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For a normal distribution, use Table A, software, or a calculator to find the probability that an observation is a. at least 1 standard deviation above the mean. b. at least 1 standard deviation below the mean. c. In each case, sketch a curve and show the tail probability.

Short Answer

Expert verified
a: 0.1587, b: 0.1587; both can be shown using a normal curve with shaded tails.

Step by step solution

01

Understanding the Problem

We need to find the probabilities that a variable from a standard normal distribution is at least 1 standard deviation above and below the mean. This involves using the standard normal distribution table or software to find the tail probabilities for these scenarios.
02

Identifying the Standard Scores

For a standard normal distribution, the z-score formula is used. The z-score for being 1 standard deviation above the mean is 1, and the z-score for being 1 standard deviation below the mean is -1.
03

Using the Z-table for at least 1 Standard Deviation Above the Mean

Look up the z-score of 1 in the standard normal distribution table. The table gives the area to the left of z = 1, which is 0.8413. To find the area to the right (at least 1 SD above), calculate 1 - 0.8413 = 0.1587.
04

Probability for 1 Standard Deviation Below the Mean

Using symmetry of the normal distribution, the probability of being at least 1 standard deviation below the mean is the same as being at least 1 standard deviation above the mean, which is also 0.1587.
05

Checking Results with a Distribution Curve Sketch

Sketch a standard normal distribution curve and shade the right tail starting at z = 1 to represent part (a) and the left tail starting at z = -1 for part (b). This provides a visual confirmation of the probabilities found.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
Understanding the Z-score is key to navigating problems involving the Standard Normal Distribution. The Z-score converts different data points into a standard form, showing how far a point is from the mean in terms of standard deviations.
  • To calculate a Z-score, use the formula: \( z = \frac{(X - \mu)}{\sigma} \), where \( X \) is the value, \( \mu \) is the mean, and \( \sigma \) is the standard deviation.
  • A Z-score of 1 indicates a value 1 standard deviation above the mean. Conversely, a Z-score of -1 indicates a value 1 standard deviation below the mean.
Z-scores help us standardize different datasets, making them comparable on a broader level. In our exercise, understanding Z-scores allows us to use standard normal distribution tables to find probabilities associated with specific data points.
Standard Deviation
The standard deviation is a measure that tells us how spread out the data is around the mean. It's a crucial concept in statistics, particularly in the context of normal distributions.
  • A smaller standard deviation means that data points tend to be closer to the mean.
  • A larger standard deviation indicates that the data is more spread out.
In a standard normal distribution, the mean is 0, and the standard deviation is 1. This gives us a benchmark to understand how far or close observations are in terms of standard deviations. By knowing the standard deviation, one can quickly determine where an observation lies within a data set by using the Z-score.
Probability Table
A Probability Table, specifically the Z-table or Standard Normal Distribution Table, helps us find the area under the curve of a normal distribution. This area represents probability and is essential in determining the likelihood of a given observation.
  • The Z-table lists cumulative probabilities, which are the probabilities that a random variable is less than a particular Z-score.
  • To find an area to the right of a Z-score, subtract the cumulative probability from 1.
For instance, in the exercise, finding the probability of a variable being at least 1 standard deviation above the mean involves looking up the Z-score of 1. The table gives a cumulative probability of 0.8413. Therefore, the probability of being at least 1 standard deviation above is \( 1 - 0.8413 = 0.1587 \). This process is repeated for other Z-scores to find probabilities of different observations.
Tail Probability
Tail Probability refers to the probability of a variable falling into the "tails" of a probability distribution, which are the extreme ends on either side. In the context of a standard normal distribution, we're interested in how often data points land more than a certain number of standard deviations away from the mean.
  • The right tail probability is found by looking beyond a positive Z-score.
  • The left tail probability looks beyond a negative Z-score.
In the exercise, to determine the probability of an observation being at least 1 standard deviation from the mean, whether above or below, tail probabilities are calculated. Using the symmetry of the normal distribution, both tail probabilities for Z-scores of 1 and -1 are the same, each yielding a probability of 0.1587. Sketching a curve with shaded tails offers a powerful visual to solidify understanding.

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Most popular questions from this chapter

A new roller coaster at an amusement park requires individuals to be at least \(4^{\prime} 8^{\prime \prime}\) (56 inches) tall to ride. It is estimated that the heights of 10-year-old boys are normally distributed with \(\mu=54.5\) inches and \(\sigma=4.5\) inches. a. What proportion of 10 -year-old boys is tall enough to ride the coaster? b. A smaller coaster has a height requirement of 50 inches to ride. What proportion of 10 year-old-boys is tall enough to ride this coaster? c. What proportion of 10 -year-old boys is tall enough to ride the coaster in part b but not tall enough to ride the coaster in part a?

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Move first in Monopoly In Monopoly, dice are used to determine which player gets to move first. Suppose there are two players in the game. Each player rolls a die and the player with the higher number gets to move first. If the numbers are the same, the players roll again. a. Using the sample space \(\\{(1,1),(1,2),(1,3),(1,4)\), \((1,5),(1,6),(2,1), \ldots(6,5),(6,6)\\}\) of the 36 equally likely outcomes for the two dice, show that the probability distribution for the maximum of the two numbers is as shown in the table. Hint: For each outcome in the sample space, indicate the value of \(X\) assigned to that outcome. b. Show that the two conditions in the definition of a probability distribution are satisfied.

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