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According to flightstats.com, American Airlines flights from Dallas to Chicago are on time \(80 \%\) of the time. Suppose 15 flights are randomly selected, and the number of on-time flights is recorded. (a) Explain why this is a binomial experiment. (b) Find and interpret the probability that exactly 10 flights are on time. (c) Find and interpret the probability that fewer than 10 flights are on time. (d) Find and interpret the probability that at least 10 flights are on time. (e) Find and interpret the probability that between 8 and 10 flights, inclusive, are on time.

Short Answer

Expert verified
This problem is binomial. P(X=10)=0.2013. P(X<10)=0.2311. P(X≥10)=0.7689. P(8≤X≤10)=0.4481.

Step by step solution

01

Define the binomial experiment

A binomial experiment consists of n independent trials with two possible outcomes: success and failure. In this case, each flight is a trial, with 'on-time' being a success and 'not on-time' being a failure. The probability of success is 0.8, and each of the 15 flights represents an independent trial.
02

Set up the binomial formula for part (b)

The probability of exactly k successes (on-time flights) out of n trials is given by the binomial formula: \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \) For this case, n=15, k=10, and p=0.8. Substitute these values in the formula.
03

Calculate the probability for exactly 10 flights

\[ P(X = 10) = \binom{15}{10} (0.8)^{10} (0.2)^{5} \] Calculate this using a calculator or binomial probability table.
04

Interpret the result for part (b)

The resulting probability provides the likelihood that exactly 10 out of the 15 flights will be on time. This gives us an idea of how likely it is for that specific number of flights to be punctual.
05

Use a cumulative probability function for part (c)

To find the probability that fewer than 10 flights are on time, sum the probabilities of 0 through 9 flights being on time: \[ P(X < 10) = \binom{15}{0} (0.8)^0 (0.2)^{15} + \binom{15}{1} (0.8)^1 (0.2)^{14} + ... + \binom{15}{9} (0.8)^9 (0.2)^6 \] Use a cumulative distribution function calculator or table.
06

Interpret the result for part (c)

The calculated probability indicates the likelihood that fewer than 10 of the 15 flights will be on time, helping to understand how often delays might occur.
07

Use cumulative probability for part (d)

For the probability that at least 10 flights are on time: \[ P(X \text{≥} 10) = 1 - P(X < 10) \] Use the result from part (c) to find this value.
08

Interpret the result for part (d)

The resulting probability shows the likelihood that 10 or more flights will be on time, providing insight into the reliability of the flights.
09

Calculate for part (e)

For the probability that between 8 and 10 flights, inclusive, are on time: \[ P(8 \text{≤} X \text{≤} 10) = P(X = 8) + P(X = 9) + P(X = 10) \] Calculate using the binomial formula for k=8, 9 and 10, then sum the results.
10

Interpret the result for part (e)

This probability gives the likelihood that the number of on-time flights falls within the range of 8 to 10, inclusive, offering another measure of punctuality performance.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Probability Distribution
When dealing with situations that involve success or failure outcomes, the binomial probability distribution is your go-to tool. It is particularly handy when you need to determine the likelihood of a certain number of successful outcomes out of a fixed number of independent trials. For example, if you are looking at flights being on time or delayed, and you know the probability of a flight being on time, you can use the binomial probability distribution to find out how many flights are likely to be on time.
The binomial distribution can be easily recognized because:
  • There are a fixed number of trials (n). In our case, 15 flights.
  • The trials are independent of each other.
  • Each trial has two possible outcomes: success (on-time) or failure (not on-time).
  • The probability of success (p) is constant across trials.
This specific situation with the 15 flights fits into a binomial distribution, where the probability of a flight being on time (success) is 0.8.
Cumulative Distribution Function
The Cumulative Distribution Function (CDF) helps you figure out the probability that a random variable will be less than or equal to a certain value. For example, if you want to know the probability that fewer than 10 flights out of 15 are on time, you can sum the probabilities of having 0, 1, 2,..., up to 9 flights on time. The formula looks intimidating at first, but it’s manageable with a calculator or cumulative binomial probability table.
In our case, you will calculate:
\[ P(X < 10) = \sum_{k=0}^{9} \binom{15}{k} (0.8)^k (0.2)^{15-k} \]
Here, you add up the individual probabilities from having 0 flights on time up to 9 flights on time.
This cumulative probability gives a clearer picture because it tells you the overall likelihood of having a range of outcomes.
Binomial Formula
The binomial formula is central to solving problems related to binomial experiments. This formula calculates the probability of getting exactly k successes (for example, on-time flights) out of n trials:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
Where:
  • \(\binom{n}{k}\) is the binomial coefficient, calculated as \( \frac{n!}{k!(n-k)!} \).
  • n is the total number of trials.
  • k is the number of successes.
  • p is the probability of success on any given trial.
  • (1-p) is the probability of failure.
Using this formula, we can find the probability of any specific outcome. For example, to find the probability that exactly 10 out of 15 flights are on time:
\[ P(X = 10) = \binom{15}{10} (0.8)^{10} (0.2)^{5} \]
This formula is incredibly powerful for calculating the likelihood of various outcomes in a binomial distribution.
Probability Interpretation
Interpreting probabilities helps you understand the practical implications of your calculations. For example, when you find that the probability of exactly 10 out of 15 flights being on time is 0.2013 (after calculation), it means there is approximately a 20.13% chance of this happening. Similarly:
  • If you interpret a CDF of fewer than 10 flights being on time (e.g., 30%), it indicates that 30 out of 100 times, you can expect fewer than 10 on-time flights.
  • For probabilities like at least 10 flights on time, it involves subtracting the cumulative probability of fewer than 10 flights from 1. This shows the complementary understanding of events (at least scenarios are always 1 – less than scenarios).
  • For a range, like between 8 and 10 flights being on time, you sum the individual probabilities for having 8, 9, and 10 on-time flights.
This layering understanding helps you interpret real-world situations using probability in a meaningful way.
Independent Trials
Understanding independent trials is crucial for binomial experiments. Independent trials mean that the outcome of one trial does not affect the outcome of another. For example, whether one flight is on time or late does not influence whether another flight will be on time or late. This independence is a key assumption in binomial experiments.
In our case of flights, independence means:
  • The probability of a flight being on time (0.8) remains the same for each of the 15 flights.
  • The outcome of each flight’s punctuality is determined independently of the others.
Ensuring trials are truly independent allows you to rely on the binomial distribution and its associated calculations. It ensures the probabilities you calculate using the binomial formula are accurate and meaningful.

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