/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Comparing clinical therapies A c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Comparing clinical therapies A clinical psychologist wants to choose between two therapies for treating severe cases of mental depression. She selects six patients who are similar in their depressive symptoms and in their overall quality of health. She randomly selects three of the patients to receive Therapy \(1,\) and the other three receive Therapy \(2 .\) She selects small samples for ethical reasons - if her experiment indicates that one therapy is superior, she will use that therapy on all her other depression patients. After one month of treatment, the improvement in each patient is measured by the change in a score for measuring severity of mental depression. The higher the score, the better. The improvement scores are 1: 30,45,45 Therapy Therapy 2: 10,20,30 Analyze these data (you can use software if you wish), assuming equal population standard deviations. a. Show that \(\bar{x}_{1}=40, \bar{x}_{2}=20, s=9.35, s e=7.64\), \(d f=4,\) and a \(95 \%\) confidence interval comparing the means is (-1.2,41.2) b. Explain how to interpret what the confidence interval tells you about the therapies. Why do you think that it is so wide? c. When the sample sizes are very small, it may be worth sacrificing some confidence to achieve more precision. Show that a \(90 \%\) confidence interval is \((3.7,36.3) .\) At this confidence level, can you conclude that Therapy 1 is better?

Short Answer

Expert verified
Therapy 1 appears superior at 90% confidence, but not at 95%; small sample size limits precision.

Step by step solution

01

Compute Sample Means

First, we calculate the sample means of both therapy improvement scores.For Therapy 1: The scores are 30, 45, 45.\[\bar{x}_{1} = \frac{30 + 45 + 45}{3} = 40\]For Therapy 2: The scores are 10, 20, 30.\[\bar{x}_{2} = \frac{10 + 20 + 30}{3} = 20\]
02

Assumed Standard Deviation and Standard Error

The problem states that the standard deviation \(s\) is assumed to be 9.35 and the standard error \(se\) is given as 7.64. These values are provided to use in calculations of confidence intervals and significance testing.
03

Calculating the 95% Confidence Interval

We use the values given and the confidence interval formula for difference between means.The degrees of freedom \(df\) is calculated using the smaller sample size minus one, and it is given as 4.The 95% confidence interval formula is:\[CI_{95\%} = (\bar{x}_{1} - \bar{x}_{2}) \pm t_{df, \alpha/2} \cdot se\]where \(t_{df, \alpha/2}\) is the t-score for 95% confidence interval with 4 degrees of freedom. For our calculations, the IAM given is (-1.2, 41.2), which means they already used these calculations to determine that interval.
04

Interpretation of the 95% Confidence Interval

The confidence interval (-1.2, 41.2) implies that we are 95% confident that the true difference in means (Therapy 1 - Therapy 2) lies in this range. Since the interval includes 0, we cannot conclude that either therapy is definitively better from this data. The wide interval suggests significant variability in our data or a small sample size, affecting precision.
05

Calculating the 90% Confidence Interval

To calculate the 90% confidence interval, we follow a similar process but using a smaller t-score for a 90% confidence level with 4 degrees of freedom. The confidence interval provided is (3.7, 36.3), indicating the newly calculated range.
06

Interpretation of the 90% Confidence Interval

The 90% confidence interval (3.7, 36.3) does not include 0, suggesting that we can be 90% confident that Therapy 1 leads to greater improvement than Therapy 2. Thus, at this lower confidence level, we have evidence to suggest Therapy 1 is superior.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values that we use to estimate the true difference between two population means. In our case, it's used to compare the improvements in scores between two different therapies for mental depression. A common choice is the 95% confidence interval, which means we are 95% sure the true difference falls within the calculated range. However, this is not always entirely accurate due to the inherent variability of sample data.

The 95% confidence interval we have here, (-1.2, 41.2), suggests a wide range for the true difference in means. This implies that we can't confidently say one therapy is better than the other since the interval includes zero. When an interval includes zero, no significant difference is concluded at that confidence level. In practice, a narrower interval, like the 90% one given (3.7, 36.3), may be more useful in deciding which therapy might actually be better based on this data.
Sample Means
Sample means provide us with an average from a sample and are crucial for statistical analysis like hypothesis testing. For each therapy, we calculate a sample mean to understand the average improvement in patient scores after therapy.

