/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Monthly charges for cell phone p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Monthly charges for cell phone plans in the United States are normally distributed with mean \(\mu=\$ 62\) and standard deviation \(\sigma=\$ 18 .\) (a) Draw a normal curve with the parameters labeled. (b) Shade the region that represents the proportion of plans that charge less than \(\$ 44\) (c) Suppose the area under the normal curve to the left of \(x=\$ 44\) is 0.1587 . Provide two interpretations of this result.

Short Answer

Expert verified
The area under the normal curve to the left of \( \x=\$ 44 \) is 0.1587, representing approximately 15.87% of plans charging less than \( \x=\$ 44 \).

Step by step solution

01

Draw the Normal Curve

To draw the normal curve, mark the horizontal axis (x-axis) with the mean value \( \mu=\$ 62 \) at the center. Draw a bell-shaped curve centered at \( \mu=\$ 62 \), indicating the mean. The standard deviation \( \sigma=\$ 18 \) shows the spread of the curve. Label the points \( \mu \pm \sigma, \mu \pm 2\sigma, \mu \pm 3\sigma \) on the horizontal axis.
02

Locate and Shade the Region

Identify the charge amount \( \x=\$ 44 \) on the horizontal axis. Since we want to find the proportion of plans that charge less than \( \x=\$ 44 \), shade the area to the left of \( \x=\$ 44 \). The shaded region under the curve represents this proportion.
03

Interpret the Left-Side Area

Use the information that the area under the normal curve to the left of \( \x=\$ 44 \) is 0.1587. This means: 1) Approximately 15.87% of the cell phone plans charge less than \( \x=\$ 44 \). 2) If a cell phone plan is randomly selected, there is a 15.87% chance that its monthly charge is less than \( \x=\$ 44 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean
In statistics, the mean is a measure of central tendency, giving you an idea of the average value in a dataset. For example, in our exercise about cell phone plans in the United States, the mean monthly charge is denoted by \(\mu = \$ 62\). This value represents the average monthly cost of cell phone plans. To draw the normal curve, you should place this mean value at the center of the horizontal axis (x-axis). The bell-shaped curve will be symmetrical around this point. Understanding the mean is crucial because it is the reference point for interpreting the data under a normal distribution.
Standard Deviation
Standard deviation is a measure of how spread out the values in a dataset are around the mean. In our example, the standard deviation is given by \(\sigma = \$ 18\). This value shows the extent to which cell phone plan charges deviate from the average charge of \(\$ 62\). The greater the standard deviation, the more spread out the values are. Conversely, a smaller standard deviation indicates that the values are closely clustered around the mean.
When you draw a normal distribution curve, you label points on the x-axis by the mean (\(\mu\)) plus and minus the standard deviations (\(\sigma\)):
  • First standard deviation: \(\mu \pm \sigma\), in this case, \(\$ 62 \pm \$ 18 = [\$ 44, \$ 80]\)
  • Second standard deviation: \(\mu \pm 2\sigma\), here, \(\$ 62 \pm \$ 36 = [\$ 26, \$ 98]\)
  • Third standard deviation: \(\mu \pm 3\sigma\), for this example, \(\$ 62 \pm \$ 54 = [\$ 8, \$ 116]\)
These markers help you understand the spread and variability of the data around the mean.
Area Under Curve
The area under the curve in a normal distribution is essential to understanding the proportion of data points within certain ranges. Each segment of the bell curve corresponds to a probability. For example, the problem states that the area to the left of \(\$ 44\) (less than one standard deviation below the mean) is \(0.1587\), or 15.87%. This area represents the proportion of cell phone plans with charges less than \(\$ 44\) a month.
Here's how to interpret this result:
  • Approximately 15.87% of cell phone plans are cheaper than \(\$ 44\) per month.
  • If you randomly select a cell phone plan, there's a 15.87% chance that its cost will be below \(\$ 44\) per month.
To find such areas, you typically use standard normal distribution tables or calculators. These tools give you the area (or probability) related to specific z-scores. A z-score tells you how many standard deviations an element is from the mean. In our case, \(\$ 44\) is equivalent to a z-score of \(\frac{\text{\(44-\)62}}{\text{\(18\sigma\)}} = -1\).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ball bearings are manufactured with a mean diameter of 5 millimeters \((\mathrm{mm})\). Because of variability in the manufacturing process, the diameters of the ball bearings are approximately normally distributed, with a standard deviation of \(0.02 \mathrm{~mm}\) (a) What proportion of ball bearings has a diameter more than \(5.03 \mathrm{~mm} ?\) (b) Any ball bearings that have a diameter less than \(4.95 \mathrm{~mm}\) or greater than \(5.05 \mathrm{~mm}\) are discarded. What proportion of ball bearings will be discarded? (c) Using the results of part (b), if 30,000 ball bearings are manufactured in a day, how many should the plant manager expect to discard? (d) If an order comes in for 50,000 ball bearings, how many bearings should the plant manager manufacture if the order states that all ball bearings must be between \(4.97 \mathrm{~mm}\) and \(5.03 \mathrm{~mm} ?\)

True or False: The normal curve is symmetric about its mean, \(\mu .\)

Assume that the random variable \(X\) is normally distributed, with mean \(\mu=50\) and standard deviation \(\sigma=7\). Find each indicated percentile for \(X\) The 81 st percentile

Researchers conducted a prospective cohort study in which male patients who had an out-of-hospital cardiac arrest were submitted to therapeutic hypothermia (intravenous infusion of cold saline followed by surface cooling with the goal of maintaining body temperature of 33 degrees Celsius for 24 hours. Note that normal body temperature is 37 degrees Celsius). The survival status, length of stay in the intensive care unit (ICU), and time spent on a ventilator were measured. Each of these variables was compared to a historical cohort of patients who were treated prior to the availability of therapeutic hypothermia. Of the 52 hypothermia patients, 37 survived; of the 74 patients in the control group, 43 survived. The median length of stay among survivors for the hypothermia patients was 14 days versus 21 days for the control group. The time on the ventilator among survivors for the hypothermia group was 219 hours versus 328 hours for the control group. (a) What does it mean to say this is a prospective cohort study? (b) What is the explanatory variable in the study? Is it qualitative or quantitative? (c) What are the three response variables in the study? For each, state whether the variable is qualitative or quantitative. (d) Is time on the ventilator a statistic or parameter? Explain. (e) To what population does this study apply? (f) Based on the results of this study, what is the probability a randomly selected male who has an out-of-hospital cardiac arrest and submits to therapeutic hypothermia wil survive? What about those who do not submit to therapeutic hypothermia?

Find the indicated z-score. Be sure to draw a standard normal curve that depicts the solution. Find the \(z\) -score such that the area under the standard normal curve to its right is \(0.35 .\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.