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Appropriate use of the interval $$ \hat{p} \pm(z \text { critial value }) \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} $$ requires a large sample. For each of the following combinations of \(n\) and \(\hat{p}\), indicate whether the sample size is large enough for this interval to be appropriate. $$ \begin{array}{l} \text { a. } n=100 \text { and } \hat{p}=0.70 \\ \text { b. } n=40 \text { and } \hat{p}=0.25 \\ \text { c. } n=60 \text { and } \hat{p}=0.25 \end{array} $$ d. \(n=80\) and \(\hat{p}=0.10\)

Short Answer

Expert verified
The sample sizes in cases 'a', 'b', and 'c' are large enough for the interval to be appropriate. However, the sample size in case 'd' is not large enough.

Step by step solution

01

Calculate \(n\hat{p}\)

For each case, calculate \(n\hat{p}\). In case 'a', this would be \(100 \times 0.70 = 70\), for case 'b' it would be \(40 \times 0.25 = 10\), for 'c' it would be \(60 \times 0.25 = 15\) and for 'd' it would be \(80 \times 0.10 = 8\).
02

Calculate \(n(1-\hat{p})\)

Again, calculate this for each case. In case 'a', this would be \(100 \times (1 - 0.70) = 30\), for case 'b' it would be \(40 \times (1 - 0.25) = 30\), for 'c' it would be \(60 \times (1 - 0.25) = 45\) and for 'd' it would be \(80 \times (1 - 0.10) = 72\).
03

Check the condition

Now, if both these values are greater than or equal to 10 for each case, then the sample size is considered large enough for the interval to be appropriate. In case 'a' and 'b', both values are greater than or equal to 10. However, in cases 'c' and 'd', while \(n(1-\hat{p})\) is greater than or equal to 10, \(n\hat{p}\) in case 'd' is less than 10. Therefore, the sample size is not large enough in case 'd'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values, derived from sample statistics, which is likely to contain the value of an unknown population parameter. To put it simply, it gives an estimated range of values which is assumed to cover the true value of the parameter with a certain degree of confidence, typically expressed as a percentage. This is crucial because we often cannot measure an entire population, but we try to infer about it from a sample.

When constructing a confidence interval for a population proportion, the formula typically used is:
\[\begin{equation}\hat{p} \pm(z \text { critical value }) \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\end{equation}\]
Here, \(\hat{p}\) is the sample proportion, \(z\) is the z-score corresponding to the desired level of confidence, and \(n\) is the sample size. The term \(\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\) represents the margin of error for the confidence interval. The larger the sample size or the lower the confidence level, the narrower the confidence interval will be, providing a more precise estimate of the population parameter.
Population Proportion
Population proportion, denoted as \( P \), represents the fraction of individuals in a population that possess a certain characteristic, feature, or attribute. In contrast, a sample proportion, \(\hat{p}\), refers to the fraction of individuals with the characteristic in a sample drawn from the population.

Estimating the population proportion can be challenging because it is not feasible or practical to investigate every individual in a large population. Hence, statisticians use the sample proportion as an estimator of the population proportion, which involves collecting data from a subset of the whole population. The accuracy of the estimation improves with larger samples and random sampling methods, as it reduces the chance of bias and increases representation of the varied population characteristics.
Normal Approximation
The normal approximation method is used in statistics to estimate the probability distribution of a binomial variable using a normal distribution when certain conditions are met. This becomes particularly useful when the sample size is large, as it is easier to work with a normal distribution than a binomial one.

The binomial distribution can be approximated with a normal distribution when both \( n\hat{p} \) and \( n(1-\hat{p}) \) are greater than or equal to 10—the larger these products, the better the approximation. When these conditions are met, the sample proportion, \(\hat{p}\), has an approximately normal distribution, allowing us to make inferences about the population proportion with confidence intervals or hypothesis tests.
Sample Proportion
The sample proportion, \(\hat{p}\), is a statistic that estimates the proportion of elements in a population with a certain characteristic based on a sample. It's calculated by dividing the number of individuals in the sample with the characteristic by the total number of individuals in the sample.

For example, if you have a sample size of \(n\) individuals and \(x\) of them have the characteristic you're analyzing, the sample proportion is:
\[\begin{equation}\hat{p} = \frac{x}{n}\end{equation}\]
This sample proportion is key when conducting statistical tests or constructing confidence intervals. It's a snapshot of what we might expect in the wider population, and it plays a critical role in determining the representativeness of the sample. A larger sample size generally leads to a sample proportion that is a better estimator of the actual population proportion, primarily due to the reduction in the margin of error and the effects of random variability.

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Most popular questions from this chapter

A researcher wants to estimate the proportion of city residents who favor spending city funds to promote tourism. Would the standard error of the sample proportion \(\hat{p}\) be smaller for random samples of size \(n=100\) or random samples of size \(n=200 ?\)

Suppose that a city planning commission wants to know the proportion of city residents who support installing streetlights in the downtown area. Two different people independently selected random samples of city residents and used their sample data to construct the following confidence intervals for the population proportion: Interval 1:(0.28,0.34) Interval 2:(0.31,0.33) (Hint: Consider the formula for the confidence interval given on page 401 ) a. Explain how it is possible that the two confidence intervals are not centered in the same place. b. Which of the two intervals conveys more precise information about the value of the population proportion? c. If both confidence intervals have a \(95 \%\) confidence level, which confidence interval was based on the smaller sample size? How can you tell? d. If both confidence intervals were based on the same sample size, which interval has the higher confidence level? How can you tell?

Based on data from a survey of 1,200 randomly selected Facebook users (USA Today, March 24, 2010), a \(90 \%\) confidence interval for the proportion of all Facebook users who say it is not OK to "friend" someone who reports to you at work is (0.60,0.64) . What is the meaning of the \(90 \%\) confidence level associated with this interval?

A researcher wants to estimate the proportion of students enrolled at a university who eat fast food more than three times in a typical week. Would the standard error of the sample proportion \(\hat{p}\) be smaller for random samples of size \(n=50\) or random samples of size \(n=200 ?\)

The article "Hospitals Dispute Medtronic Data on Wires" (The Wall Street Journal, February 4, 2010) describes several studies of the failure rate of defibrillators used in the treatment of heart problems. In one study conducted by the Mayo Clinic, it was reported that failures within the first 2 years were experienced by 18 of 89 patients under 50 years old and 13 of 362 patients age 50 and older. Assume that these two samples are representative of patients who receive this type of defibrillator in the two age groups. a. Construct and interpret a \(95 \%\) confidence interval for the proportion of patients under 50 years old who experience a failure within the first 2 years. b. Construct and interpret a \(99 \%\) confidence interval for the proportion of patients age 50 and older who experience a failure within the first 2 years. c. Suppose that the researchers wanted to estimate the proportion of patients under 50 years old who experience this type of failure with a margin of error of \(0.03 .\) How large a sample should be used? Use the given study results to obtain a preliminary estimate of the population proportion.

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