability in the verbal GRE scores is explained by the math GRE scores. Hence, a significant amount of the variation in verbal scores can be related back to the math scores, reinforcing the strength of the linear association between the two variables. The closer the \( r^2 \) value is to 1, the better your regression line fits the data.
Predicted Values
Predicting values involves using a regression equation to estimate what one variable would be given the value of another. Here, our regression equation is \( \hat{y} = 30 + 0.80x \), where \( \hat{y} \) is the predicted verbal GRE score and \( x \) is the math GRE score.
  • This formula helps us make informed predictions based on established relationships.
  • The main idea is that with a known \( x \), you can substitute it into the equation to find \( \hat{y} \).
For example, if a student scored the mean math score of 150, we plug it into the equation: \( \hat{y} = 30 + 0.80 \times 150 \), resulting in a \( \hat{y} = 150 \).

This means that a math score of 150 predicts a verbal score of 150, illustrating the power of regression analysis in forecasting outcomes. Predicted values are particularly useful in making decisions based on potential future trends or results.

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Most popular questions from this chapter

Predicting maximum bench strength in males For the Male Athlete Strength data file on the book's website, the prediction equation relating \(y=\) maximum bench press (maxBP) in kilograms to \(x=\) repetitions to fatigue bench press \((\mathrm{repBP})\) is \(\hat{y}=117.5+5.86 x\) a. Find the predicted maxBP for a male athlete with a repBP of \(35,\) which was one of the highest repBP values. b. Find the predicted maxBP for a male athlete with a repBP of 0 , which was the lowest repBP value. c. Interpret the \(y\) -intercept. Use the slope to describe how predicted maxBP changes as repBP increases from 0 to 35 .

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