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USA Today (October 14,2002 ) reported that \(36 \%\) of adult drivers admit that they often or sometimes talk on a cell phone when driving. This estimate was based on data from a representative sample of 1,004 adult drivers. A margin of error of \(3.1 \%\) was also reported. Is this margin of error correct? Explain.

Short Answer

Expert verified
To find out if the 3.1% margin of error quoted in the exercise is correct, we need to use the formula for the margin of error and compare the result to the value provided. It's essential to show how to apply the margin of error formula meticulously.

Step by step solution

01

Define the Variables

Firstly, we identify the variables from the problem. The sample proportion \(p\) is 0.36 (36%). The sample size \(n\), equals 1,004.
02

Apply Margin of Error Formula

We apply the margin of error formula \(E = Z \sqrt{\frac{{p(1-p)}}{n}}\). Here, we use the standard \(Z\) value of 1.96 for a 95% confidence interval, \(p=0.36\), and \(n=1004\). Then calculate the value.
03

Compare Calculated Margin of Error with Given Margin of Error

After calculating the margin of error, we compare it with the given margin of error of 3.1%. If they are close or approximately equal, the stated margin of error would be assumed correct. Otherwise, it isn't correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error is a vital concept in statistics, particularly in survey results and public opinion polling. It tells us the range within which we can expect the true population parameter to fall, with a certain level of confidence. In essence, it's a measure of the uncertainty or potential error in our estimation process.
The formula for the margin of error when dealing with proportions generally considers three primary factors: the critical value, the sample proportion, and the sample size. The formula is:
  • \[E = Z \sqrt{\frac{{p(1-p)}}{n}}\]
where:
  • \(E\) is the margin of error,
  • \(Z\) is the critical value from the Z-distribution,
  • \(p\) is the sample proportion, and
  • \(n\) is the sample size.
For a 95% confidence level, a common choice in social sciences, you typically use a Z-score of 1.96. This estimate gives us a symmetric interval around the sample proportion. If the margin of error exceeds expectations or doesn't match the calculation, this may indicate a need to revisit the assumptions or the provided data.
Sample Proportion
The sample proportion is a statistic that offers a glimpse into the behavior or characteristics of a larger population, based on a sample. It is the ratio of individuals in a sample showing a particular trait. In the context of the exercise, the sample proportion of 0.36 represents the fraction of the sample that admits to talking on a cell phone while driving. This proportion helps estimate the prevalence of this behavior among all drivers.Calculating the sample proportion is straightforward: simply divide the number of success cases (individuals showing the trait) by the total sample size. Here the calculation would be:
  • \(p = \frac{x}{n}\)
where:
  • \(x\) is the number of individuals in the sample with the trait, and
  • \(n\) is the total sample size.
Understanding the sample proportion allows researchers to generalize from the sample to the population with a bigger picture in mind. The sample proportion serves as the foundation for further calculations, such as constructing a confidence interval.
Confidence Interval
A confidence interval provides a range in which we estimate the true population parameter to lie with a certain probability. It's a key concept in inferential statistics, offering researchers a way to make educated guesses about population parameters based on sample data.
  • The general form of a confidence interval for a sample proportion \(p\) is:
\[ CI = p \pm E \]where:
  • \(CI\) is the confidence interval,
  • \(p\) is the sample proportion, and
  • \(E\) is the margin of error.
For instance, if the margin of error is 3.1% as in our exercise, and the sample proportion is 36%, the confidence interval would stretch from 32.9% to 39.1%. This interval suggests that we can be reasonably sure, in this case with 95% confidence, that the true proportion of all adult drivers who engage in this behavior falls within this range.Understanding confidence intervals is crucial because it highlights the reasoning that, while our sample provides a specific proportion, there is natural variability and uncertainty when attempting to infer about the entire population.

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Most popular questions from this chapter

Data from a representative sample were used to estimate that \(32 \%\) of all computer users in 2011 had tried to get on a Wi-Fi network that was not their own in order to save money (USA Today, May 16,2011 ). You decide to conduct a survey to estimate this proportion for the current year. What is the required sample size if you want to estimate this proportion with a margin of error of 0.05 ? Calculate the required sample size first using 0.32 as a preliminary estimate of \(p\) and then using the conservative value of \(0.5 .\) How do the two sample sizes compare? What sample size would you recommend for this study?

If two statistics are available for estimating a population characteristic, under what circumstances might you choose a biased statistic over an unbiased statistic?

A large online retailer is interested in learning about the proportion of customers making a purchase during a particular month who were satisfied with the online ordering process. A random sample of 600 of these customers included 492 who indicated they were satisfied. For each of the three following statements, indicate if the statement is correct or incorrect. If the statement is incorrect, explain what makes it incorrect. Statement 1: It is unlikely that the estimate \(\hat{p}=0.82\) differs from the value of the actual population proportion by more than 0.0157 . Statement 2 : It is unlikely that the estimate \(\hat{p}=0.82\) differs from the value of the actual population proportion by more than 0.0307 . Statement 3: The estimate \(\hat{p}=0.82\) will never differ from the value of the actual population proportion by more than 0.0307 .

a. Use the given information to estimate the proportion of college students who use the Internet more than 3 hours per day. b. Verify that the conditions needed in order for the margin of error formula to be appropriate are met. c. Calculate the margin of error. d. Interpret the margin of error in the context of this problem.Most American college students make use of the Internet for both academic and social purposes. What proportion of students use it for more than 3 hours a day? The authors of the paper "U.S. College Students" Internet Use: Race, Gender and Digital Divides" (Journal of Computer-Mediated Communication [2009]: 244-264) describe a survey of 7,421 students at 40 colleges and universities. The sample was selected to reflect general demographics of U.S. college students. Of the students surveyed, 2,998 reported Internet use of more than 3 hours per day.

A random sample will be selected from the population of all adult residents of a particular city. The sample proportion \(\hat{p}\) will be used to estimate \(p,\) the proportion of all adult residents who do not own a car. For which of the following situations will the estimate tend to be closest to the actual value of \(p ?\) i. \(\quad n=500, p=0.1\) $$ \text { ii. } \quad n=1,000, p=0.2 $$ iii. \(n=1,200, p=0.3\)

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