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Monthly charges for cell phone plans in the United States are normally distributed with mean \(\mu=\$ 62\) and standard deviation \(\sigma=\$ 18 .\) (a) Draw a normal curve with the parameters labeled. (b) Shade the region that represents the proportion of plans that charge less than \(\$ 44\) (c) Suppose the area under the normal curve to the left of \(x=\$ 44\) is 0.1587 . Provide two interpretations of this result.

Short Answer

Expert verified
The area under the normal curve to the left of \( \x=\$ 44 \) is 0.1587, representing approximately 15.87% of plans charging less than \( \x=\$ 44 \).

Step by step solution

01

Draw the Normal Curve

To draw the normal curve, mark the horizontal axis (x-axis) with the mean value \( \mu=\$ 62 \) at the center. Draw a bell-shaped curve centered at \( \mu=\$ 62 \), indicating the mean. The standard deviation \( \sigma=\$ 18 \) shows the spread of the curve. Label the points \( \mu \pm \sigma, \mu \pm 2\sigma, \mu \pm 3\sigma \) on the horizontal axis.
02

Locate and Shade the Region

Identify the charge amount \( \x=\$ 44 \) on the horizontal axis. Since we want to find the proportion of plans that charge less than \( \x=\$ 44 \), shade the area to the left of \( \x=\$ 44 \). The shaded region under the curve represents this proportion.
03

Interpret the Left-Side Area

Use the information that the area under the normal curve to the left of \( \x=\$ 44 \) is 0.1587. This means: 1) Approximately 15.87% of the cell phone plans charge less than \( \x=\$ 44 \). 2) If a cell phone plan is randomly selected, there is a 15.87% chance that its monthly charge is less than \( \x=\$ 44 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean
In statistics, the mean is a measure of central tendency, giving you an idea of the average value in a dataset. For example, in our exercise about cell phone plans in the United States, the mean monthly charge is denoted by \(\mu = \$ 62\). This value represents the average monthly cost of cell phone plans. To draw the normal curve, you should place this mean value at the center of the horizontal axis (x-axis). The bell-shaped curve will be symmetrical around this point. Understanding the mean is crucial because it is the reference point for interpreting the data under a normal distribution.
Standard Deviation
Standard deviation is a measure of how spread out the values in a dataset are around the mean. In our example, the standard deviation is given by \(\sigma = \$ 18\). This value shows the extent to which cell phone plan charges deviate from the average charge of \(\$ 62\). The greater the standard deviation, the more spread out the values are. Conversely, a smaller standard deviation indicates that the values are closely clustered around the mean.
When you draw a normal distribution curve, you label points on the x-axis by the mean (\(\mu\)) plus and minus the standard deviations (\(\sigma\)):
  • First standard deviation: \(\mu \pm \sigma\), in this case, \(\$ 62 \pm \$ 18 = [\$ 44, \$ 80]\)
  • Second standard deviation: \(\mu \pm 2\sigma\), here, \(\$ 62 \pm \$ 36 = [\$ 26, \$ 98]\)
  • Third standard deviation: \(\mu \pm 3\sigma\), for this example, \(\$ 62 \pm \$ 54 = [\$ 8, \$ 116]\)
These markers help you understand the spread and variability of the data around the mean.
Area Under Curve
The area under the curve in a normal distribution is essential to understanding the proportion of data points within certain ranges. Each segment of the bell curve corresponds to a probability. For example, the problem states that the area to the left of \(\$ 44\) (less than one standard deviation below the mean) is \(0.1587\), or 15.87%. This area represents the proportion of cell phone plans with charges less than \(\$ 44\) a month.
Here's how to interpret this result:
  • Approximately 15.87% of cell phone plans are cheaper than \(\$ 44\) per month.
  • If you randomly select a cell phone plan, there's a 15.87% chance that its cost will be below \(\$ 44\) per month.
To find such areas, you typically use standard normal distribution tables or calculators. These tools give you the area (or probability) related to specific z-scores. A z-score tells you how many standard deviations an element is from the mean. In our case, \(\$ 44\) is equivalent to a z-score of \(\frac{\text{\(44-\)62}}{\text{\(18\sigma\)}} = -1\).

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