/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A certain chromosome defect occu... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A certain chromosome defect occurs in only 1 in 200 adult Caucasian males. A random sample of 100 adult Caucasian males will be selected. The proportion of men in this sample who have the defect, \(\hat{p},\) will be calculated. a. What are the mean and standard deviation of the sampling distribution of \(\hat{p}\) ? b. Is the sampling distribution of \(\hat{p}\) approximately normal? Explain. c. What is the smallest value of \(n\) for which the sampling distribution of \(\hat{p}\) is approximately normal?

Short Answer

Expert verified
a. Mean is 0.005 and the standard deviation is 0.022. b. No, the sample distribution of \(\hat{p}\) is not approximately normal as \(np = 0.5 < 5\) and \(n(1 - p) = 99.5 > 5\). c. Minimum sample size, \(n\), for \(\hat{p}\) to be approximately normal is 1000.

Step by step solution

01

Calculate Mean and Standard Deviation of \(\hat{p}\)

In this step, we utilize the formulas for mean and standard deviation of a sample proportion. The mean (\(\mu_{\hat{p}}\)) is equal to the success proportion in the population (\(p\)), which is \(\frac{1}{200}\) or 0.005 in this case. The standard deviation (\(\sigma_{\hat{p}}\)) is calculated by the formula, \(\sigma_{\hat{p}} = \sqrt{\frac{p(1 - p)}{n}}\), where \(n\) is the sample size of 100 men.
02

Check the Normality of the Sampling Distribution

The normality of the sampling distribution can be justified by applying the rule of thumb which states that, for the sampling distribution of a proportion to be approximately normal, both \(np\) and \(n(1 - p)\) should be greater than or equal to 5. Given \(p = 0.005\) and \(n = 100\), we check whether both the quantities are greater than 5 or not.
03

Find the Minimum Sample Size for Normality

We must find the smallest value of \(n\) which makes the sampling distribution approximately normal. This value can be calculated by ensuring that both \(np\) and \(n(1 - p)\) are greater than or equal to 5.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
In statistics, a sample proportion is a helpful tool when trying to understand how often an event occurs in a sample compared to the entire population. When you're dealing with a sample proportion, you essentially answer the question: "How common is this feature within my sample?" To calculate the sample proportion (\(\hat{p}\)), you use the formula:
  • Number of successes in the sample divided by the total sample size.
So, if you tested 100 people for a trait and found that 5 of them exhibit it, your sample proportion would be:
  • \(\hat{p} = \frac{5}{100} = 0.05\)
This value represents the portion of your sample that displays the feature of interest. As with any measurement, the sample proportion may differ from the actual proportion in the population. It's crucial to understand this core concept because it's the foundation for making inferences about a larger population.
Normality
The normality of the sampling distribution is vital because it influences how we interpret data and make predictions. A sampling distribution of a sample proportion is roughly normal if certain conditions are met, like seeing how often a particular trait appears in many similar-sized samples.

Rule of Thumb for Normality

To decide if the sampling distribution is normal, we use a simple rule of thumb: both \(np\) and \(n(1 - p)\) should be at least 5.
  • "\(np\)" checks the expected number of successes.
  • "\(n(1 - p)\)" checks the expected number of failures.
For example, if you have a small success rate, like detecting a rare trait, you need a large sample to ensure normality. Once normality is established, you can use the properties of the normal distribution to make statistical inferences about the population.
Mean and Standard Deviation
The mean and standard deviation are key elements in understanding the sampling distribution of a sample proportion. The mean of the sampling distribution for the proportion (\(\mu_{\hat{p}}\)) actually equals the true proportion of the population (\(p\)).

Mean

Given a population proportion (\(p\)), your mean of the sampling distribution is straightforwardly given by \(\mu_{\hat{p}} = p\). Essentially, it reflects where the center of your data points lies, over repeated sampling.

Standard Deviation

The standard deviation (\(\sigma_{\hat{p}}\)) is slightly more complex. It indicates how much variation exists in the sampling distribution and is calculated using:\[\sigma_{\hat{p}} = \sqrt{\frac{p(1 - p)}{n}}\]This formula allows you to measure the spread of your sample proportions from the mean. A smaller standard deviation indicates less spread, meaning your samples tend to be closer to the population proportion.Understanding these concepts will enable you to effectively critique data because you'll know both its typical behavior (mean) and variability (standard deviation).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A random sample of 50 registered voters in a particular city included 32 who favored using city funds for the construction of a new recreational facility. For this sample, \(\hat{p}=\frac{32}{50}=\) 0.64 . If a second random sample of 50 registered voters was selected, would it surprise you if \(\hat{p}\) for that sample was not equal to 0.64 ? Why or why not?

A random sample of size 300 is to be selected from a population. Determine the mean and standard deviation of the sampling distribution of \(\hat{p}\) for each of the following population proportions. a. \(p=0.20\) b. \(p=0.45\) c. \(p=0.70\) d. \(p=0.90\)

The article "Thrillers" (Newsweek, April 22,1985 ) stated, "Surveys tell us that more than half of America's college graduates are avid readers of mystery novels." Let \(p\) denote the actual proportion of college graduates who are avid readers of mystery novels. Consider a sample proportion \(\hat{p}\) that is based on a random sample of 225 college graduates. If \(p=0.5,\) what are the mean value and standard deviation of the sampling distribution of \(\hat{p}\) ? Answer this question for \(p=0.6 .\) Is the sampling distribution of \(\hat{p}\) approximately normal in both cases? Explain.

Consider the following statement: A county tax assessor reported that the proportion of property owners who paid 2012 property taxes on time was 0.93 . a. Is the number that appears in boldface in this statement a sample proportion or a population proportion? b. Which of the following use of notation is correct, \(p=0.93\) or \(p=0.93 ?\)

If a hurricane were headed your way, would you evacuate? The headline of a press release issued January \(21,2009,\) by the survey research company International Communications Research (icrsurvey.com) states, "Thirty-one Percent of People on High-Risk Coast Will Refuse Evacuation Order, Survey of Hurricane Preparedness Finds." This headline was based on a survey of 5,046 adults who live within 20 miles of the coast in high hurricane risk counties of eight southern states. The sample was selected to be representative of the population of coastal residents in these states, so assume that it is reasonable to regard the sample as if it were a random sample. a. Suppose you are interested in learning about the value of \(p\), the proportion of adults who would refuse to evacuate. This proportion can be estimated using the sample proportion, \(\hat{p} .\) What is the value of \(\hat{p}\) for this sample? b. Based on what you know about the sampling distribution of \(\hat{p}\), is it reasonable to think that the estimate is within 0.03 of the actual value of the population proportion? Explain why or why not.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.