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How often feel sad? Refer to the previous exercise. This question was asked of 10 students in a class at the University of Wisconsin recently. The responses were $$ 0,0,1,0,7,2,1,0,0,3 $$ Find and interpret a \(90 \%\) confidence interval for the population mean, and indicate what you would have to assume for this inference to apply to the population of all University of Wisconsin students.

Short Answer

Expert verified
The 90% confidence interval for the mean is (0.43, 2.37). Assume the sample is random and representational of the population.

Step by step solution

01

Organize the Data

Start by organizing the data from the student responses: \(0, 0, 1, 0, 7, 2, 1, 0, 0, 3\). Count 10 responses.
02

Calculate the Sample Mean

To find the sample mean (\(\bar{x}\)), sum all the data values and divide by the number of data points: \(\bar{x} = \frac{0+0+1+0+7+2+1+0+0+3}{10} = \frac{14}{10} = 1.4\).
03

Calculate the Sample Standard Deviation

First, find each data point's deviation from the mean, square it, sum these squared deviations, and divide by \(n-1\) (degrees of freedom). Calculate the square root of this result to get the standard deviation \(s\): \[s = \sqrt{\frac{(0-1.4)^2+(0-1.4)^2+\cdots+(3-1.4)^2}{10-1}} = \sqrt{\frac{1.96+1.96+0.16+1.96+31.36+0.36+0.16+1.96+1.96+2.56}{9}} = \sqrt{2.24} \approx 1.673\].
04

Determine the t-Value for Confidence Interval

Use a t-distribution table to find the t-value for a 90% confidence level with \(n-1\) degrees of freedom (\(n = 10\), so \(df = 9\)). The t-value is approximately 1.833.
05

Calculate the Margin of Error

Calculate the margin of error (ME) using the formula: \(ME = t \cdot \frac{s}{\sqrt{n}}\). Plugging in the values: \[ME = 1.833 \cdot \frac{1.673}{\sqrt{10}} = 1.833 \cdot 0.529 = 0.970\].
06

Compute the Confidence Interval

Use the sample mean and margin of error to construct the confidence interval: \[CI = \text{mean} \pm \text{ME} = 1.4 \pm 0.970\]. This gives the interval \(1.4 - 0.970\) to \(1.4 + 0.970\), or \(0.43\) to \(2.37\).
07

Interpret the Results

The 90% confidence interval for the population mean is between \(0.43\) and \(2.37\). This means we are 90% confident that the average number of times students at the University of Wisconsin feel sad per reference period lies within this range. For this inference to apply to the broader population of all students at the university, we assume the sample is random and representative of this population, and that the response is normally distributed or the sample size is sufficiently large.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is a fundamental concept in statistics. It provides a single value summary of a data set, offering a measure of the central tendency. In the context of our exercise, the sample mean was calculated from the responses of 10 students regarding how often they feel sad.
To find the sample mean (\(\bar{x}\)), you sum up all the data points and divide by the number of points. For our data, it was computed as follows:
  • Sum of responses: 0 + 0 + 1 + 0 + 7 + 2 + 1 + 0 + 0 + 3 = 14
  • Number of responses: 10
  • Sample mean: \(\bar{x} = \frac{14}{10} = 1.4\)
This sample mean of 1.4 provides an average estimate of how often these students feel sad within the context of our study.
Standard Deviation
Standard deviation is a measure of the dispersion or spread in a set of data. It tells us how much the data values deviate from the mean on average. In simple terms, it shows how spread out the numbers are in a dataset.
Calculating the sample standard deviation involves several steps:
  • Find the deviation of each data point from the sample mean.
  • Square these deviations to remove negative values.
  • Sum the squared deviations and divide by \(n-1\), where \(n\) is the number of data points.
  • Take the square root of the result.
In the given exercise, the sample standard deviation was approximately 1.673. This value indicates variability in students' responses about feeling sad compared to the mean.
t-Distribution
The t-distribution is an essential concept used when estimating population parameters with a smaller sample size (\(n < 30\)). It accounts for the increased variability inherent in small samples. The shape is similar to a normal distribution but has heavier tails.
For constructing a confidence interval, we use a t-value derived from the t-distribution. This value depends on the desired level of confidence and the degrees of freedom (\(df\), calculated as \(n - 1\)). In this exercise, with \(df = 9\) for 10 data points and a 90% confidence level, the corresponding t-value is approximately 1.833.
This t-value is crucial in determining how much uncertainty there is in our sample mean estimation.
Margin of Error
The margin of error quantifies the uncertainty in our estimate of the population parameter, based on the sample. It's the range above and below the sample mean that the true population mean is expected to fall into with a specified confidence level.
In the context of our exercise, the margin of error (\(ME\)) is calculated using the formula: \(ME = t \cdot \frac{s}{\sqrt{n}}\).
  • \(t\) is the t-value from the t-distribution table.
  • \(s\) is the sample standard deviation.
  • \(n\) is the number of observations.
With our numbers, the margin of error was about 0.970. Adding and subtracting this from the sample mean of 1.4 gives the confidence interval. This implies we are quite sure the true population mean lies in this interval, accounting for the uncertainty.

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