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A logistic regression model describes how the probability of voting for the Republican candidate in a presidential election depends on \(x,\) the voter's total family income (in thousands of dollars) in the previous year. The prediction equation for a particular sample is $$\hat{p}=\frac{e^{-1.00+0.02 x}}{1+e^{-1.00+0.02 x}}$$ Find the estimated probability of voting for the Republican candidate when (a) income \(=\$ 10,000\), (b) income \(=\$ 100,000\). Describe how the probability seems to depend on income.

Short Answer

Expert verified
Probability is 0.31 for $10,000 income and 0.73 for $100,000. Probability increases with income.

Step by step solution

01

Understand the Equation

The logistic regression model provides the equation for the estimated probability \( \hat{p} \). The equation is \( \hat{p} = \frac{e^{-1.00 + 0.02x}}{1 + e^{-1.00 + 0.02x}} \). Here, \( x \) is the total income in thousands of dollars.
02

Calculate Probability for $10,000 Income

Substitute \( x = 10 \) (since $10,000 is 10 thousands of dollars) into the equation, \( \hat{p} = \frac{e^{-1.00 + 0.02 \times 10}}{1 + e^{-1.00 + 0.02 \times 10}} = \frac{e^{-0.80}}{1 + e^{-0.80}} \). Calculate \( e^{-0.80} \) and \( 1 + e^{-0.80} \), then divide them to find \( \hat{p} \).
03

Calculate \(e^{-0.80}\)

Using a calculator, find \( e^{-0.80} \approx 0.4493 \).
04

Calculate Full Equation for $10,000

Substitute the value of \( e^{-0.80} \) into the full equation: \( \hat{p} = \frac{0.4493}{1 + 0.4493} \approx \frac{0.4493}{1.4493} \approx 0.31 \).
05

Calculate Probability for $100,000 Income

Substitute \( x = 100 \) (since $100,000 is 100 thousands of dollars) into the equation, \( \hat{p} = \frac{e^{-1.00 + 0.02 \times 100}}{1 + e^{-1.00 + 0.02 \times 100}} = \frac{e^{1.00}}{1 + e^{1.00}} \).
06

Calculate \(e^{1.00}\)

Using a calculator, find \( e^{1.00} \approx 2.718 \).
07

Calculate Full Equation for $100,000

Substitute the value of \( e^{1.00} \) into the full equation: \( \hat{p} = \frac{2.718}{1 + 2.718} \approx \frac{2.718}{3.718} \approx 0.73 \).
08

Analyze the Probability Dependence on Income

As income increases from $10,000 to $100,000, the estimated probability of voting for the Republican candidate increases from 0.31 to 0.73, suggesting a positive correlation between higher income and voting Republican.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Estimation
Probability estimation using logistic regression is a method to determine the likelihood of a specific event occurring. In the context of the exercise, it involves calculating the probability (\( \hat{p} \)) that a voter will choose the Republican candidate based on their income. Logistic regression is particularly suitable for this task because it deals with binary outcomes, which is the nature of voting decisions.

The equation utilized here is:\[\hat{p} = \frac{e^{-1.00 + 0.02x}}{1 + e^{-1.00 + 0.02x}}\]This function helps transition between the logistic model's linear combination of predictors to a probability that lies between 0 and 1. The transformation it uses results in an S-shaped curve that predicts the easing-in probability as income changes. However, the key is in substitution — replacing \( x \) with the income (in thousands of dollars) allows for the calculation of specific probabilities for different incomes.

For instance, at an income of \(10,000 (\( x = 10 \)), we calculate the probability using the equation. By substitution and subsequent calculation of the exponents, we find the likelihood that a person with that income votes Republican. This is similarly done for \)100,000 to understand how the probability grows with income.
Logistic Model Equation
The logistic model equation is integral to logistic regression and probability estimation. It mathematically defines how different predictive factors, like income, influence an outcome. In our exercise, the equation:\[\hat{p} = \frac{e^{-1.00 + 0.02x}}{1 + e^{-1.00 + 0.02x}}\]is a specific instance of a logistic model where \(-1.00 + 0.02x\) represents the log-odds: the natural logarithm of the odds of voting Republican.

