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For a family with two children, let A denote \\{first child is female\\}, let B denote (at least one child is female\\}, and let \(C\) denote \\{both children are female\\}. a. Show that \(\mathrm{P}(\mathrm{C} \mid \mathrm{A})=1 / 2\). b. Are \(A\) and \(C\) independent events? Why or why not? c. Find \(\mathrm{P}(\mathrm{C} \mid \mathrm{B})\). d. Describe what makes \(\mathrm{P}(\mathrm{C} \mid \mathrm{A})\) different than \(\mathrm{P}(\mathrm{C} \mid \mathrm{B})\).

Short Answer

Expert verified
a. \(\mathrm{P}(C \mid A) = \frac{1}{2}\). b. Not independent. c. \(\mathrm{P}(C \mid B) = \frac{1}{3}\). d. \(\mathrm{P}(C \mid A)\) > \(\mathrm{P}(C \mid B)\).

Step by step solution

01

Define and List All Possible Outcomes

List the possible outcomes for the gender of two children: \{FF, FM, MF, MM\}, where F represents female and M represents male. Each has an equal probability of \(\frac{1}{4}\).
02

Calculate \(\mathrm{P}(C \mid A)\)

Given event \(A\), where the first child is female, the possible outcomes are \{FF, FM\}. Event \(C\), both children are female, only matches outcome \{FF\}. Therefore, \(\mathrm{P}(C \mid A) = \frac{1}{2}\), as there are 2 outcomes, and only 1 outcome satisfies \(C\).
03

Determine Independence of \(A\) and \(C\)

Two events \(A\) and \(C\) are independent if \(\mathrm{P}(C \mid A) = \mathrm{P}(C)\). We know \(\mathrm{P}(C \mid A) = \frac{1}{2}\). Calculate \(\mathrm{P}(C) = \frac{1}{4}\) because there is one favorable outcome (FF) among four. Since \(\frac{1}{2} eq \frac{1}{4}\), \(A\) and \(C\) are not independent.
04

Calculate \(\mathrm{P}(C \mid B)\)

In event \(B\), at least one child is female, the possible outcomes are \{FF, FM, MF\}. Event \(C\), both children are female, aligns with outcome \{FF\}. Therefore, \(\mathrm{P}(C \mid B) = \frac{1}{3}\), as there are 3 outcomes in \(B\), and within them, only 1 satisfies \(C\).
05

Compare \(\mathrm{P}(C \mid A)\) and \(\mathrm{P}(C \mid B)\)

\(\mathrm{P}(C \mid A)\) considers a known first female child, thus limiting options to \{FF, FM\}, leading to a higher probability for \(C\). \(\mathrm{P}(C \mid B)\) only restricts that at least one child be female, allowing more combinations \{FF, FM, MF\}, thus decreasing \(C\)'s probability. Hence, \(\mathrm{P}(C \mid A) = \frac{1}{2}\) is greater than \(\mathrm{P}(C \mid B) = \frac{1}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is an essential mathematical framework used to analyze the likelihood of different outcomes within a given scenario. At its core, it's about quantifying uncertainty. This framework finds application in various fields, including statistics, finance, and genetics. Probability theory concerns itself with both simple occurrences and complex events. A simple event would be the flip of a fair coin, either heads or tails.

More complex events involve multiple stages or conditions, much like in our exercise involving two children and their possible gender combinations. The principle of probability theory helps to determine how likely an event is to happen, given a specific set of circumstances. For example, probability theory tells us that the likelihood of two children both being female can be calculated once we know that the first child is female. By applying probability theory, we can derive conditional probabilities and make more informed decisions based on available data.
Independent Events
Understanding independent events in probability is crucial in determining how different events influence each other. Two events are said to be independent if the occurrence of one event does not affect the occurrence of the other. More formally, events A and C are independent if the probability of C occurring given A has occurred is equal to the probability of C occurring by itself: \(P(C \mid A) = P(C)\).

