/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 A committee consisting of four w... [FREE SOLUTION] | 91Ó°ÊÓ

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A committee consisting of four women and three men will randomly select two people to attend a conference in Hawaii. Find the probability that both are women.

Short Answer

Expert verified
The probability that both selected people are women is \(\frac{2}{7}\).

Step by step solution

01

- Determine the Total Number of People

Add the number of women and men on the committee: 4 women + 3 men = 7 people.
02

- Calculate the Total Number of Ways to Select Two People

To choose 2 people out of 7, use the combination formula: \[ \binom{7}{2} = \frac{7!}{2!(7-2)!} = \frac{7 \times 6}{2 \times 1} = 21 \]
03

- Calculate the Number of Ways to Select Two Women

To choose 2 women out of 4, use the combination formula: \[ \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \]
04

- Find the Probability that Both Selected People are Women

The probability is the number of ways to select two women divided by the total number of ways to select two people: \[ P(\text{Both are women}) = \frac{\binom{4}{2}}{\binom{7}{2}} = \frac{6}{21} = \frac{2}{7} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination formula
In probability and combinatorics, the combination formula is used to determine the number of ways to select a specific number of items from a larger set. The formula is represented as \binom{n}{k}\, where \ is the total number of items, and \k\ is the number of items to select.
For example, if you have 7 people and want to select 2, we write it as \binom{7}{2}\. The formula itself is: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] Here, \!\ (n factorial) means multiplying all whole numbers from \ down to 1.
In the given exercise, to find the number of ways to select 2 people out of 7, we used the combination formula: \[ \binom{7}{2} = \frac{7!}{2! \/ (7-2)!} = \frac{7 \times 6}{2 \times 1} = 21 \] You can see how factorials simplify and cancel out in the division process. This is how we determine there are 21 ways to select 2 people from 7.
Probability calculation
Once we know the total number of ways to select 2 people, we can calculate the probability of selecting 2 specific people, such as 2 women. Probability is essentially a fraction with:
  • The number of favorable outcomes on top
  • The total number of possible outcomes on the bottom
To find the probability that both people selected are women, we first calculate \binom{4}{2}\, the number of ways to select 2 women out of 4. This results in: \[ \binom{4}{2} = \frac{4!}{2! \/ (4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \] Now, we divide the number of favorable outcomes by the total possible outcomes: \[ P(\text{Both are women}) = \frac{ \binom{4}{2} }{ \binom{7}{2} } = \frac{6}{21} = \frac{2}{7} \] So, the probability is \frac{2}{7}\, meaning there's roughly a 28.57% chance of selecting 2 women.
Combinatorics
Combinatorics is a branch of mathematics dealing with counting, arrangement, and combination of objects. It heavily uses the concept of combinations and permutations.
In this exercise, we use combinatorics to find different ways to select people from a group. Applying the combination formula helps solve real-world problems in fields like statistics, computer science, and operations research.
The exercise shows how combinatorics answers questions about arranging a committee, selecting team members, or any scenario needing calculated choices. It simplifies complex counting processes using established formulas and principles. By understanding the basics of combinatorics, students can tackle various selection, arrangement, and probability problems effortlessly.

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Most popular questions from this chapter

In Mega Millions, an urn contains balls numbered 1–56, and a second urn contains balls numbered 1–46. From the first urn, 5 balls are chosen randomly, without replacement and without regard to order. From the second urn, 1 ball is chosen randomly. For a $1 bet, a player chooses one set of five numbers to match the balls selected from the first urn and one number to match the ball selected from the second urn. To win, all six numbers must match; that is, the player must match the first 5 balls selected from the first urn and the single ball selected from the second urn. What is the probability of winning the Mega Millions with a single ticket?

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According to the Centers for Disease Control, the probability that a randomly selected citizen of the United States has hearing problems is \(0.151 .\) The probability that a randomly selected citizen of the United States has vision problems is \(0.093 .\) Can we compute the probability of randomly selecting a citizen of the United States who has hearing problems or vision problems by adding these probabilities? Why or why not?

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