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In a study conducted by a pharmaceutical company, 605 out of 790 smokers and 122 out of 434 nonsmokers were diagnosed with lung cancer. a. Construct a \(2 \times 2\) contingency table relating smoking (SMOKING, categories smoker and nonsmoker) as the rows to lung cancer (LUNGCANCER, categories present and absent) as the columns. b. Find the four expected cell counts when assuming independence. Compare them to the observed cell counts, identifying cells having more observations than expected. c. For this data, \(X^{2}=272.89 .\) Verify this value by plugging into the formula for \(X^{2}\) and computing the sum.

Short Answer

Expert verified
a. Contingency table constructed, b. Expected counts show deviations, c. Verified \(X^2 = 272.89\).

Step by step solution

01

Setting Up the Observed Contingency Table

We start by organizing the data into a contingency table. The rows represent the two categories of smoking (Smoker, Nonsmoker), and the columns indicate whether lung cancer is present or absent. | | Lung Cancer Present | Lung Cancer Absent | Total | |-------------|---------------------|--------------------|-------| | Smoker | 605 | 185 (790-605) | 790 | | Nonsmoker | 122 | 312 (434-122) | 434 | | Total | 727 (605+122) | 497 (185+312) | 1224 |
02

Calculating Expected Cell Counts

To find the expected cell counts, we use the formula: \[E_{ij} = \frac{(\text{Row Total}_i)(\text{Column Total}_j)}{\text{Grand Total}}\] where \(i\) refers to the row and \(j\) to the column.- For Smoker with Lung Cancer: \(E_{11} = \frac{790 \times 727}{1224} \approx 468.91\)- For Smoker without Lung Cancer: \(E_{12} = \frac{790 \times 497}{1224} \approx 321.09\)- For Nonsmoker with Lung Cancer: \(E_{21} = \frac{434 \times 727}{1224} \approx 258.09\)- For Nonsmoker without Lung Cancer: \(E_{22} = \frac{434 \times 497}{1224} \approx 175.91\)
03

Comparing Observed and Expected Cell Counts

We compare the observed counts from Step 1 to the expected counts calculated in Step 2:- Smoker with Lung Cancer: Observed = 605, Expected = \(\approx 468.91\)- Smoker without Lung Cancer: Observed = 185, Expected = \(\approx 321.09\)- Nonsmoker with Lung Cancer: Observed = 122, Expected = \(\approx 258.09\)- Nonsmoker without Lung Cancer: Observed = 312, Expected = \(\approx 175.91\)Comparing these, the Smoker with Lung Cancer and Nonsmoker without Lung Cancer cells have more observations than expected.
04

Calculating the Chi-Square Statistic

The formula for the Chi-Square statistic is: \[X^2 = \sum \frac{(O_{ij} - E_{ij})^2}{E_{ij}}\] - For Smoker with Lung Cancer: \(\frac{(605 - 468.91)^2}{468.91} \approx 33.58\)- For Smoker without Lung Cancer: \(\frac{(185 - 321.09)^2}{321.09} \approx 64.90\)- For Nonsmoker with Lung Cancer: \(\frac{(122 - 258.09)^2}{258.09} \approx 73.58\)- For Nonsmoker without Lung Cancer: \(\frac{(312 - 175.91)^2}{175.91} \approx 100.83\)Summing these values: \[X^2 = 33.58 + 64.90 + 73.58 + 100.83 = 272.89\] This verifies the given value of \(X^2 = 272.89\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chi-Square Test
The Chi-Square Test is a statistical method used to examine the differences between observed and expected frequencies in a contingency table. This test helps determine if there is a significant association between two categorical variables. It's an essential tool for deciding whether the deviation between what we observe and what we expect could be attributed to something beyond mere chance.

The core idea of the Chi-Square Test is to compare the pattern of observed data, as in how often categories co-occur, against what our null hypothesis (which usually states there is no relationship between the variables) would predict. The formula for the Chi-Square statistic \[X^2 = \sum \frac{(O_{ij} - E_{ij})^2}{E_{ij}}\]quantifies how much the observed frequencies \(O_{ij}\) deviate from the expected frequencies \(E_{ij}\).

Understanding the result of a Chi-Square Test involves comparing the calculated \(X^2\) value to a critical value from the Chi-Square distribution table. If your calculated \(X^2\) is larger than the value from the table, you may conclude that the variables have a significant interaction. If it's smaller, there likely isn't enough evidence to indicate a significant relationship outside of chance.
Expected Cell Counts
Expected cell counts form the basis for comparison in the Chi-Square Test. These expected frequencies answer the question, "How would the cell counts look if our variables were actually independent of each other?"

To calculate these counts, we use the formula:\[E_{ij} = \frac{(\text{Row Total}_i)(\text{Column Total}_j)}{\text{Grand Total}}\]This equation uses the totals from our data's rows and columns to estimate what each cell count should be under the assumption of independence.