Let's dissect this equation further:
  • **\(-1.00\)** is the intercept, where an income of zero would result in these base odds.
  • **\(0.02x\)** is the coefficient for income, indicating how much the log-odds change with each additional thousand dollars of income. A positive coefficient suggests a direct relationship — as income increases, so do the odds of voting Republican.
This model balances simplicity and explanatory power. It incorporates both mathematical precision and intuitive clarity, enabling discussions on how income variations might influence voting behavior. By normalizing the odds between 0 and 1, it becomes easier to interpret and implement in real-world analysis.
Income and Voting Behavior
Income levels often correlate with voting behavior, and logistic regression helps quantify this relationship. Voting patterns, particularly in U.S. presidential elections, show distinct trends based on socio-economic demographics. This exercise demonstrates how logistic regression is employed to explore these trends quantifiably.

As demonstrated, lower income ($10,000) corresponds to a probability of 0.31 of voting for the Republican candidate. In contrast, a higher income ($100,000) links to a markedly higher probability, at 0.73. This indicates an increasing likelihood of voting Republican as income rises.

Such patterns might stem from party policies appealing differently across income brackets, where individuals with higher incomes may favor economic policies perceived as beneficial to their financial interests. This positive correlation between income and Republican voting behavior, as shown through logistic regression, provides valuable insights.
  • Data-driven decision-making: Understanding these patterns can aid political campaigns in targeting specific demographics.
  • Policy implications: Recognizing these correlations might influence political strategies and policy proposals.
Using logistic regression thus not only forecasts individual voting behavior but also enriches our understanding of broader electoral dynamics.

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Most popular questions from this chapter

In the model \(\mu_{y}=\alpha+\beta_{1} x_{1}+\beta_{2} x_{2},\) suppose that \(x_{2}\) is an indicator variable for gender, equaling 1 for females and 0 for males. a. We set \(x_{2}=0\) if we want a predicted mean without knowing gender. b. The slope effect of \(x_{1}\) is \(\beta_{1}\) for males and \(\beta_{2}\) for females. c. \(\beta_{2}\) is the difference between the population mean of \(y\) for females and for males. d. \(\beta_{2}\) is the difference between the population mean of \(y\) for females and males, for all those subjects having \(x_{1}\) fixed, such as \(x_{1}=10\)

Suppose you fit a straight-line regression model to \(y=\) amount of time sleeping per day and \(x=\) age of subject. Values of \(y\) in the sample tend to be quite large for young children and for elderly people, and they tend to be lower for other people. Sketch what you would expect to observe for (a) the scatterplot of \(x\) and \(y\) and (b) a plot of the residuals against the values of age.

You want to include religious affiliation as a predictor in a regression model, using the categories Protestant, Catholic, Jewish, Other. You set up a variable \(x_{1}\) that equals 1 for Protestants, 2 for Catholics, 3 for Jewish, and 4 for Other, using the model \(\mu_{y}=\alpha+\beta x_{1}\). Explain why this is inappropriate.

Parabolic regression A regression formula that gives a parabolic shape instead of a straight line for the relationship between two variables is $$\mu_{y}=\alpha+\beta_{1} x+\beta_{2} x^{2}$$ a. Explain why this is a multiple regression model, with \(x\) playing the role of \(x_{1}\) and \(x^{2}\) (the square of \(x\) ) playing the role of \(x_{2}\). b. For \(x\) between 0 and 5 , sketch the prediction equation (i) \(\hat{y}=10+2 x+0.5 x^{2}\) and (ii) \(\hat{y}=10+2 x-0.5 x^{2} .\) This shows how the parabola is bowl-shaped or mound-shaped, depending on whether the coefficient \(x^{2}\) is positive or negative.

Let's use multiple regression to predict total body weight (in pounds) using data from a study of University of Georgia female athletes. Possible predictors are \(\mathrm{HGT}=\) height (in inches), \(\% \mathrm{BF}=\) percent body fat, and age. The display shows correlations among these explanatory variables. a. Which explanatory variable gives by itself the best predictions of weight? Explain. b. With height as the sole predictor, \(\hat{y}=-106+3.65\) \((\mathrm{HGT})\) and \(r^{2}=0.55 .\) If you add \(\% \mathrm{BF}\) as a predictor, you know that \(R^{2}\) will be at least \(0.55 .\) Explain why. c. When you add \% body fat to the model, \(\hat{y}=-121+3.50(\mathrm{HGT})+1.35(\% \mathrm{BF})\) and \(R^{2}=0.66 .\) When you add age to the model, \(\hat{y}=-97.7+3.43(\mathrm{HGT})+1.36(\% \mathrm{BF})-0.960(\mathrm{AGE})\) and \(R^{2}=0.67\). Once you know height and \(\%\) body fat, does age seem to help you in predicting weight? Explain, based on comparing the \(R^{2}\) values.

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