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How many different simple random samples of size 7 can be obtained from a population whose size is 100?

Short Answer

Expert verified
There are 16,007,560,800 different simple random samples of size 7 from a population of 100.

Step by step solution

01

- Understand the Concept

To solve this problem, it's important to understand what a simple random sample is. A simple random sample means each subset of the population has an equal probability of being chosen.
02

- Use the Combination Formula

The number of different simple random samples can be calculated using the combination formula \( C(n, k) = \frac{n!}{k!(n-k)!} \), where \(n\) is the population size and \(k\) is the sample size. Here, \(n = 100\) and \(k = 7\).
03

- Calculate Factorials

Calculate the factorial for each term in the combination formula. \(100!\) is the factorial of 100, \(7!\) is the factorial of 7, and \(93!\) is the factorial of 93.
04

- Apply the Combination Formula

Substitute the factorial values into the combination formula: \[ C(100, 7) = \frac{100!}{7!(100-7)!} = \frac{100!}{7! \cdot 93!} \]
05

- Simplify the Result

Use a calculator or software to simplify and find the final value of the combination formula. This will provide the number of different simple random samples.
06

- Conclude the Solution

The number of different simple random samples of size 7 that can be obtained from a population of 100 is the result obtained in Step 5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination Formula
To determine the number of different simple random samples, you need the combination formula. This formula is essential for calculating how many ways you can choose a sample of items from a larger set without regard to the order. The combination formula is represented as: i) \( C(n, k) = \frac{n!}{k!(n-k)!} \) Where: n) \(n\) is the population size k) \(k\) is the sample size ii) For our case, you have a population size of 100, and you need a sample size of 7. Hence, \(C(100, 7)\) is what you are solving. When using the formula, it is also important to substitute the values correctly. This helps in getting the accurate count of different possible samples.
Factorials
Factorials play a crucial role in computing combinations. A factorial, denoted by an exclamation mark (!), is the product of all positive integers up to a certain number. For example: i) The factorial of 5, written as \(5!\), is calculated as: \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] ii) To solve \(C(100, 7)\), you will be calculating three factorials: \(100!\), \(7!\), and \(93!\). \(100!\) is the multiplication of all numbers from 100 down to 1, which is a massive number. Factorials grow rapidly with larger numbers and are best computed using a calculator or specific software. Remember, understanding factorials makes it easier to handle problems involving combinations.
Sample Size Selection
The size of the sample chosen represents the number of items you want to pick out from a larger population. For simple random sampling: i) Each item in the population has an equal chance of being selected. ii) In our example, the sample size (\(k\)) is 7, and the population size (\(n\)) is 100. It is important to decide on the sample size carefully to ensure that the sample accurately represents the population. The sample size used influences the precision of your results. Simple random sampling can be depicted as drawing 7 items from a bag containing 100 items, where each selection is independent of the others.

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Most popular questions from this chapter

In the game Text Twist, six letters are given and the player must form words of varying lengths using the letters provided. Suppose that the letters in a particular game are ENHSIC. (a) How many different arrangements are possible using all 6 letters? (b) How many different arrangements are possible using only 4 letters? (c) The solution to this game has three 6 -letter words. To advance to the next round, the player needs at least one of the six-letter words. If the player simply guesses, what is the probability that he or she will get one of the six-letter words on their first guess of six letters?

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