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Exit poll with smaller sample In the previous exercise, suppose the same proportions resulted from \(n=140\) (instead of 1400 ), with counts 66 and 74 . a. Now does a \(95 \%\) confidence interval allow you to predict the winner? Explain. b. Explain why the same proportions but with smaller samples provide less information. (Hint: What effect does \(n\) have on the standard error?)

Short Answer

Expert verified
a. No, overlapping intervals prevent a clear prediction. b. Smaller samples increase standard error, reducing precision.

Step by step solution

01

Calculate Proportion

We have a sample of 140 with counts 66 and 74. First, calculate the proportion of the sample for each candidate. \[ p_1 = \frac{66}{140} \approx 0.471 \] \[ p_2 = \frac{74}{140} \approx 0.529 \]
02

Calculate Standard Error

To find the standard error for the proportion, first find the pooled proportion: \[ \hat{p} = \frac{66 + 74}{140} = 1 \] Since the proportions sum to 1, take one of the proportions: \[ SE = \sqrt{\frac{p_1(1-p_1)}{n}} = \sqrt{\frac{0.471 \times 0.529}{140}} \approx 0.042 \]
03

Determine Margin of Error

The margin of error for a 95% confidence interval is calculated as \( ME = Z \times SE \), where \( Z \approx 1.96 \) for a 95% confidence interval. \[ ME = 1.96 \times 0.042 \approx 0.082 \]
04

Calculate Confidence Interval

Using the margin of error, compute the 95% confidence interval for the proportion. \[ CI = p_1 \pm ME = 0.471 \pm 0.082 \] \[ CI = (0.389, 0.553) \] For \( p_2 \), it is just the complement: \[ CI = (0.447, 0.611) \]
05

Interpret Confidence Interval

Since the confidence intervals \((0.389, 0.553)\) for \( p_1 \) and \((0.447, 0.611)\) for \( p_2 \) overlap, they do not allow us to clearly predict the winner.
06

Impact of Sample Size on Information

The sample size \( n \) affects the standard error: \( SE = \sqrt{\frac{p(1-p)}{n}} \). A larger sample size reduces \( SE \), resulting in a narrower confidence interval, which provides a more precise estimate of the population parameter. A smaller sample, like \( n=140 \), results in a wider interval and less confidence in the estimated proportion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
When conducting surveys or research, the "sample size" refers to the number of observations or data points collected in the study. In the context of polls or experiments, a larger sample size is typically desirable for several reasons.
The main benefits include:
  • Reduced Random Error: With more data points, the effect of random fluctuations is minimized, providing results that are closer to the true population parameter.
  • Greater Precision: Larger samples yield tighter (smaller) confidence intervals, enabling more exact predictions and conclusions.
  • Increased Representativeness: Bigger samples can better reflect the diversity of the larger population, reducing biases.
Conversely, a smaller sample size, like in the example where we only have 140 respondents, limits the accuracy and precision of the findings. This is because each data point carries more weight in determining the overall results, potentially skewing the analysis with any outliers or anomalies. Thus, when the sample size is small, conclusions drawn from the data should be handled with caution, especially in predicting outcomes such as election results.
Standard Error
The "standard error" is a critical component in statistical analysis, particularly when dealing with estimates of population parameters, such as means or proportions.
It measures the variability or dispersion of the sample statistics (like the sample mean or proportion) from the actual population parameter.
Two key points regarding standard error are:
  • Dependence on Sample Size: The standard error decreases as the sample size increases. This is because more data provides a clearer picture of the population, leading to less uncertainty. Mathematically, it is depicted as: \[ SE = \sqrt{\frac{p(1-p)}{n}} \]where \( p \) is the sample proportion and \( n \) is the sample size.
  • Role in Confidence Intervals: The standard error is used to calculate the margin of error in confidence intervals. Smaller standard errors lead to narrower, more precise intervals, while larger standard errors result in wider intervals.
By understanding standard error, you gain insight into the reliability of your sample statistics. Smaller standard errors indicate the sample statistic is a closer approximation to the true population parameter, enhancing the overall confidence in the results.
Margin of Error
The "margin of error" is an essential statistic that provides a range around the sample estimate, accounting for sampling variability.
It helps convey the potential error or uncertainty when generalizing results from a sample to the entire population.
  • Calculation: The margin of error is determined by multiplying the standard error by a critical value (often represented as \( Z \) score) from a normal distribution. For a 95% confidence interval, the \( Z \) score is typically 1.96.
  • Interpretation: A margin of error informs us how far the sample proportion could reasonably be from the true population proportion. In the poll exercise, the margin of error for a 95% confidence interval is \( ME = 1.96 \times 0.042 \approx 0.082 \).
  • Impact: Larger sample sizes will result in smaller margins of error, providing more confidence in the accuracy of the sample statistic.
Understanding the margin of error is crucial when interpreting confidence intervals. It encapsulates the uncertainty and variability in estimates, offering a clear picture of the potential range for the true population parameter. Thus, whenever we see poll results with a noted margin of error, it indicates the range within which the actual number might fall.

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Most popular questions from this chapter

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