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Head movement evaluations are important because disabled individuals may be able to operate communications aids using head motion. The paper "Constancy of Head Turning Recorded in Healthy Young Humans" (Journal of Biomedical Engineering [2008]\(: 428-436)\) reported the accompanying data on neck rotation (in degrees) both in the clockwise direction (CL) and in the counterclockwise direction (CO) for 14 subjects. For purposes of this exercise, you may assume that the 14 subjects are representative of the population of adult Americans. Based on these data, is it reasonable to conclude that mean neck rotation is greater in the clockwise direction than in the counterclockwise direction? Carry out a hypothesis test using a significance level of 0.01 . $$ \begin{array}{lccccccc} \text { Subject: } & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \text { CL: } & 57.9 & 35.7 & 54.5 & 56.8 & 51.1 & 70.8 & 77.3 \\ \text { CO: } & 44.2 & 52.1 & 60.2 & 52.7 & 47.2 & 65.6 & 71.4 \\ \text { Subject: } & 8 & 9 & 10 & 11 & 12 & 13 & 14 \\ \text { CL: } & 51.6 & 54.7 & 63.6 & 59.2 & 59.2 & 55.8 & 38.5 \\ \text { CO: } & 48.8 & 53.1 & 66.3 & 59.8 & 47.5 & 64.5 & 34.5 \end{array} $$

Short Answer

Expert verified
Based on the t-score and the critical t-value, it can be determined whether to accept the null hypothesis or reject it in favor of the alternative hypothesis. Depending on the answer, the conclusion would be made if it is reasonable or not that the mean neck rotation is greater in the clockwise direction than in the counterclockwise.

Step by step solution

01

Determine the Hypothesis

The null hypothesis \(H_0\) states that the mean neck rotation in the clockwise direction is equal to that in the counterclockwise direction, whereas the alternative hypothesis \(H_1\) posits that the clockwise mean neck rotation is greater than the counterclockwise. So, we have: \(H_0: \mu_{CL} = \mu_{CO}\) \(H_1: \mu_{CL} > \mu_{CO}\) where \(\mu_{CL}\) and \(\mu_{CO}\) are population mean neck rotations in the clockwise and counterclockwise directions, respectively.
02

Calculate Mean and Difference

Calculate the mean rotation in both directions by summing up the rotations and dividing by 14 (total number of subjects). Subsequently, calculate the difference in mean neck rotations.
03

Calculate the standard deviation and Standard Error

Calculate the standard deviation of the differences. Then calculate the Standard Error (SE) by dividing the standard deviation by the square root of the number of samples.
04

Determine the t-score

Using the formula for the t-score in a paired t-test, calculate the t-score. The formula should be \( t = \frac{\bar{d}}{SE} \), where \(\bar{d}\) is the mean difference, and SE is the Standard Error from Step 3.
05

Determine the critical value and compare

Determine the critical t-value for a 0.01 significance level with \( n - 1 \) degrees of freedom. Compare the calculated t-score with the critical t-value. If the t-score is greater than the critical t-value, reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Significance Level
The significance level, denoted by \( \alpha \), is a threshold that determines when we should reject the null hypothesis in a hypothesis test. If the probability of observing the test statistic under the null hypothesis is less than the significance level, we reject the null hypothesis as it suggests that such an extreme value of the test statistic is unlikely to occur just by random chance. In the context of our exercise, a significance level of 0.01 means we have a maximum tolerance of a 1% chance of committing a Type I error, which is rejecting a true null hypothesis. Establishing such a low significance level reflects the need for a high degree of confidence in the results of the hypothesis test.
Paired t-test
A paired t-test is a statistical method used to compare the means of two related groups. In our exercise, we are comparing neck rotation measurements in two different directions for the same individuals, making it a classic scenario for the paired t-test. This test takes into account that the two samples are not independent and that they are 'paired' because they come from the same individual. The test assesses whether the average difference between the pairs is significantly different from zero. The paired t-test is particularly powerful in 'before and after' studies or studies that measure the effect of a treatment or condition in the same subjects over time.
Population Mean Comparison
Comparing population means is a common objective in statistical analyses, as it allows researchers to determine if there is a significant difference between two or more groups. In our neck rotation exercise, we aim to compare the population mean neck rotations in the clockwise direction \( \mu_{CL} \) with that in the counterclockwise direction \( \mu_{CO} \). The null hypothesis posits that there is no difference between these means, while the alternative hypothesis suggests there is a difference, specifically that the mean in the clockwise direction is greater. The paired t-test will help to determine if the observed difference in sample means reflects a true difference in population means or if it’s likely attributable to random variation.
Standard Error Calculation
The standard error (SE) is a measure of how much sample means are expected to vary from the true population mean. It's calculated by dividing the standard deviation of the sample by the square root of the sample size. In other words, SE gives us an understanding of the precision of our sample mean as an estimate of the population mean. For the paired t-test in our exercise, the SE is calculated using the standard deviation of the differences in neck rotations (CL - CO) between pairs. This SE is then used to calculate the t-score, which will tell us how many standard errors the sample mean difference is from zero. A larger t-score indicates a more significant difference between our paired observations.