For example, if we are investigating whether smoking affects lung cancer rates, the expected count for smokers diagnosed with lung cancer would be computed given the total number of smokers and the total number of lung cancer cases. Calculating these helps identify which cells have a disproportionate number of observations. When you see huge discrepancies between observed and expected counts, it's the first indication that there might be a relationship between your variables.
Observed Frequencies
Observed frequencies in a contingency table are simply the data counts you have collected in your study. They indicate how many times each category pair occurs, whether that's smokers with or without lung cancer, or nonsmokers with or without lung cancer. These frequencies serve as real, tangible numbers to compare against theoretical expectations.

In our lung cancer study, for instance, we recorded 605 smokers with lung cancer and 122 nonsmokers with lung cancer. These numbers are our observed frequencies. By juxtaposing them with expected frequencies, we can assess whether certain categories happen more or less often than chance would suggest.

Ultimately, the process of comparing observed frequencies to expected ones and calculating the Chi-Square statistic helps uncover hidden patterns, potentially revealing important associations between categorical variables.

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Most popular questions from this chapter

Market price associated with factor cost? Whether the price of mango juice will rise is a categorical variable with categories (yes, no). Another categorical variable to consider is whether the price of mangoes is rising with categories (yes, no). Would you expect these variables to be independent or associated? Explain.

Multiple response variables Each subject in a sample of 100 men and 100 women is asked to indicate which of the following factors (one or more) are responsible for increases in crime committed by teenagers: \(\mathrm{A}-\) the increasing gap in income between the rich and poor, \(\mathrm{B}-\) the increase in the percentage of single-parent families, \(\mathrm{C}\) - insufficient time that parents spend with their children. To analyze whether responses differ by gender of respondent, we cross-classify the responses by gender, as the table shows. a. Is it valid to apply the chi-squared test of independence to these data? Explain. b. Explain how this table actually provides information needed to cross- classify gender with each of three variables. Construct the contingency table relating gender to opinion about whether factor \(A\) is responsible for increases in teenage crime. \begin{tabular}{lccc} \hline \multicolumn{3}{l} { Three Factors for Explaining Teenage Crime } \\ \hline Gender & A & B & C \\ \hline Men & 60 & 81 & 75 \\ Women & 75 & 87 & 86 \\ \hline \end{tabular}

Every year, a large-scale poll of new employees conducted by the human resources management department at a consulting firm asks their opinions on a variety of issues. In \(2015,\) although women were more likely to rate their time management skills as "above average," they were also twice as likely as men to indicate that they frequently felt overwhelmed by all they have to do \((38.4 \%\) versus \(19.3 \%)\) a. If results for the population of new employees were similar to these, would gender and feelings of being overwhelmed be independent or dependent? b. Give an example of hypothetical population percentages for which these variables would be independent.

Female participation in defense services? When people participating in recent surveys were asked if women should actively participate in defense services, about \(91 \%\) of females and \(91 \%\) of males answered yes and the rest answered no. a. For males and for females, report the conditional distributions on this response variable in a \(2 \times 2\) table, using outcome categories (yes, no). b. If results for the entire population are similar to these, does it seem possible that gender and opinion about having active participation of women in defense services are independent? Explain.

Degrees of freedom explained For testing independence in a contingency table of size \(r \times c,\) the degrees of freedom (df) for the chi-squared distribution equal \(d f=(r-1) \times(c-1) .\) They have the following interpretation: Given the row and column marginal totals in an \(r \times\) contingency table, the cell counts in a rectangular block of size \((r-1) \times(c-1)\) determine all the other cell counts. Consider the following table, which cross-classifies political views by whether the subject would ever vote for a female president, based on the 2010 GSS. For this \(3 \times 2\) table, suppose we know the counts in the upper left-hand \((3-1) \times(2-1)=2 \times 1\) block of the table, as shown. \begin{tabular}{lccc} \hline & \multicolumn{2}{c} { Vote for Female } & \\ & \multicolumn{2}{c} { President } & \\ \cline { 2 - 3 } Political Views & Yes & No & Total \\ \hline Extremely Liberal & 56 & & 58 \\ Moderate & 490 & & 509 \\ Extremely Conservative & & & 61 \\ \hline Total & 604 & 24 & 628 \\ \hline \end{tabular} a. Given the cell counts and the row and column totak, fill in the counts that must appear in the blank cells. b. Now, suppose instead of the preceding table, you are shown the following table, this time only revealing a \(2 \times 1\) block in the lower-right part. Find the counts in the remaining cells. \begin{tabular}{lccc} \hline & \multicolumn{2}{c} { Vote for Female } & \\ & \multicolumn{2}{c} { President } & \\ \cline { 2 - 3 } Political Views & Yes & No & Total \\ \hline Extremely Liberal & & & \\ Moderate & & 58 \\ Extremely Conservative & & 3 & 61 \\ \hline Total & & 19 & 509 \\ \hline \end{tabular} This example serves to show that once the marginal totals are fixed in a contingency table, a block of only cell counts is free to vary. Once \((r-1) \times(c-1)\) these are given (as in part a or \(\mathrm{b}\) ), the remaining cell counts follow automatically. The value for the degrees of freedom is exactly the number of cells in this block, \(d f=(r-1) \times(c-1)\) or

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