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Determine \(\mu_{\bar{x}}\) and \(\sigma_{\bar{x}}\) from the given parameters of the population and the sample size. \(\mu=80, \sigma=14, n=49\)

Short Answer

Expert verified
μ_{\bar{x}} = 80, \sigma_{\bar{x}} = 2

Step by step solution

01

Understand the Symbols and Given Data

Identify the given values: \( \text{Population mean} (\text{μ}) = 80 \), \( \text{Population standard deviation} (\text{σ}) = 14 \), \( \text{Sample size} (\text{n}) = 49 \).
02

Determine the Mean of the Sample Distribution (\text{μ}_{\bar{x}})

The mean of the sample distribution \( \text{μ}_{\bar{x}} \) is equal to the population mean \( \text{μ} \). Hence, \( \text{μ}_{\bar{x}} = 80 \).
03

Calculate the Standard Deviation of the Sample Distribution (\text{σ}_{\bar{x}})

The standard deviation of the sample distribution \( \text{σ}_{\bar{x}} \) is calculated using the formula: \[ \text{σ}_{\bar{x}} = \frac{\text{σ}}{\root n \text{n}} \] Substitute the given values into the formula: \[ \text{σ}_{\bar{x}} = \frac{14}{\root{49}} = \frac{14}{7} = 2 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

population mean
The population mean, denoted as \(\mu\), represents the average value of a particular characteristic in the entire population. In statistics, it is a critical parameter because it gives insights into the central tendency of the data.
To calculate the population mean, sum up all the values in the population data set and divide by the total number of values (N):
\[ \mu = \frac{\sum X}{N} \]
For example, with a given population mean \(\mu = 80\), it means that on average, each element in the population has a value of 80.
Understanding the population mean helps in comparing individual values to the central point and is essential for inferential statistics, like estimating the sample mean.
population standard deviation
Population standard deviation, symbolized by \(\sigma\), measures the dispersion or spread of values in the entire population. It indicates how much each value in the population deviates from the mean.
To calculate the population standard deviation:
  • Subtract the mean from each value
  • Square the result of each subtraction
  • Sum these squared differences
  • Divide by the total number of values (N)
  • Take the square root of the result
\[ \sigma = \sqrt{ \frac{\sum (X-\mu)^2}{N}} \]
For instance, given \(\sigma = 14\), it shows that on average, each value is about 14 units away from the mean.
Spreading out understanding helps gauge variability in the population—a crucial aspect when analyzing statistical data.
sample size
Sample size, represented by \(\text{n}\), is the number of observations or data points in a sample drawn from the population. It plays a vital role in the accuracy and reliability of statistical inference.
A larger sample size generally results in more reliable and accurate estimates of the population parameters because it better represents the population.
For example, with \(\text{n} = 49\), it indicates that the sample consists of 49 observations from the population.
The sample size impacts the calculations of the sample mean and the standard deviation of the sample distribution.
mean of sample distribution
The mean of the sample distribution, \(\mu_{\bar{x}} \), is the average of the sample means if you took multiple samples from the population.
Interestingly, \(\mu_{\bar{x}} \) is equal to the population mean (\mu). Thus, for our example: \[ \mu_{\bar{x}} = 80 \]
A key point to understand here is that while individual samples may have different means, the distribution of these sample means will center around the population mean.
This concept is the foundation of the Central Limit Theorem, which states that the distribution of the sample means tends to be normal (or approximately normal) as the sample size grows, regardless of the shape of the population distribution.
standard deviation of sample distribution
The standard deviation of the sample distribution, denoted \(\sigma_{\bar{x}} \), shows the spread of the sample means around the population mean. It's also known as the standard error of the mean (SEM).
It's calculated using the formula: \[ \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \]
Substituting our given values:
\[ \sigma_{\bar{x}} = \frac{14}{\sqrt{49}} = \frac{14}{7} = 2 \]
This indicates that the sample means' distribution will have a standard deviation of 2.
The standard error gives insight into the precision of the sample mean as an estimate of the population mean. Smaller values indicate more precise estimates.

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Most popular questions from this chapter

Marriage Obsolete? According to a study done by the Pew Research Center, \(39 \%\) of adult Americans believe that marriage is now obsolete. (a) Suppose a random sample of 500 adult Americans is asked whether marriage is obsolete. Describe the sampling distribution of \(\hat{p}\), the proportion of adult Americans who believe marriage is obsolete. (b) What is the probability that in a random sample of 500 adult Americans less than \(38 \%\) believe that marriage is obsolete? (c) What is the probability that in a random sample of 500 adult Americans between \(40 \%\) and \(45 \%\) believe that marriage is obsolete? (d) Would it be unusual for a random sample of 500 adult Americans to result in 210 or more who believe marriage is obsolete?

Afraid to Fly According to a study conducted by the Gallup organization, the proportion of Americans who are afraid to fly is \(0.10 .\) A random sample of 1100 Americans results in 121 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased since the time of the Gallup study.

Election Prediction Exit polling is a popular technique used to determine the outcome of an election prior to results being tallied. Suppose a referendum to increase funding for education is on the ballot in a large town (voting population over 100,000 ). An exit poll of 310 voters finds that 164 voted for the referendum. How likely are the results of your sample if the population proportion of voters in the town in favor of the referendum is 0.49 ? Based on your result, comment on the dangers of using exit polling to call elections. Include a discussion of the potential nonsampling error that could disrupt your findings.

We assume that we are obtaining simple random samples from infinite populations when obtaining sampling distributions. If the size of the population is finite, we technically need a finite population correction factor. However, if the sample size is small relative to the size of the population, this factor can be ignored. Explain what an "infinite population" is. What is the finite population correction factor? How small must the sample size be relative to the size of the population so that we can ignore the factor? Finally, explain why the factor can be ignored for such samples.

The amount of time Americans spend watching television is closely monitored by firms such as \(\mathrm{AC}\) Nielsen because this helps determine advertising pricing for commercials. (a) Do you think the variable "weekly time spent watching television" would be normally distributed? If not, what shape would you expect the variable to have? (b) According to the American Time Use Survey, adult Americans spend 2.35 hours per day watching television on a weekday. Assume that the standard deviation for "time spent watching television on a weekday" is 1.93 hours. If a random sample of 40 adult Americans is obtained, describe the sampling distribution of \(\bar{x},\) the mean amount of time spent watching television on a weekday. (c) Determine the probability that a random sample of 40 adult Americans results in a mean time watching television on a weekday of between 2 and 3 hours. (d) One consequence of the popularity of the Internet is that it is thought to reduce television watching. Suppose that a random sample of 35 individuals who consider themselves to be avid Internet users results in a mean time of 1.89 hours watching television on a weekday. Determine the likelihood of obtaining a sample mean of 1.89 hours or less from a population whose mean is presumed to be 2.35 hours. Based on the result obtained, do you think avid Internet users watch less television?

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