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Number of sex partners \(\quad\) According to recent General Social Surveys, in the United States the population distribution for adults of \(X=\) number of sex partners in the past 12 months has a mean of about 1.0 and a standard deviation of about 1.0 . a. Does \(X\) have a normal distribution? Explain. b. For a random sample of 100 adults, describe the sampling distribution of \(\bar{x}\) and give its mean and standard deviation. What is the effect of \(X\) not having a normal distribution?

Short Answer

Expert verified
a. X is not normally distributed; it is skewed. b. The sampling distribution of \( \bar{x} \) is approximately normal with mean 1.0 and standard deviation 0.1.

Step by step solution

01

Evaluate Normality

The distribution of the number of sex partners for adults, described by X, is not normally distributed. The mean and the standard deviation equal to one, alongside the nature of categorical data like number of partners, typically indicate a skewed distribution.
02

Central Limit Theorem

Even though the original distribution of X is not normal, the Central Limit Theorem states that for a large sample size (n=100 in this case), the sampling distribution of the sample mean \( \bar{x} \) will approximate a normal distribution.
03

Describe the Sampling Distribution

For a random sample size \( n = 100 \), the sampling distribution of \( \bar{x} \) is approximately normal due to the Central Limit Theorem. The mean of \( \bar{x} \) is the same as the population mean: \( \mu_{\bar{x}} = \mu = 1.0 \).
04

Calculate the Standard Deviation of \( \bar{x} \)

The standard deviation of \( \bar{x} \), also known as the standard error, is given by \( \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \). Substituting the given values, \( \sigma_{\bar{x}} = \frac{1.0}{\sqrt{100}} = 0.1 \).
05

Effect of Non-normality

The fact that X is not normally distributed does not significantly affect the sampling distribution of the mean due to the sample size being large enough (n=100). The distribution of \( \bar{x} \) is still approximately normal by the Central Limit Theorem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Distribution
A sampling distribution is a way to understand how a sample statistic behaves when we take multiple samples from the same population. Instead of just looking at individual data points or a single sample, researchers focus on a sample's overall behavior.

When we refer to the sampling distribution of the sample mean \( \bar{x} \), we are talking about how the average of a sample tends to behave. According to the Central Limit Theorem, even if our original data (like the number of sex partners) does not follow a normal distribution, the distribution of the sample mean \( \bar{x} \) will approximate normality if the sample size is large enough.

In our exercise, with a sample size of 100, this approximation holds true, allowing us to predict the characteristics of the mean from any given random sample. The key takeaway is that, due to the Central Limit Theorem, sampling distributions provide a powerful tool to make predictions about population parameters based on sample data.
Standard Deviation
Standard deviation is a measure of how spread out numbers in a data set are. It tells us how much variation or dispersion there is from the average (mean). In simple terms, it shows how much individual data points differ from the mean of the data set.

In the context of sampling distributions, the standard deviation of the sample mean \( \bar{x} \) is often referred to as the standard error. For our problem, it's important to note that while the standard deviation of the population data \( X \) is 1.0, the standard error \( \sigma_{\bar{x}} \) is different due to the effect of sampling.

The standard error is calculated as \( \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the population standard deviation, and \( n \) is the sample size. This formula helps us understand that as the sample size increases, the standard error decreases, making our estimates more precise. For a sample size of 100, the standard error becomes 0.1, indicating the average sample mean will be very close to the true population mean.
Normal Distribution
A normal distribution is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. It's often referred to as a bell curve due to its shape.

In statistics, the normal distribution is critically important for several reasons. It simplifies the analysis since it has properties that allow for easy predictions about the data. Even though our original data regarding the number of sex partners doesn't follow a normal distribution, by the Central Limit Theorem, the sampling distribution of the sample mean will be approximately normal if the sample size is large enough.

For a sample size of 100, the distribution of the sample mean \( \bar{x} \) resembles a normal distribution, meaning we can apply normal probability models to make inferences. This allows statisticians to use z-scores and other tools to gauge probabilities and make decisions based on the sample data, despite the data itself originating from a non-normal distribution.

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Most popular questions from this chapter

Income of farm workers For the population of farm workers in New Zealand, suppose that weekly income has a distribution that is skewed to the right with a mean of \(\mu=\$ 500(\mathrm{~N} . Z .)\) and a standard deviation of \(\sigma=\$ 160 .\) A researcher, unaware of these values, plans to randomly sample 100 farm workers and use the sample mean annual income \(\bar{x}\) to estimate \(\mu\). a. Show that the standard deviation of \(\bar{x}\) equals 16.0 . b. Explain why it is almost certain that the sample mean will fall within \(\$ 48\) of \(\$ 500\). c. The sampling distribution of \(\bar{x}\) provides the probability that \(\bar{x}\) falls within a certain distance of \(\mu,\) regardless of the value of \(\mu\). Show how to calculate the probability that \(\bar{x}\) falls within \(\$ 20\) of \(\mu\) for all such workers. (Hint: Using the standard deviation, convert the distance 20 to a \(z\) -score for the sampling distribution.)

Education of the self-employed According to a recent Current Population Reports, the population distribution of number of years of education for self- employed individuals in the United States has a mean of 13.6 and a standard deviation of 3.0 . a. Identify the random variable \(X\) whose population distribution is described here. b. Find the mean and standard deviation of the sampling distribution of \(\bar{x}\) for a random sample of size 100 . Interpret the results. c. Repeat part b for \(n=400 .\) Describe the effect of increasing \(n\).

True or false \(\quad\) As the sample size increases, the standard deviation of the sampling distribution of \(\bar{x}\) increases. Explain your answer.

Standard deviation of a proportion Suppose \(x=1\) with probability \(p,\) and \(x=0\) with probability \((1-p) .\) Then, \(x\) is the special case of a binomial random variable with \(n=1,\) so that \(\sigma=\sqrt{n p(1-p)}=\sqrt{p(1-p)} .\) With \(n\) trials, using the formula \(\sigma / \sqrt{n}\) for a standard deviation of a sample mean, explain why the standard deviation of a sample proportion equals \(\sqrt{p(1-p) / n}\)

Purpose of sampling distribution You'd like to estimate the proportion of all students in your school who are fluent in more than one language. You poll a random sample of 50 students and get a sample proportion of 0.12. Explain why the standard deviation of the sampling distribution of the sample proportion gives you useful information to help gauge how close this sample proportion is to the unknown population proportion.

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