/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 The article "Career Expert Provi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The article "Career Expert Provides DOs and DON'Ts for Job Seekers on Social Networking" (CareerBuilder.com, August 19,2009 ) included data from a survey of 2,667 hiring managers and human resource professionals. The article noted that more employers are now using social networks to screen job applicants. Of the 2,667 people who participated in the survey, 1,200 indicated that they use social networking sites such as Facebook, MySpace, and LinkedIn to research job applicants. Assume that the sample is representative of hiring managers and human resource professionals. Answer the four key questions (QSTN) to confirm that the suggested method in this situation is a confidence interval for a population proportion.

Short Answer

Expert verified
The suggested method i.e., a confidence interval for a population proportion, is valid in this scenario as the outcomes are binary, the sample is representative, and the sample size is sufficiently large.

Step by step solution

01

Identify the sample proportion

In this case, the sample size is 2,667 people who participated in the survey, of which 1,200 use social networking sites to research applicants. Thus the sample proportion (p̂) would be the number of hiring managers who use social networking sites divided by the total number of hiring managers, i.e, \( \frac{1200}{2667} = 0.449 \).
02

Check if the sample is representative

We are given that the managers are representative of all hiring managers and HR professionals. The sample size is sufficiently large and presumably randomly selected, therefore, we can assume it is a representative sample.
03

Find the sample size

We are also given that the sample size is 2,667 and we know that for a confidence interval for a proportion to be the correct method, the sample size needs to be sufficiently large. A rule of thumb for this sufficiency is that both \( np̂ \) and \( n(1 - p̂) \) should be greater than 5. Here, \( 2667⋅0.449 = 1197.83 > 5 \) and \( 2667⋅(1 - 0.449) = 1469.17 > 5 \), thus, the sample size is sufficiently large and the use of a confidence interval for a population proportion is an appropriate method in this situation.
04

Population is binary

We understand that a job applicant is either researched through social networking sites or not. Employers either use social networking sites for hiring or they do not. Hence, the population is binary (divided into two distinct groups) which confirms that the confidence interval for a population proportion is indeed a suitable method.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When we talk about sample proportion, we're referring to the fraction of individuals in a sample that exhibit a particular trait or characteristic. In the context of the provided exercise, the characteristic of interest is the use of social networking sites by hiring managers to screen job applicants.

The sample proportion, denoted by \( \hat{p} \), is the number of individuals in the sample with the characteristic divided by the total number of individuals in the sample. In our case, with 1,200 hiring managers using social networking sites out of a sample of 2,667, the sample proportion \( \hat{p} \) equals \( \frac{1200}{2667} \), which simplifies to approximately 0.449. This figure serves as an estimate for the true population proportion.
Representative Sample
A representative sample accurately reflects the population from which it's drawn, ensuring that any conclusion drawn from the sample can be generalized to the population. To achieve this, the sample must be randomly selected, and its composition should mirror the diversity of the population in terms of key characteristics.

In our exercise, the survey's respondents are hiring managers and human resource professionals, and we assume that they are a representative sample of all such individuals in the general population. This assumption is crucial because it backs the validity of using the sample proportion to estimate the population proportion, particularly when constructing a confidence interval for that population proportion.
Sample Size
Sample size, denoted by \( n \), is the number of observations or individuals in a sample. The size of the sample plays a significant role in determining the precision of our estimates and the reliability of our statistical inferences.

The chosen sample size in our problem was 2,667, a figure which we assessed using the criteria that \( n\hat{p} \) and \( n(1 - \hat{p}) \) both exceed 5. This rule of thumb ensures that the Central Limit Theorem holds, and our sample proportion's distribution approaches normalcy, allowing us to confidently create a confidence interval for the population proportion. Our sample size of 2,667 satisfies this condition, with both \( 2667\times0.449 \) and \( 2667\times(1 - 0.449) \) being greater than 5.
Binary Population
The term 'binary population' refers to a scenario where each member of the population can be categorized into one of two groups based on a characteristic. This duality is essential when determining proportions since the characteristic is present in some members and absent in others.

In our exercise, the binary groups are hiring managers who do use social networking sites to screen job applicants and those who do not. This clear-cut separation allows for the calculation of the population proportion, which is the foundation for constructing a confidence interval. The binary nature of the population validates the methods used and the interpretability of the results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The formula used to calculate a large-sample confidence interval for \(p\) is $$ \hat{p} \pm(z \text { critial value }) \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} $$ What is the appropriate \(z\) critical value for each of the following confidence levels? a. \(95 \%\) b. \(98 \%\) c. \(85 \%\)

The article "Nine Out of Ten Drivers Admit in Survey to Having Done Something Dangerous" (Knight Ridder Newspapers, July 8,2005\()\) reported on a survey of 1,100 drivers. Of those surveyed, 990 admitted to careless or aggressive driving during the previous 6 months. Assume that the sample is representative of the population of drivers. Answer the four key questions (QSTN) to confirm that the suggested method in this situation is a confidence interval for a population proportion.

In a study of 1,710 schoolchildren in Australia (Herald Sun, October 27,1994 ), 1,060 children indicated that they normally watch TV before school in the morning. (Interestingly, only \(35 \%\) of the parents said their children watched TV before school.) Construct and interpret a \(95 \%\) confidence interval for the proportion of all Australian children who say they watch TV before school. In order for the method used to construct the interval to be valid, what assumption about the sample must be reasonable?

High-profile legal cases have many people reevaluating the jury system. Many believe that juries in criminal trials should be able to convict on less than a unanimous vote. To assess support for this idea, investigators asked each individual in a random sample of Californians whether they favored allowing conviction by a \(10-2\) verdict in criminal cases not involving the death penalty. The Associated Press (San Luis ObispoTelegram-Tribune, September 13,1995 ) reported that \(71 \%\) favored conviction with a \(10-2\) verdict. Suppose that the sample size for this survey was \(n=900\). Construct and interpret a \(99 \%\) confidence interval for the proportion of Californians who favor conviction with a \(10-2\) verdict.

A car manufacturer is interested in learning about the proportion of people purchasing one of its cars who plan to purchase another car of this brand in the future. A random sample of 400 of these people included 267 who said they would purchase this brand again. For each of the three statements below, indicate if the statement is correct or incorrect. If the statement is incorrect, explain what makes it incorrect. Statement 1 : The estimate \(\hat{p}=0.668\) will never differ from the value of the actual population proportion by more than \(0.0462 .\) Statement 2 : It is unlikely that the estimate \(\hat{p}=0.668\) differs from the value of the actual population proportion by more than 0.0235 . Statement 3: It is unlikely that the estimate \(\hat{p}=0.668\) differs from the value of the actual population proportion by more than 0.0462 .

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.