In our exercise, we consider events A and C, where A is 'the first child is female' and C is 'both children are female'. Through the problem, we determined that \(P(C \mid A) = \frac{1}{2}\), whereas \(P(C) = \frac{1}{4}\). These probabilities are not equal. Therefore, events A and C are not independent, meaning knowing the gender of the first child provides information that impacts the probability of both children being female.
Probability Calculation
Calculating probability involves determining how many favorable outcomes exist compared to the total number of possible outcomes. In problems involving multiple stages or conditions, calculating probability often requires an understanding of conditional probability. Conditional probability specifically refers to the probability of an event occurring given that another event has already occurred.

Take the task of finding the probability that both children in a family are female, given that the first child is female (\(P(C \mid A)\)). Here, with a given first female child, we're left to consider only the outcomes of \{FF, FM\}. Out of these, the potential outcome for both females is just one: \{FF\}. This results in a probability of \(\frac{1}{2}\).
  • Step-by-step calculations ensure accuracy in these problems. Begin by listing all possible outcomes.
  • Evaluate how many meet the event's criteria.
  • Finally, apply the conditional or standard probability rules to render your solution.
Through these steps, probabilities can be calculated precisely, offering insights into how events interrelate and help predict outcomes under various conditions.

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Most popular questions from this chapter

Workers specified as actively disengaged are those who are emotionally disconnected from their work and workplace. A Gallup poll conducted in December \(2010^{5}\) surveyed individuals who were either unemployed or who were actively disengaged in their current position. Individuals were asked to classify themselves as thriving or struggling. The poll reported that \(42 \%\) of the actively disengaged group claimed to be thriving, compared to \(48 \%\) of the unemployed group. a. Are these percentages (probabilities) ordinary or conditional? Explain, by specifying events to which the probabilities refer. b. Of the individuals polled, 1266 were unemployed and 400 were actively disengaged. Create a contingency table showing counts for job status and self- classification. c. Create a tree diagram such that the first branching represents job status and the second branching represent self-classification. Be sure to include the appropriate percentages on each branch.

Current estimates are that about \(25 \%\) of all deaths are due to cancer, and of the deaths that are due to cancer, \(30 \%\) are attributed to tobacco, \(40 \%\) to diet, and \(30 \%\) to other causes. a. Define events, and identify which of these four probabilities refer to conditional probabilities. b. Find the probability that a death is due to cancer and tobacco.

Consider a random number generator designed for equally likely outcomes. Which of the following is not correct, and why? a. For each random digit generated, each integer between 0 and 9 has probability 0.10 of being selected. b. If you generate 10 random digits, each integer between 0 and 9 must occur exactly once. c. If you generated a very large number of random digits, then each integer between 0 and 9 would occur close to \(10 \%\) of the time. d. The cumulative proportion of times that a 0 is generated tends to get closer to 0.10 as the number of random digits generated gets larger and larger.

Pro basketball player Shaquille O'Neal is a poor free-throw shooter. Consider situations in which he shoots a pair of free throws. The probability that he makes the first free throw is \(0.50 .\) Given that he makes the first, suppose the probability that he makes the second is \(0.60 .\) Given that he misses the first, suppose the probability that he makes the second one is 0.40 . a. What is the probability that he makes both free throws? b. Find the probability that he makes one of the two free throws (i) using the multiplicative rule with the two possible ways he can do this and (ii) by defining this as the complement of making neither or both of the free throws. c. Are the results of the free throws independent? Explain.

The digits in \(9 / 11\) add up to \(11(9+1+1)\), American Airlines flight 11 was the first to hit the World Trade Towers (which took the form of the number 11), there were 92 people on board \((9+2=11)\), September 11 is the 254 th day of the year \((2+5+4=11)\), and there are 11 letters in Afghanistan, New York City, the Pentagon, and George W. Bush (see article by L. Belkin, New York Times, August 11,2002 ). How could you explain to someone who has not studied probability that, because of the way we look for patterns out of the huge number of things that happen, this is not necessarily an amazing coincidence?

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