/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 In the game of roulette, a wheel... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the game of roulette, a wheel consists of 38 slots numbered \(0,00,1,2, \ldots, 36\). (See the photo.) To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots. (a) Determine the sample space. (b) Determine the probability that the metal ball falls into the slot marked eight. Interpret this probability. (c) Determine the probability that the metal ball lands in an odd slot. Interpret this probability.

Short Answer

Expert verified
Sample space is \( \{0, 00, 1, 2, \ldots, 36\} \). Probability of landing on 8 is \frac{1}{38}\. Probability of landing in an odd slot is \frac{9}{19}\.

Step by step solution

01

Determine the Sample Space

The sample space, denoted as S, includes all possible outcomes of the roulette wheel. Here, the wheel has 38 slots, which are numbered \(0, 00, 1, 2, \ldots, 36\). Therefore, the sample space is: \[ S = \{0, 00, 1, 2, 3, \ldots, 36\} \].
02

Find the Probability of Landing on Eight

To find the probability that the ball falls into the slot marked eight, use the formula for probability, which is \(\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}\). There is only one slot marked eight, and there are 38 slots in total. Therefore, the probability is: \[ P(8) = \frac{1}{38} \]. This means there's a 1/38 chance, or approximately 0.0263, that the ball will land on the slot marked eight.
03

Probability of Landing in an Odd Slot

To determine the probability that the ball lands in an odd slot, first count the total number of odd slots. The odd numbers from 1 to 36 are 1, 3, 5, \ldots, 35, making a total of 18 odd numbers. Including the slots 0 and 00, there are 38 total slots. Thus, the probability is: \[ P(\text{Odd}) = \frac{18}{38} = \frac{9}{19} \]. This means there's a \frac{9}{19} chance, or approximately 0.4737, that the ball will land in an odd slot.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Space
In the game of roulette, understanding the sample space is crucial. The sample space represents all possible outcomes from spinning the wheel and dropping the ball. In this game, the wheel has 38 slots, each marked with numbers ranging from 0 to 36, including a '00'. This makes the set of all possible outcomes:
  • 0
  • 00
  • 1
  • 2
  • 3
  • ...
  • 36
The sample space, denoted as S, can therefore be written as:

\[ S = \{0, 00, 1, 2, 3, \ldots, 36\} \].

Understanding this is vital because it forms the foundation for calculating probabilities in the game of roulette.
Probability Calculation
Calculating probability in roulette involves determining the likelihood of a specific event occurring out of all possible outcomes. To do this, use the formula:

\[ P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \]

For example, if we want to find the probability that the ball lands in the slot marked eight, we first note that there is only one slot marked eight out of the 38 slots available. So, the probability is:

\[ P(8) = \frac{1}{38} \]

This translates into decimal form as approximately 0.0263 or 2.63%. Similarly, to find the probability that the ball will land in any odd-numbered slot, you have to count the odd-numbered slots from 1 to 36, which total 18 odd numbers. Applying the same formula gives:

\[ P(\text{Odd}) = \frac{18}{38} = \frac{9}{19} \]

This is approximately 0.4737 or 47.37%.
Interpretation of Probability
Understanding the interpretation of probability helps in grasping what these numbers mean in real-world scenarios. When we found that the probability of the ball landing on the number eight is \( \frac{1}{38} \), it means there is roughly a 2.63% chance for the ball to fall into that exact slot. If you played 38 spins, you'd expect the ball to land on eight roughly once. For the probability of landing in an odd-numbered slot, which we calculated as \( \frac{9}{19} \), it means there is a 47.37% chance for the ball to land on any odd slot. This is almost a 50-50 chance, roughly expecting the ball to land on an odd number in half of the spins. By interpreting these probabilities, you can better understand the randomness and outcomes of the game.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

False Positives The ELISA is a test to determine whether the HIV antibody is present. The test is \(99.5 \%\) effective, which means that the test will come back negative if the HIV antibody is not present \(99.5 \%\) of the time. The probability of a test coming back positive when the antibody is not present (a false positive) is \(0.005 .\) Suppose that the ELISA is given to five randomly selected people who do not have the HIV antibody. (a) What is the probability that the ELISA comes back negative for all five people? (b) What is the probability that the ELISA comes back positive for at least one of the five people?

In finance, a derivative is a financial asset whose value is determined (derived) from a bundle of various assets, such as mortgages. Suppose a randomly selected mortgage has a probability of 0.01 of default. (a) What is the probability a randomly selected mortgage will not default (that is, pay off)? (b) What is the probability a bundle of five randomly selected mortgages will not default assuming the likelihood any one mortgage being paid off is independent of the others? Note: A derivative might be an investment in which all five mortgages do not default. (c) What is the probability the derivative becomes worthless? That is, at least one of the mortgages defaults? (d) In part (b), we made the assumption that the likelihood of default is independent. Do you believe this is a reasonable assumption? Explain.

The probability that a randomly selected individual in the United States 25 years and older has at least a bachelor's degree is \(0.094 .\) The probability that an individual in the United States 25 years and older has at least a bachelor's degree, given that the individual lives in Washington \(\mathrm{DC},\) is, \(0.241 .\) Are the events "bachelor's degree" and "lives in Washington, DC," independent?

A certain digital music player randomly plays each of 10 songs. Once a song is played, it is not repeated until all the songs have been played. In how many different ways can the player play the 10 songs?

Suppose that you roll a pair of dice 1000 times and get seven 350 times. Based on these results, what is the probability that the next roll results in seven?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.