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The table shows results from the 2014 General Social Survey on gender and whether one believes in an afterlife. $$ \begin{array}{lccc} \hline & \ {\text { Belief in Afterlife }} & \\ { 2 - 3 } \text { Gender } & \text { Yes } & \text { No } & \text { Total } \\\ \hline \text { Female } & 1026 & 207 & 1233 \\ \text { Male } & 757 & 252 & 1009 \\ \hline\end{array}$$ a. Denote the population proportion who believe in an afterlife by \(p_{1}\) for females and by \(p_{2}\) for males. Estimate \(p_{1}, p_{2},\) and \(\left(p_{1}-p_{2}\right)\) b. Find the standard error for the estimate of \(\left(p_{1}-p_{2}\right)\). Interpret. c. Construct a \(95 \%\) confidence interval for \(\left(p_{1}-p_{2}\right)\). Can you conclude which of \(p_{1}\) and \(p_{2}\) is larger? Explain. d. Suppose that, unknown to us, \(p_{1}=0.81\) and \(p_{2}=0.72 .\) Does the confidence interval in part c contain the parameter it is designed to estimate? Explain.

Short Answer

Expert verified
The female proportion who believe in afterlife is larger. The confidence interval includes the true parameter difference.

Step by step solution

01

Calculate Female Proportion (p1)

To find the population proportion for females who believe in an afterlife, divide the number of females who said 'Yes' by the total number of females surveyed. Therefore, \( p_1 = \frac{1026}{1233} \approx 0.832 \).
02

Calculate Male Proportion (p2)

For males, compute the proportion who believe in an afterlife by dividing the number of males who said 'Yes' by the total number of males surveyed. Thus, \( p_2 = \frac{757}{1009} \approx 0.750 \).
03

Calculate Difference in Proportions (p1 - p2)

Subtract the male proportion \( p_2 \) from the female proportion \( p_1 \) to find the difference in the proportions: \( p_1 - p_2 = 0.832 - 0.750 = 0.082 \).
04

Find Standard Error for Difference

The standard error for the difference in two proportions is calculated using the following formula: \[ SE = \sqrt{ \frac{p_1(1-p_1)}{n_1} + \frac{p_2(1-p_2)}{n_2} } \] Substituting the given values: \[ SE = \sqrt{ \frac{0.832 \times 0.168}{1233} + \frac{0.750 \times 0.250}{1009} } \approx 0.021 \].
05

Construct 95% Confidence Interval

To construct a 95% confidence interval for \( p_1 - p_2 \), use the formula: \[ (p_1 - p_2) \pm Z\cdot SE \] where \( Z \approx 1.96 \) for a 95% confidence level. Therefore, the interval is: \[ 0.082 \pm 1.96 \times 0.021 \approx (0.041, 0.123) \]. Since the interval does not include zero and is entirely positive, \( p_1 \) is greater than \( p_2 \).
06

Check if Confidence Interval Contains True Difference

The given true proportions are \( p_1 = 0.81 \) and \( p_2 = 0.72 \), which means the true difference \( p_1 - p_2 = 0.09 \). This value falls within our calculated confidence interval of (0.041, 0.123), indicating that the interval does include the true parameter difference it is designed to estimate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference in Proportions
When we talk about the difference in proportions, we're comparing two groups to see how common a certain characteristic is in each of them. In this case, we're looking at how many females versus males believe in an afterlife. To find these proportions, we divide the number of affirmative responses by the total surveyed in each gender group.

For example:
  • The proportion of females believing in an afterlife, noted as \( p_1 \), is calculated as \( \frac{1026}{1233} \approx 0.832 \).
  • For males, the proportion \( p_2 \) is \( \frac{757}{1009} \approx 0.750 \).
Subtracting these, we get the difference \( p_1 - p_2 = 0.832 - 0.750 = 0.082 \). This difference indicates that a higher proportion of females believe in an afterlife compared to males.

Understanding this difference helps us to see how these two groups compare in their beliefs.
Standard Error
Standard error is a measure of how much variation we might expect in the difference between two proportions. It gives us a sense of the uncertainty around the estimated difference in proportions. The formula for the standard error of the difference is:
  • \[ SE = \sqrt{ \frac{p_1(1-p_1)}{n_1} + \frac{p_2(1-p_2)}{n_2} } \]
Here, \( n_1 \) and \( n_2 \) represent the total number of surveyed females and males, respectively.

