/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 (a) construct a binomial probabi... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) construct a binomial probability distribution with the given parameters; (b) compute the mean and standard deviation of the random variable using the methods of Section \(6.1 ;\) (c) compute the mean and standard deviation, using the methods of this section; and \((d)\) draw a graph of the probability distribution and comment on its shape. $$ n=8, p=0.5 $$

Short Answer

Expert verified
Construct probability distribution, mean = 4, standard deviation ≈ 1.41, symmetric distribution graph.

Step by step solution

01

Construct the Binomial Probability Distribution

For a binomial distribution, the probability of exactly k successes in n trials is given by the formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( n = 8 \), \( p = 0.5 \), and \( k \) ranges from 0 to 8. Calculate \( P(X = k) \) for each value of \( k \).
02

Compute the Mean of the Random Variable

The mean (expected value) of a binomial distribution is given by the formula: \[ \text{Mean} ( \text{or } \text{expected value} ) = E(X) = n \times p \] Substitute \( n = 8 \) and \( p = 0.5 \) into this formula to find the mean.
03

Compute the Standard Deviation of the Random Variable

The standard deviation of a binomial distribution is given by the formula: \[ \text{Standard Deviation} = \text{SD}(X) = \sqrt{n \times p \times (1-p)} \] Substitute \( n = 8 \) and \( p = 0.5 \) into this formula to find the standard deviation.
04

Draw and Comment on the Graph of the Probability Distribution

Plot the probabilities from Step 1 on a graph with the x-axis representing the number of successes \( k \) and the y-axis representing the probability \( P(X = k) \). Since \( p = 0.5 \), the distribution will be symmetric around the mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mean of random variables
In any probability distribution, the mean—or expected value—is a measure of the central tendency. For a binomial distribution, the mean is calculated using the formula: \[ E(X) = n \times p \] This tells us the average number of successes we can expect in \( n \) trials with a success probability \( p \).
In our exercise, with \( n = 8 \) and \( p = 0.5 \), we find: \[ E(X) = 8 \times 0.5 = 4 \]
This means, on average, we can expect 4 successes in 8 trials. Understanding the mean allows you to grasp the center of the binomial distribution.
standard deviation of binomial distribution
Standard deviation measures the amount of variability or spread in a set of data. For a binomial distribution, it's given by the formula: \[ \text{SD}(X) = \sqrt{n \times p \times (1 - p)} \] Substituting our values \( n = 8 \) and \( p = 0.5 \), we get: \[ \text{SD}(X) = \sqrt{8 \times 0.5 \times 0.5} = \sqrt{2} \approx 1.41 \]
This standard deviation value tells us how much the number of successes will typically vary from the mean of 4. Knowing the standard deviation helps in understanding the spread and reliability of the data.
graphing probability distributions
Visualizing the binomial probability distribution can provide deeper insights into the data. To graph the distribution, you plot each calculated probability for \( k = 0, 1, 2, ..., 8 \) against the number of successes.
  • The x-axis represents the number of successes \( k \)
  • The y-axis represents the probability \( P(X = k) \)

Given that \( p = 0.5 \), our distribution will be symmetric around the mean of 4. This symmetry is due to the equal likelihood of success and failure. Graphing helps to visualize the bell shape and understand the distribution's behavior.
probability calculations
Calculating probabilities in a binomial distribution involves using the formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] Here, \( \binom{n}{k} \) is the binomial coefficient representing the number of ways to choose \( k \) successes out of \( n \) trials. With \( n = 8 \) and \( p = 0.5 \), you compute this for \( k \ \text{from} \ 0 \ \text{to} \ 8 \).
For example, for \( k = 4 \): \[ P(X = 4) = \binom{8}{4} (0.5)^4 (1-0.5)^{4} \] This simplifies to: \[ P(X = 4) = 70 \times 0.0625 \times 0.0625 = 0.2734375 \] Calculating these probabilities for all values of \( k \) allows you to build the complete probability distribution. Understanding these calculations is crucial for working with binomial models.

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Most popular questions from this chapter

According to flightstats.com, American Airlines flights from Dallas to Chicago are on time \(80 \%\) of the time. Suppose 15 flights are randomly selected, and the number of on-time flights is recorded. (a) Explain why this is a binomial experiment. (b) Find and interpret the probability that exactly 10 flights are on time. (c) Find and interpret the probability that fewer than 10 flights are on time. (d) Find and interpret the probability that at least 10 flights are on time. (e) Find and interpret the probability that between 8 and 10 flights, inclusive, are on time.

The random variable \(X\) follows a Poisson process with the given value of \(\lambda\) and \(t\). Assuming \(\lambda=0.07\) and \(t=10\), compute (a) \(P(4)\) (b) \(P(X<4)\) (c) \(P(X \geq 4)\) (d) \(P(4 \leq X \leq 6)\) (e) \(\mu_{X}\) and \(\sigma_{X}\)

Determine the required value of the missing probability to make the distribution a discrete probability distribution. $$ \begin{array}{cc} x & P(x) \\ \hline 3 & 0.4 \\ \hline 4 & ? \\ \hline 5 & 0.1 \\ \hline 6 & 0.2 \\ \hline \end{array} $$

The phone calls to a computer software help desk occur at the rate of 2.1 per minute between 3:00 p.m. and 4:00 p.m. Compute the probability that the number of calls between 3:10 p.m. and 3:15 p.m. is (a) exactly eight. Interpret the result. (b) fewer than eight. Interpret the result. (c) at least eight. Interpret the result.

Televisions In the Sullivan Statistics Survey I, individuals were asked to disclose the number of televisions in their household. In the following probability distribution, the random variable \(X\) represents the number of televisions in households. $$ \begin{array}{cl} \text { Number of Televisions, } x & P(x) \\ \hline 0 & 0 \\ \hline 1 & 0.161 \\ \hline 2 & 0.261 \\ \hline 3 & 0.176 \\ \hline 4 & 0.186 \\ \hline 5 & 0.116 \\ \hline 6 & 0.055 \\ \hline 7 & 0.025 \\ \hline 8 & 0.010 \\ \hline 9 & 0.010 \\ \hline \end{array} $$ (a) Verify this is a discrete probability distribution. (b) Draw a graph of the probability distribution. Describe the shape of the distribution. (c) Determine and interpret the mean of the random variable \(X\). (d) Determine the standard deviation of the random variable \(X\). (e) What is the probability that a randomly selected household has three televisions? (f) What is the probability that a randomly selected household has three or four televisions? (g) What is the probability that a randomly selected household has no televisions? Would you consider this to be an impossible event?

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