/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Public transportation-center The... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Public transportation-center The owner of a company in downtown Atlanta is concerned about the large use of gasoline by her employees due to urban sprawl, traffic congestion, and the use of energy inefficient vehicles such as SUVs. She'd like to promote the use of public transportation. She decides to investigate how many miles her employees travel on public transportation during a typical day. The values for her 10 employees (recorded to the closest mile) are \(\begin{array}{llll}0 & 0 & 4 & 0\end{array}\) \(\begin{array}{llll}0 & 0 & 10 & 0\end{array}\) 60 a. Find and interpret the mean, median, and mode. b. She has just hired an additional employee. He lives in a different city and travels 90 miles a day on public transport. Recompute the mean and median. Describe the effect of this outlier.

Short Answer

Expert verified
Mean: 7.4, median: 0, mode: 0; new mean: 14.91, new median: 0.

Step by step solution

01

Organize Data

The given data set of public transportation miles for 10 employees is: \(0, 0, 4, 0, 0, 0, 10, 0, 0, 60\). To perform statistical calculations like mean, median, and mode, we need this organized.
02

Calculate the Mean

To find the mean, add all the miles traveled and divide by the number of employees. The sum is \(0 + 0 + 4 + 0 + 0 + 0 + 10 + 0 + 0 + 60 = 74\). The mean is \(\frac{74}{10} = 7.4\) miles per day.
03

Calculate the Median

To find the median, arrange the values in increasing order: \(0, 0, 0, 0, 0, 0, 4, 10, 60\). With 10 numbers, the median is the average of the 5th and 6th numbers: \((0 + 0)/2 = 0\).
04

Calculate the Mode

Mode is the number that appears most frequently. In the set \(0, 0, 4, 0, 0, 0, 10, 0, 0, 60\), '0' appears the most often. Thus, the mode is 0.
05

Recalculate Mean with New Employee

With the new 11th employee traveling 90 miles, the total miles become \(74 + 90 = 164\). The new mean is \(\frac{164}{11} \approx 14.91\) miles per day.
06

Recalculate Median with New Employee

Add the 90 miles to the data set and reorder: \(0, 0, 0, 0, 0, 0, 4, 10, 60, 90\). With 11 numbers, the median is the 6th one, which is '0'.
07

Analyze Effects of the Outlier

The addition of an outlier (90 miles) increased the mean from 7.4 to 14.91, showing sensitivity to extreme values. However, the median (0) remained unchanged, highlighting its resistance to outliers.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
The mean, or average, is a fundamental concept in statistics. To calculate the mean, you simply add up all the values in a dataset and then divide by the number of values in that set.
In the context of our problem, the dataset represents the number of miles employees travel using public transportation per day. For this group of 10 employees, the miles are added up to make 74.
To find the mean, divide this total by the number of employees: \[ \text{Mean} = \frac{74}{10} = 7.4 \text{ miles per day} \] With the introduction of a new employee traveling 90 miles, the new sum becomes 164, resulting in: \[ \text{New Mean} = \frac{164}{11} \approx 14.91 \text{ miles per day} \] The increase in mean highlights how sensitive it is to high-value data entries, illustrating that outliers can significantly shift the mean value.
Median Calculation
The median provides the middle value in a dataset when organized in ascending order. It's a measure of central tendency often used to understand the midpoint of data. For our dataset of 10 values, after sorting, we find the middle position to be between the 5th and 6th values, both being 0: \[ \text{Median} = \frac{0 + 0}{2} = 0 \] After adding the new employee's data, the dataset becomes 11 values long. Thus, we simply take the 6th value in the ordered list for the median: 0. The median remains unaffected by the addition of the new employee's 90-mile travel figure, as it focuses on the middle value rather than the extremes. This robustness against outliers makes it a preferred measure in skewed distributions.
Mode Calculation
The mode is the value that occurs most frequently in a dataset. It's a straightforward measure of central tendency that's useful for categorical data or datasets with repeated values.
In our case, the number '0' appears the most, occurring multiple times: in all, seven times.
This makes '0' the mode. Being the most popular data point, the mode effectively represents the most common outcome for this particular dataset of employee transportation miles.
Outliers
An outlier is a data value that significantly differs from the other values in a dataset. It can skew data-driven analysis and results.
In our data, the initial dataset has a mileage range from 0 to 60. Introducing the employee traveling 90 miles dramatically impacts some statistical measures. Notably, the outlier increased the mean from 7.4 to approximately 14.91, emphasizing its influence on data that relies on the average calculation.
However, concentrating on median and mode helped strip away the distortions caused by outliers. Thus, recognizing outliers helps ensure data interpretations are accurate and reliable.
Data Analysis
Data analysis involves thorough examination of a dataset to extract meaningful insights. For the exercise at hand, we're examining employee travel distance using public transport.
Through calculations of mean, median, and mode, and understanding the impact of outliers, we gain a clearer picture of the dataset. Each statistical measure reveals different insights about the dataset. While mean gives an overall average, the median provides a resistant central point, and the mode shows commonality.
Recognizing outliers and their effects helps refine these insights, allowing better strategic decisions, like promoting public transport to reduce inefficient vehicle use amongst employees. This comprehensive analysis leads to more informed decisions about resource management and company policies.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Household net worth A study reported that in 2007 the mean and median net worth of American families were \(\$ 556,300\) and \(\$ 120,300,\) respectively. a. Is the distribution of net worth for these families likely to be symmetric, skewed to the right, or skewed to the left? Explain. b. During the Great Recession of \(2008,\) many Americans lost wealth due to the large decline in values of assets such as homes and retirement savings. In 2009 , reported mean and median net worth were reported as \(\$ 434,782\) and \(\$ 91,304\). Why do you think the difference in decline from 2007 to 2009 was larger for the mean than the median?

Ways to measure variability The standard deviation, the range, and the interquartile range (IQR) summarize the variability of the data. a. Why is the standard deviation \(s\) usually preferred over the range? b. Why is the IQR sometimes preferred to \(s ?\) c. What is an advantage of \(s\) over the IQR?

Golfers' gains During the 2010 Professional Golfers Association (PGA) season, 90 golfers earned at least \(\$ 1\) million in tournament prize money. Of those, 5 earned at least \(\$ 4\) million, 11 earned between \(\$ 3\) million and \(\$ 4\) million, 21 earned between \(\$ 2\) million and \(\$ 3\) million, and 53 earned between \(\$ 1\) million and \(\$ 2\) million. a. Would the data for all 90 golfers be symmetric, skewed to the left, or skewed to the right? b. Two measures of central tendency of the golfers' winnings were \(\$ 2,090,012\) and \(\$ 1,646,853 .\) Which do you think is the mean and which is the median?

Canadian income According to Statistics Canada, in 2004 the median household income in Canada was \(\$ 58,100\) and the mean was \(\$ 76,100 .\) What would you predict about the shape of the distribution? Why?

Multiple choice: GRE scores In a study of graduate students who took the Graduate Record Exam (GRE), the Educational Testing Service reported that for the quantitative exam, U.S. citizens had a mean of 529 and standard deviation of 127 , whereas the non-U.S. citizens had a mean of 649 and standard deviation of \(129 .\) Which of the following is true? a. Both groups had about the same amount of variability in their scores, but non-U.S. citizens performed better, on the average, than U.S. citizens. b. If the distribution of scores was approximately bell shaped, then almost no U.S. citizens scored below 400 . c. If the scores range between 200 and 800 , then probably the scores for non-U.S. citizens were symmetric and bell shaped. d. A non-U.S. citizen who scored 3 standard deviations below the mean had a score of 200 .

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.