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Most popular questions from this chapter

Some people believe that talking on a cell phone while driving slows reaction time, increasing the risk of accidents. The study described in the paper "A Comparison of the Cell Phone Driver and the Drunk Driver" (Human Factors [2006]: \(381-391\) ) investigated the braking reaction time of people driving in a driving simulator. Drivers followed a pace car in the simulator, and when the pace car's brake lights came on, the drivers were supposed to step on the brake. The time between the pace car brake lights coming on and the driver stepping on the brake was measured. Two samples of 40 drivers participated in the study. The 40 people in one sample used a cell phone while driving. The 40 people in the second sample drank a mixture of orange juice and alcohol in an amount calculated to achieve a blood alcohol level of \(0.08 \%\) (a value considered legally drunk in most states). For the cell phone sample, the mean braking reaction time was 779 milliseconds and the standard deviation was 209 milliseconds. For the alcohol sample, the mean breaking reaction time was 849 milliseconds and the standard deviation was \(228 .\) Is there convincing evidence that the mean braking reaction time is different for the population of drivers talking on a cell phone and the population of drivers who have a blood alcohol level of \(0.08 \%\) ? For purposes of this exercise, you can assume that the two samples are representative of the two populations of interest.

For each of the following hypothesis testing scenarios, indicate whether or not the appropriate hypothesis test would be for a difference in population means. If not, explain why not. Scenario 1: The authors of the paper "Adolescents and MP3 Players: Too Many Risks, Too Few Precautions" (Pediatrics [2009]: e953-e958) studied independent random samples of 764 Dutch boys and 748 Dutch girls ages 12 to \(19 .\) Of the boys, 397 reported that they almost always listen to music at a high volume setting. Of the girls, 331 reported listening to music at a high volume setting. You would like to determine if there is convincing evidence that the proportion of Dutch boys who listen to music at high volume is greater than this proportion for Dutch girls. Scenario 2: The report "Highest Paying Jobs for \(2009-10\) Bachelor's Degree Graduates" (National Association of Colleges and Employers, February 2010 ) states that the mean yearly salary offer for students graduating with accounting degrees in 2010 is \(\$ 48,722\). A random sample of 50 accounting graduates at a large university resulted in a mean offer of \(\$ 49,850\) and a standard deviation of \(\$ 3,300\). You would like to determine if there is strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the 2010 national average of \(\$ 48,722\). Scenario 3: Each person in a random sample of 228 male teenagers and a random sample of 306 female teenagers was asked how many hours he or she spent online in a typical week (Ipsos, January 25,2006 ). The sample mean and standard deviation were 15.1 hours and 11.4 hours for males and 14.1 and 11.8 for females. You would like to determine if there is convincing evidence that the mean number of hours spent online in a typical week is greater for male teenagers than for female teenagers.

Descriptions of four studies are given. In each of the studies, the two populations of interest are the students at a particular university who live on campus and the students who live off campus. Which of these studies have samples that are independently selected? Study 1: To determine if there is evidence that the mean amount of money spent on food each month differs for the two populations, a random sample of 45 students who live on campus and a random sample of 50 students who live off campus are selected. Study 2: To determine if the mean number of hours spent studying differs for the two populations, a random sample students who live on campus is selected. Each student in this sample is asked how many hours he or she spend working each week. For each of these students who live on campus, a student who lives off campus and who works the same number of hours per week is identified and included in the sample of students who live off campus. Study 3: To determine if the mean number of hours worked per week differs for the two populations, a random sample of students who live on campus and who have a brother or sister who also attends the university but who lives off campus is selected. The sibling who lives on campus is included in the on campus sample, and the sibling who lives off campus is included in the off- campus sample. Study 4: To determine if the mean amount spent on textbooks differs for the two populations, a random sample of students who live on campus is selected. A separate random sample of the same size is selected from the population of students who live off campus.

Do children diagnosed with attention deficit/ hyperactivity disorder (ADHD) have smaller brains than children without this condition? This question was the topic of a research study described in the paper "Developmental Trajectories of Brain Volume Abnormalities in Children and Adolescents with Attention Deficit/Hyperactivity Disorder" (journal of the American Medical Association [2002]: \(1740-\) 1747). Brain scans were completed for a representative sample of 152 children with ADHD and a representative sample of 139 children without ADHD. Summary values for total cerebral volume (in milliliters) are given in the following table: $$ \begin{array}{lccc} & n & \bar{x} & s \\ \hline \text { Children with ADHD } & 152 & 1,059.4 & 117.5 \\ \text { Children Without ADHD } & 139 & 1,104.5 & 111.3 \end{array} $$ Use a \(95 \%\) confidence interval to estimate the differ- ence in mean brain volume for children with and without ADHD.

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