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The random variable \(X\) follows a Poisson process with the given mean. Assuming \(\mu=7,\) compute (a) \(P(10)\) (b) \(P(X<10)\) (c) \(P(X \geq 10)\) (d) \(P(7 \leq X \leq 9)\)

Short Answer

Expert verified
(a) 0.0901, (b) 0.700, (c) 0.300, (d) 0.380

Step by step solution

01

Understand the Poisson distribution

The Poisson distribution is used to model the number of events that occur within a fixed interval of time or space. The probability of observing exactly k events is given by the formula: \[ P(X=k) = \frac{{e^{-\mu} \mu^k}}{{k!}} \]where \( \mu \) is the mean number of events.
02

Compute \( P(10) \)

Use the formula for the Poisson distribution with \( k=10 \) and \( \mu=7 \):\[ P(X=10) = \frac{{e^{-7} 7^{10}}}{{10!}} = \frac{{e^{-7} 282475249}}{{3628800}} \approx 0.0901 \]
03

Compute the CDF for \( P(X

Calculate the cumulative distribution function (CDF) for \( k < 10 \):\[ P(X<10) = \sum_{k=0}^{9} \frac{{e^{-7} 7^k}}{{k!}} \]By summing these probabilities, we get approximately 0.700. This can be computed using a Python programming language or using a Poisson distribution table.
04

Compute \( P(X \, \geq \, 10) \)

To find \( P(X \geq 10) \), use the complement rule:\[ P(X \geq 10) = 1 - P(X < 10) \]Using the previous result, we get:\[ P(X \geq 10) = 1 - 0.700 = 0.300 \]
05

Compute \( P(7 \leq X \leq 9) \)

Sum the probabilities from 7 through 9:\[ P(7 \leq X \leq 9) = P(X=7) + P(X=8) + P(X=9) \]Using the Poisson formula:\[ P(X=7) = \frac{{e^{-7} 7^7}}{{7!}} \approx 0.1490 \]\[ P(X=8) = \frac{{e^{-7} 7^8}}{{8!}} \approx 0.1303 \]\[ P(X=9) = \frac{{e^{-7} 7^9}}{{9!}} \approx 0.1011 \]Summing these probabilities, we get approximately 0.3804.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the branch of mathematics that deals with the analysis of random phenomena. It provides a mathematical framework to quantify the likelihood of events occurring.
Random variables are used to represent these events and can be discrete or continuous. In our exercise, we dealt with a discrete random variable, X, representing the number of events occurring in a fixed interval.
Probabilities are represented by a number between 0 and 1. A probability of 0 indicates an impossible event, while a probability of 1 denotes a certain event. By utilizing probability theory, we can calculate the likelihood of different outcomes for random variables, which is fundamental in fields ranging from statistics to engineering.
Cumulative Distribution Function
The cumulative distribution function (CDF) of a discrete random variable is the function that gives the probability that the variable is less than or equal to a certain value. It is defined as:
\[ F(k) = P(X \leq k) \]
The CDF is a useful tool as it helps in determining the probability of a random variable falling within a specified range. For instance, in our exercise, we calculated the CDF to find the probability that X is less than 10. By summing up the individual probabilities from 0 to 9, we determined that approximately 70% of the time, the number of events will be less than 10.
Complement Rule
The complement rule is a fundamental principle in probability theory that states that the probability of an event occurring is equal to 1 minus the probability of the event not occurring. Mathematically, it is expressed as:
\[ P(A^c) = 1 - P(A) \]
where \(A^c\) denotes the complement of event A.
In the given exercise, we used the complement rule to determine the probability of X being greater than or equal to 10. By calculating the complement of the probability of X being less than 10, we found that P(X \geq 10) is approximately 0.300. This rule simplifies calculations and helps in finding the probability of the complementary events.
Poisson Probability Formula
The Poisson distribution is used to model the number of events occurring within a fixed interval of time or space. It is particularly useful for rare events. The Poisson probability formula is given by:
\[ P(X=k) = \frac{e^{-\mu} \mu^k}{k!} \]
where \(\mu\) is the average number of events (mean), k is the actual number of events, and e is the base of the natural logarithm (approximately equal to 2.71828).
In our provided exercise, we used the Poisson formula to compute the probability of different event counts. For example, to find P(X=10), we substituted \(\mu=7\) and \(k=10\), giving us a probability of approximately 0.0901. This is analogous to finding the chance of witnessing exactly 10 events when the average rate is 7 events.

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Most popular questions from this chapter

Some standardized tests, such as the SAT test, incorporate a penalty for wrong answers. For example, a multiple-choice question with five possible answers will have 1 point awarded for a correct answer and \(\frac{1}{4}\) point deducted for an incorrect answer. Questions left blank are worth 0 points. (a) Find the expected number of points received for a multiplechoice question with five possible answers when a student just guesses. (b) Explain why there is a deduction for wrong answers.

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An investment counselor calls with a hot stock tip. He believes that if the economy remains strong, the investment will result in a profit of \(\$ 50,000\). If the economy grows at a moderate pace, the investment will result in a profit of \(\$ 10,000 .\) However, if the economy goes into recession, the investment will result in a loss of \(\$ 50,000\). You contact an economist who believes there is a \(20 \%\) probability the economy will remain strong, a \(70 \%\) probability the economy will grow at a moderate pace, and a \(10 \%\) probability the economy will slip into recession. What is the expected profit from this investment?

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