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Suppose you want to estimate the probability that a randomly selected customer at a particular grocery store will pay by credit card. Over the past 3 months, 80,500 payments were made, and 37,100 of them were by credit card. What is the estimated probability that a randomly selected customer will pay by credit card?

Short Answer

Expert verified
The estimated probability that a randomly selected customer will pay by credit card is approximately 0.46 or 46%.

Step by step solution

01

Identify the total number of outcomes

The total number of outcomes is the total payments made at the grocery store which is 80,500.
02

Identify the number of favorable outcomes

The number of favorable outcomes is the number of payments made by credit card which is 37,100.
03

Calculate the Probability

The probability of a randomly selected customer paying by credit card is calculated by dividing the number of favorable outcomes by the total number of outcomes. Using these numbers, the calculation would be \(\frac{37100}{80500}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Sampling
Random sampling is a fundamental method used in the field of statistics to select a subset of individuals or observations from within a statistical population to estimate characteristics of the whole population. Understanding this concept is critical when it comes to tackling real-world problems where it's impractical or impossible to examine an entire population.

In the exercise provided, the grocery store's payments represent the population, and each payment is an individual observation. By collecting data from the entire three months, which involves 80,500 payments, the store ensures that the sample reflects the broad range of customers. The concept assumes that every payment had an equal chance of being included in the data set, which is a key principle of random sampling. It minimizes biases that can skew results and provides a reliable foundation for estimating the probability of future events, such as the likelihood of customers paying with credit cards.

Random sampling's real value lies in its ability to provide accurate estimations that can be generalized to the larger group, which is especially useful when the total population is too large to analyze fully.
Favorable Outcomes
Whether you are calculating the likelihood of rolling a six on a die or estimating the probability of an event in real life, the concept of favorable outcomes is central to probability. Favorable outcomes are those specific results that we're interested in when performing a probability experiment.

In the context of our grocery store example, a favorable outcome refers to an event where a customer pays by credit card. Out of the 80,500 total payments, 37,100 were made with a credit card. These 37,100 payments are our favorable outcomes. They are 'favorable' simply because these are the outcomes we are counting when we aim to estimate the probability of a particular occurrence.

Understanding what constitutes a favorable outcome is essential for accurate probability calculation. It affects the numerator in our probability fraction and thus directly impacts the calculated likelihood of an event occurring. Additionally, providing clarity on what exactly are the favorable outcomes can help students easily grasp the concept, specially in the context of complex, real-world problems.
Probability Calculation
The probability calculation is the mathematical process used to find the likelihood of a particular event happening. This is expressed as a number between 0 and 1, where 0 indicates an impossibility, and 1 represents certainty.

Following the steps solved in the exercise, calculating the probability involves dividing the number of favorable outcomes by the total number of possible outcomes. As seen in the grocery store scenario, the probability that a customer pays by credit card is the quotient of the favorable credit card payments (37,100) over the total payments made (80,500). Therefore, using the formula for probability, \( P(A) = \frac{\text{number of favorable outcomes}}{\text{total number of outcomes}} \) where A is the event of a customer paying by credit card, we get \( P(A) = \frac{37100}{80500} \) which simplifies to a decimal that estimates the probability of the event.

The calculation can be interpreted as the expected frequency of the event occurring in a long series of trials. Probability calculations are vital for decision making in many fields, enabling businesses and individuals to anticipate likely outcomes and plan accordingly.

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Most popular questions from this chapter

A company that offers roadside assistance to drivers reports that the probability that a call for assistance will be to help someone who is locked out of his or her car is \(0.18 .\) Give a relative frequency interpretation of this probability.

A rental car company offers two options when a car is rented. A renter can choose to pre-purchase gas or not and can also choose to rent a GPS device or not. Suppose that the events \(A=\) event that gas is pre-purchased \(B=\) event that a GPS is rented are independent with \(P(A)=0.20\) and \(P(B)=0.15\). a. Construct a "hypothetical 1000 " table with columns corresponding to whether or not gas is pre-purchased and rows corresponding to whether or not a GPS is rented. b. Use the table to find \(P(A \cup B)\). Give a long-run relative frequency interpretation of this probability.

A Nielsen survey of teens between the ages of 13 and 17 found that \(83 \%\) use text messaging and \(56 \%\) use picture messaging (“How Teens Use Media," Nielsen, June 2009). Use these percentages to explain why the two events \(T=\) event that a randomly selected teen uses text messaging and \(P=\) event that a randomly selected teen uses picture messaging cannot be mutually exclusive.

The paper "Predictors of Complementary Therapy Use Among Asthma Patients: Results of a Primary Care Survey" (Health and Social Care in the Community [2008]: \(155-164)\) described a study in which each person in a large sample of asthma patients responded to two questions: Question 1: Do conventional asthma medications usually help your symptoms? Question 2: Do you use complementary therapies (such as herbs, acupuncture, aroma therapy) in the treatment of your asthma? Suppose that this sample is representative of asthma patients. Consider the following events: \(E=\) event that the patient uses complementary therapies \(F=\) event that the patient reports conventional medications usually help The data from the sample were used to estimate the following probabilities: $$P(E)=0.146 \quad P(F)=0.879 \quad P(E \cap F)=0.122$$ a. Use the given probability information to set up a "hypothetical 1000 " table with columns corresponding to \(E\) and \(n o t E\) and rows corresponding to \(F\) and not \(F\). b. Use the table from Part (a) to find the following probabilities: i. The probability that an asthma patient responds that conventional medications do not help and that patient uses complementary therapies. ii. The probability that an asthma patient responds that conventional medications do not help and that patient does not use complementary therapies. iii. The probability that an asthma patient responds that conventional medications usually help or the patient uses complementary therapies. c. Are the events \(E\) and \(F\) independent? Explain.

The report "Improving Undergraduate Learning" (Social Science Research Council, 2011) summarizes data from a survey of several thousand college students. These students were thought to be representative of the population of all college students in the United States. When asked about an upcoming semester, \(68 \%\) said they would be taking a class that is reading-intensive (requires more than 40 pages of reading per week). Only \(50 \%\) said they would be taking a class that is writing-intensive (requires more than 20 pages of writing over the course of the semester). The percentage who said that they would be taking both a reading-intensive course and a writing-intensive course was \(42 \%\). a. Use the given information to set up a "hypothetical \(1000 "\) table. b. Use the table to find the following probabilities: i. the probability that a randomly selected student would be taking at least one of these intensive courses. ii. the probability that a randomly selected student would be taking one of these intensive courses, but not both. iii. the probability that a randomly selected student would be taking neither a reading-intensive nor a writing-intensive course.

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