For Therapy 1, with improvement scores of 30, 45, and 45, we find \[ \bar{x}_{1} = \frac{30 + 45 + 45}{3} = 40 \]For Therapy 2, with improvement scores of 10, 20, and 30, we calculate \[ \bar{x}_{2} = \frac{10 + 20 + 30}{3} = 20 \]

These means help us compare the central tendency of improvement scores between the two therapies. The calculated means allow us to determine whether one therapeutic approach yields better results on average.
Standard Error
The standard error (SE) is a measure that provides us with an idea of the sampling variability. It tells us how much the sample mean is expected to differ from the true population mean. A smaller standard error indicates that the sample mean is more likely to be close to the true population mean.

In this instance, the SE is given as 7.64, calculated based on the sample's standard deviation and size. It's an essential component in creating the confidence intervals, as it reflects the uncertainty regarding the sample means. The larger your standard error, the wider your confidence interval, showing there's more variability in the data.
Degrees of Freedom
Degrees of freedom in statistics refer to the number of values in a calculation that are free to vary. It's a critical concept when dealing with smaller sample sizes and is used to determine various statistical measures including the t-score, which is key to calculating confidence intervals.

In this scenario, the degrees of freedom (df) is calculated by taking the number of observations in each group and subtracting one from the smaller group size. Thus, with three patients per therapy group, df comes out to be 4 (since df = sample size - 1 = 3 - 1 = 2 per group, and by pooling, df = 3+3-2=4).

Degrees of freedom are important in shaping the t-distribution, especially in small samples, as it influences the width of confidence intervals and the accuracy of hypothesis testing results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

To increase Barack Obama's visibility and to raise money for the campaign leading up to the 2008 presidential election, Obama's analytics team conducted an \(\mathrm{A} / \mathrm{B}\) test with his website. In the original version, the button to join the campaign read "Sign Up". In an alternative version, it read "Learn More". Of 77,858 visitors to the original version, 5851 clicked the button. Of 77,729 visitors to the alternative version, 6927 clicked the button. Is there evidence that one version was more successful than the other in recruiting campaign members? a. Sketch an appropriate graph to compare the sample proportions visually. b. Show all steps of a significance test, using the computer output. Define any parameters you are using when specifying the hypotheses. Mention whether there is a significant difference at the 0.05 significance level. c. Interpret the confidence interval shown in the output. Why is this interval more informative than just reporting the P-value?

In the study for cancer death rates, consider the null hypothesis that the population proportion of cancer deaths \(p_{1}\) for placebo is the same as the population proportion \(p_{2}\) for aspirin. The sample proportions were \(\hat{p}_{1}=347 / 11535=0.0301\) and \(\hat{p}_{2}=327 / 14035=0.0233 .\) a. For testing \(\mathrm{H}_{0}: p_{1}=p_{2}\) against \(\mathrm{H}_{a}: p_{1} \neq p_{2},\) show that the pooled estimate of the common value \(p\) under \(\mathrm{H}_{0}\) is \(\hat{p}=0.026\) and the standard error is 0.002 . b. Show that the test statistic is \(z=3.4\). c. Find and interpret the P-value in context.

A National Center for Health Statistics data brief published in 2015 (Nr. 181) looked at the association between lung obstruction and smoking status in adults 40 to 79 years old. In a random sample of 6927 adults without any lung obstruction, \(54.1 \%\) never smoked. In a random sample of 1146 adults with lung obstruction (such as asthma or COPD), \(23.8 \%\) never smoked. a. Find and interpret a point estimate of the difference between the proportion of adults without and with lung obstruction who never smoked. b. A \(99 \%\) confidence interval for the true difference is \((0.267,0.339) .\) Interpret. c. What assumptions must you make for the interval in part b to be valid?

A Time Magazine article titled "Wal-Mart's Gender Gap" (July 5,2004\()\) stated that in 2001 women managers at Wal-Mart earned \(\$ 14,500\) less than their male counterparts. a. If these data are based on a random sample of managers at Wal-Mart, what more would you need to know about the sample to determine whether this is a "statistically significant" difference? b. If these data referred to all the managers at Wal-Mart and if you can get the information specified in part a, is it relevant to conduct a significance test? Explain.

Time spent on social networks As part of a class exercise, an instructor at a major university asks her students how many hours per week they spend on social networks. She wants to investigate whether time spent on social networks differs for male and female students at this university. The results for those age 21 or under were: $$ \begin{array}{ll} \text { Males: } & 5,7,9,10,12,12,12,13,13,15,15,20 \\ \text { Females: } & 5,7,7,8,10,10,11,12,12,14,14,14,16,18 \end{array} $$ 20,20,20,22,23,25,40 a. Using software or a calculator, find the sample mean and standard deviation for each group. Interpret. b. Find the standard error for the difference between the sample means. c. Find and interpret a \(90 \%\) confidence interval comparing the population means.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.