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Determine the required value of the missing probability to make the distribution a discrete probability distribution. $$ \begin{array}{ll} x & P(x) \\ \hline 0 & 0.30 \\ \hline 1 & 0.15 \\ \hline 2 & ? \\ \hline 3 & 0.20 \\ \hline 4 & 0.15 \\ \hline 5 & 0.05 \\ \hline \end{array} $$

Short Answer

Expert verified
The missing probability is 0.15.

Step by step solution

01

- Understand the Problem

In a discrete probability distribution, the sum of all probabilities must equal 1.
02

- Write Down Known Probabilities

List the given probabilities:\[ P(0) = 0.30 \]\[ P(1) = 0.15 \]\[ P(3) = 0.20 \]\[ P(4) = 0.15 \]\[ P(5) = 0.05 \]
03

- Calculate the Sum of Known Probabilities

Add up the known probabilities:\[ 0.30 + 0.15 + 0.20 + 0.15 + 0.05 = 0.85 \]
04

- Determine the Missing Probability

Since the total sum should be 1, subtract the sum of known probabilities from 1 to find the missing probability:\[ P(2) = 1 - 0.85 = 0.15 \]
05

- Verify the Solution

Check the sum of all probabilities, including the calculated one, to ensure it equals 1:\[ 0.30 + 0.15 + 0.15 + 0.20 + 0.15 + 0.05 = 1 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sum of probabilities
In a discrete probability distribution, one of the fundamental principles we need to understand is that the sum of probabilities must always equal 1. This requirement ensures the probabilities cover all potential outcomes within our defined scenario. So, whenever we encounter a problem involving probabilities, we can use this principle to verify if our distribution is correct. For instance, if you're given probabilities for certain outcomes and one is missing, you can find the missing probability by ensuring the total sum is exactly 1.

In our example exercise, we are given probabilities for certain values and one is missing. The known probabilities are listed out, and by adding them together, we approach solving the problem:

  • Step 1: Add up the known probabilities: 0.30 + 0.15 + 0.20 + 0.15 + 0.05 = 0.85
  • Step 2: Then use the total sum concept: Total should be 1, so missing probability = 1 - 0.85 = 0.15
missing probability
A common type of problem with probability distributions asks you to find a missing probability in a dataset. Once you have the sum of all known probabilities, discovering the missing one becomes straightforward. This method relies entirely on the principle that the sum must be 1.
To find the missing probability, follow these steps:

  • Identify and list all given probabilities.
  • Add all the known probabilities together.
  • Subtract this sum from 1 to find the missing probability.
In our exercise, the missing probability was for the value x = 2. By summing the other probabilities (0.85) and subtracting from 1, we determined the missing probability to be 0.15.
total probability equals one
The rule that the total probability of all possible outcomes must equal one is crucial in probability theory. This ensures the distribution is valid and complete. No outcome is missed, and no extra probabilities exist.
This means every event considered in the discrete probability distribution is accounted for, thereby enforcing consistency and reliability in probability calculations.
For instance, in our given problem:
  • We summed the given probabilities: 0.30, 0.15, 0.20, 0.15, 0.05.
  • We concluded the sum equals 0.85.
  • By knowing the total must be 1, we easily found the missing probability: 1 - 0.85 = 0.15.
This ensures our distribution is correct and follows the rule that the sum of all probabilities must be exactly one.
probability calculations
Probability calculations are essential skills in dealing with probability distributions. They include adding probabilities, verifying sums, and determining missing values to ensure a valid distribution.
Let's break down a typical calculation process we've used:
  • First, list all known probabilities.
  • Then, add these probabilities to find their sum.
  • To verify the completeness of your probability distribution, ensure the sum is exactly 1.
  • If a probability is missing, subtract the sum of known probabilities from 1 to find the missing one.
In our exercise, we demonstrated this effectively by first identifying sum of known probabilities as 0.85, then determining the missing probability by the equation: P(2) = 1 - 0.85 = 0.15. Always keep these steps in mind when performing probability calculations to ensure accurate and reliable results.

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Most popular questions from this chapter

Determine which of the following probability experiments represents a binomial experiment. If the probability experiment is not a binomial experiment, state why. An experimental drug is administered to 100 randomly selected individuals, with the number of individuals responding favorably recorded.

A probability distribution for the random variable \(X,\) the number of trials until a success is observed, is called the geometric probability distribution. It has the same criteria as the binomial distribution (see page 328 ), except that the number of trials is not fixed. Its probability distribution function (pdf) is $$ P(x)=p(1-p)^{x-1}, \quad x=1,2,3, \ldots $$ where \(p\) is the probability of success. (a) What is the probability that Shaquille O'Neal misses his first two free throws and makes the third? Over his career, he made \(52.4 \%\) of his free throws. That is, find \(P(3)\) (b) Construct a probability distribution for the random variable \(X,\) the number of free-throw attempts of Shaquille O'Neal until he makes a free throw. Construct the distribution for \(x=1,2,3, \ldots, 10 .\) The probabilities are small for \(x>10\) (c) Compute the mean of the distribution, using the formula presented in Section 6.1 (d) Compare the mean obtained in part (c) with the value \(\frac{1}{p}\). Conclude that the mean of a geometric probability distribution is \(\mu_{X}=\frac{1}{p} .\) How many free throws do we expect Shaq to take before we observe a made free throw?

The number of hits to a website follows a Poisson process and occurs at the rate of 10 hits per minute between 7:00 P.M. and 9: 00 P.M. How long should you expect to wait before the probability of at least 1 hit to the site is \(95 \%\) ?

According to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will cover his or her mouth with a tissue, handkerchief, or elbow (the method recommended by public health officials) when sneezing is \(0.047 .\) Suppose you sit on a bench in a mall and observe people's habits as they sneeze. (a) What is the probability that among 15 randomly observed sneezing individuals exactly 2 cover their mouth with a tissue, handkerchief, or elbow? (b) What is the probability that among 15 randomly observed sneezing individuals fewer than 3 cover their mouth with a tissue, handkerchief, or elbow? (c) Would you be surprised if, after observing 15 sneezing individuals, more than 4 covered the mouth with a tissue, handkerchief, or elbow?

Determine which of the following probability experiments represents a binomial experiment. If the probability experiment is not a binomial experiment, state why. In a town with 400 citizens, 100 randomly selected citizens are asked to identify their religion. The number who identify with a Christian religion is recorded.

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