By plugging the information we have:
  • Females: \( p_1 = 0.832 \), \( n_1 = 1233 \)
  • Males: \( p_2 = 0.750 \), \( n_2 = 1009 \)
The standard error works out to be \( SE \approx 0.021 \). This value tells us the expected variability in the estimated difference between the two proportions. A smaller standard error suggests we have a more accurate estimate of the difference.
95% Confidence Level
Taking a deep dive into what a 95% confidence level means might help clarify the idea of confidence intervals. A confidence interval provides a range of values that are believed to contain the true difference in proportions, here between genders believing in an afterlife.
  • To find this interval, we use the formula: \[ (p_1 - p_2) \pm Z \cdot SE \]
  • For a 95% confidence level, \( Z \approx 1.96 \).
  • Therefore, the interval becomes: \[ 0.082 \pm 1.96 \times 0.021 \approx (0.041, 0.123) \]
This confidence interval tells us that we are 95% confident the true difference in the proportions of belief in an afterlife between females and males lies between 0.041 and 0.123. Because this range does not include zero, it suggests that there is a statistically significant difference between the two groups, meaning that more females than males believe in an afterlife according to the survey results.

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Most popular questions from this chapter

Energy drinks: health risks and toxicity A study was carried out in Saudi Arabia in which 31 male university students (18 overweight/obese and 13 having normal weight) were enrolled from December 2013 to December 2014 (www.annsaudimed.net). The heart rate variability was significantly less in obese subjects as compared to subjects with normal weight at 60 minutes after consuming an energy drink as indicated by the mean heart rate range MHRR (P-value \(=0.012\) ). a. The conclusion was based on a significance test comparing means. Define notation in context, identify the groups and the population means and state the null hypothesis for the test. b. What information you are not able to obtain from the P-value approach which you could learn if the confidence interval comparing the means was provided?

In the study for cancer death rates, consider the null hypothesis that the population proportion of cancer deaths \(p_{1}\) for placebo is the same as the population proportion \(p_{2}\) for aspirin. The sample proportions were \(\hat{p}_{1}=347 / 11535=0.0301\) and \(\hat{p}_{2}=327 / 14035=0.0233 .\) a. For testing \(\mathrm{H}_{0}: p_{1}=p_{2}\) against \(\mathrm{H}_{a}: p_{1} \neq p_{2},\) show that the pooled estimate of the common value \(p\) under \(\mathrm{H}_{0}\) is \(\hat{p}=0.026\) and the standard error is 0.002 . b. Show that the test statistic is \(z=3.4\). c. Find and interpret the P-value in context.

A Danish study of individuals born at a Copenhagen hospital between 1959 and 1961 reported higher mean IQ scores for adults who were breast-fed for longer lengths of time as babies (E. Mortensen et al., \(J A M A,\) vol. \(287,2002,\) pp. \(2365-2371\) ). The mean IQ score was \(98.1(s=15.9)\) for the \(272 \mathrm{sub}\) jects who had been breast-fed for no longer than a month and \(108.2(s=13.1)\) for the 104 subjects who had been breast-fed for seven to nine months. a. With software that can analyze summarized data, use an inferential method to analyze whether the corresponding population means differ, assuming the population standard deviations are equal. Interpret. b. Was this an experimental or an observational study? Can you think of a potential lurking variable?

Suppose that a \(99 \%\) confidence interval for the difference \(p_{1}-p_{2}\) between the proportions of men and women in California who are alcoholics equals \((0.02,0.09) .\) Choose the best correct choice. a. We are \(99 \%\) confident that the proportion of alcoholics is between 0.02 and 0.09 . b. We are \(99 \%\) confident that the proportion of men in California who are alcoholics is between 0.02 and 0.09 larger than the proportion of women in California who are. c. We can conclude that the population proportions may be equal. d. We are \(99 \%\) confident that a minority of California residents are alcoholics. e. Since the confidence interval does not contain \(0,\) it is impossible that \(p_{1}=p_{2}\)

Multiple choice: Sample size and significance If the sample proportions in Example 4 comparing cancer death rates for aspirin and placebo had sample sizes of only 1000 each, rather than about 11,000 each, then the \(95 \%\) confidence interval for \(\left(p_{1}-p_{2}\right)\) would be (-0.007,0.021) rather than \((0.003,0.011) .\) This reflects that a. When an effect is small, it may take very large samples to have much power for establishing statistical significance. b. Smaller sample sizes are preferable because there is more of a chance of capturing 0 in a confidence interval. c. Confidence intervals get wider when sample sizes get larger. d. The confidence interval based on small sample sizes must be in error because it is impossible for the parameter to take a negative value.

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