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Multiple choice: CI property 2 Other things being equal, increasing \(n\) causes the margin of error of a confidence interval to (a) increase, (b) decrease, (c) stay the same.

Short Answer

Expert verified
(b) The margin of error decreases as \( n \) increases.

Step by step solution

01

Understanding the Confidence Interval

The confidence interval provides a range of values that is likely to contain the population parameter. It is usually expressed as the estimate ± margin of error.
02

Formula for Margin of Error

The margin of error in a confidence interval for a population mean can typically be calculated as \( z \times \left(\frac{\sigma}{\sqrt{n}}\right) \), where \( z \) is the z-score, \( \sigma \) is the population standard deviation, and \( n \) is the sample size.
03

Effect of Increasing n

Increasing \( n \), the sample size, affects the margin of error. As \( n \) increases, the denominator \( \sqrt{n} \) increases, which makes \( \frac{\sigma}{\sqrt{n}} \) smaller, thus reducing the margin of error.
04

Conclusion Based on Relationship

Since the margin of error is inversely proportional to \( \sqrt{n} \), as \( n \) increases, the margin of error decreases. Therefore, the correct choice is (b) decrease.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error is a critical concept in statistics, particularly when it comes to confidence intervals. It represents the extent of variability or uncertainty in the sample estimate of a population parameter, such as the mean. The formula for calculating the margin of error for a confidence interval is typically given by \( z \times \left(\frac{\sigma}{\sqrt{n}}\right) \).
This formula includes several components:
  • \( z \): the z-score, which corresponds to the desired confidence level, such as 95% or 99%.
  • \( \sigma \): the population standard deviation, indicating how much individual values vary in the population.
  • \( \sqrt{n} \): the square root of the sample size, where \( n \) represents the number of observations in your sample.
By understanding this formula, you can see how changes in these variables affect the margin of error. Particularly, an increase in the sample size \( n \) results in a decrease in the margin of error, providing a more precise estimate of the population parameter.
Sample Size
Sample size, denoted as \( n \), plays a significant role in determining the accuracy of statistical estimates. It refers to the number of observations or subjects included in the sample drawn from a population.
The larger the sample size, the more data points you have, creating a more representative snapshot of the entire population. This is because a larger sample size helps to better average out the variability and anomalies that might exist.
In the context of confidence intervals, increasing the sample size has a direct effect on the margin of error. As \( n \) increases, \( \sqrt{n} \) also increases, lowering the term \( \frac{\sigma}{\sqrt{n}} \). Consequently, this leads to a narrower confidence interval, implying more precision in estimating the population parameter. This beneficial property highlights why researchers often aim to have a larger sample size when feasible.
Population Parameter
A population parameter is a value that describes an entire population. It's a fixed number but often unknown because measuring an entire population directly is challenging. Instead, we rely on sample statistics to estimate these parameters.
Common examples of population parameters include:
  • The population mean (average).
  • The population proportion (frequency of a certain characteristic).
  • The population standard deviation (variability within the population).

Estimating a population parameter accurately is the ultimate goal of statistical inference. By constructing a confidence interval from sample data, one can determine a range in which it is likely this unknown population parameter lies. This method allows us to make informed guesses about the population based on a smaller, more manageable subset.
Z-Score
A z-score is a statistical measurement that describes a value's relation to the mean of a group of values. It is measured in terms of standard deviations from the mean.
Z-scores are pivotal in calculating the margin of error for confidence intervals. The z-score corresponds to the level of confidence you want in your estimates, like 90%, 95%, or 99%. Each of these confidence levels has a designated z-value, which you can find in z-tables or by using statistical software.
The role of the z-score in the margin of error is to adjust it according to how confident you wish to be. For example, a higher confidence level (like 99%) requires a larger z-score, which in turn increases the margin of error. This reflects the trade-off between confidence in your interval and its precision. Understanding z-scores helps you balance certainty against specificity when making predictions about a population.

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Most popular questions from this chapter

Alleviate PMS? A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first stages of a clinical trial, it was successful for 7 out of 10 women. a. Construct an appropriate \(95 \%\) confidence interval for the population proportion. b. Is it plausible that it's successful for only half the population? Explain.

For the number of hours of TV watching, the 2008 GSS reported a mean of 2.98 for the 1324 white subjects, with a standard deviation of \(2.66 .\) The mean was 4.38 for the 188 black subjects, with a standard deviation of 3.58 . Analyze these data, preparing a short report in which you mention the methods used and the assumptions on which they are based, and summarize and interpret your findings.

The instructor will assign the class a theme to study. Download recent results for variables relating to that theme from sda.berkeley.edu/GSS. Find and interpret confidence intervals for relevant parameters. Prepare a two-page report summarizing results.

Women's satisfaction with appearance A special issue of Newsweek in March 1999 on women and their health reported results of a poll of 757 American women aged 18 or older. When asked, "How satisfied are you with your overall physical appearance?" \(30 \%\) said very satisfied, \(54 \%\) said somewhat satisfied, \(13 \%\) said not too satisfied, and \(3 \%\) said not at all satisfied. True or false: Since all these percentages are based on the same sample size, they all have the same margin of error.

t-scores a. Show how the \(t\) -score for a \(95 \%\) confidence interval changes as the sample size increases from 10 to 20 to 30 to infinity. b. What does the answer in part a suggest about how the \(t\) distribution compares to the standard normal distribution?

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