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91Ó°ÊÓ

Explain how standard deviation measures spread. In your explanation include the computation of the same standard deviation for two data sets: Data set I: 3,4,\(5 ;\) Data set II: 0,4,8 .

Short Answer

Expert verified
Data Set I has a standard deviation of 0.816; Data Set II has a standard deviation of 3.266.

Step by step solution

01

- Understand Standard Deviation

Standard deviation is a measure of the amount of variation or dispersion in a set of values. A lower standard deviation indicates that the values tend to be close to the mean, whereas a higher standard deviation indicates that the values spread out over a wider range.
02

- Calculate the Mean for Data Set I

Sum the values in Data Set I: 3 + 4 + 5 = 12Divide the sum by the number of values: \[ \text{Mean} = \frac{12}{3} = 4 \]
03

- Calculate the Mean for Data Set II

Sum the values in Data Set II: 0 + 4 + 8 = 12Divide the sum by the number of values: \[ \text{Mean} = \frac{12}{3} = 4 \]
04

- Compute the Variance for Data Set I

First, find the squared differences from the mean: (3-4)^2 = 1, (4-4)^2 = 0, (5-4)^2 = 1Next, find the average of these squared differences (variance): \[ \text{Variance} = \frac{1+0+1}{3} = \frac{2}{3} \]
05

- Compute the Variance for Data Set II

First, find the squared differences from the mean: (0-4)^2 = 16, (4-4)^2 = 0, (8-4)^2 = 16Next, find the average of these squared differences (variance): \[ \text{Variance} = \frac{16+0+16}{3} = \frac{32}{3} \]
06

- Compute the Standard Deviation for Data Set I

Take the square root of the variance for Data Set I: \[ \text{Standard Deviation} = \text{sqrt}\bigg(\frac{2}{3}\bigg) \ \text{Standard Deviation} \ \text{ = } 0.816 \]
07

- Compute the Standard Deviation for Data Set II

Take the square root of the variance for Data Set II: \[ \text{Standard Deviation} = \text{sqrt}\bigg(\frac{32}{3}\bigg) \ \text{Standard Deviation} \ \text{ = } 3.266 \]
08

- Interpret the Results

Data Set I has a standard deviation of 0.816, indicating that the values are close to the mean. Data Set II has a standard deviation of 3.266, showing that the values are more spread out from the mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Data Spread
Understanding how data is spread helps in interpreting the consistency of your data set. Data spread is a way to describe how much variability there is in your data.
It tells us if the numbers are mostly concentrated around the mean or scattered far away.

One common way to measure data spread is by using **standard deviation**. It gives you a sense of the average distance from each data point to the mean of the data set.
For example, in Data Set I (3, 4, 5), the standard deviation is 0.816, meaning the values are fairly close to the mean (4).
In Data Set II (0, 4, 8), the standard deviation is 3.266, indicating that the values are more spread out from the mean (4).

Knowing the spread can help you understand the reliability and consistency of your data. It is especially useful in fields like statistics, finance, and science, where precise data analysis is crucial.
Variance
Variance is a measure of how much the data points in a set differ from the mean.
It is calculated by finding the average of the squared differences from the mean.

Variance helps quantify the spread of your data; it is basically the average squared deviation from the mean.
For example, in Data Set I, the variance is calculated as follows: (3-4)² = 1, (4-4)² = 0, (5-4)² = 1
Then, the variance is the average of these values: \[ \text{Variance} = \frac{1+0+1}{3} = \frac{2}{3} \]

In Data Set II, the variance calculation is similar: (0-4)² = 16, (4-4)² = 0, (8-4)² = 16
The variance is: \[ \text{Variance} = \frac{16+0+16}{3} = \frac{32}{3} \]

Variance gives you an idea of the data's spread but is not in the same unit as your data. For that, we use standard deviation, which is the square root of variance, to get back to the original units.
Mean Calculation
Calculating the mean is often the first step in understanding a data set.
The mean, or average, gives you a central value that represents your data set.

To calculate the mean, you sum up all values in your data set and then divide by the number of values.

For Data Set I, we have: 3 + 4 + 5 = 12
Since there are 3 numbers, the mean is: \[ \text{Mean} = \frac{12}{3} = 4 \]

For Data Set II, the calculation is similar: 0 + 4 + 8 = 12
Again, with 3 values, the mean is: \[ \text{Mean} = \frac{12}{3} = 4 \]

When both data sets have the same mean, we look at other measures like variance and standard deviation to understand the distribution better.
Just knowing the mean does not tell you about the spread or consistency, which is why we calculate variance and standard deviation as well.

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Most popular questions from this chapter

The average 20 - to 29 -year-old man is 69.6 inches tall, with a standard deviation of 3.0 inches, while the average 20 - to 29 -year-old woman is 64.1 inches tall, with a standard deviation of 3.8 inches. Who is relatively taller, a 67-inch man or a 62 -inch woman?

In Problem 25 from Section 3.1, we drew a histogram of the weights of \(\mathrm{M\&Ms}\) and found that the distribution is symmetric. Draw a box plot of these data. Use the box plot and quartiles to confirm the distribution is symmetric. For convenience, the data are displayed again. $$ \begin{array}{ccccccc} \hline 0.87 & 0.88 & 0.82 & 0.90 & 0.90 & 0.84 & 0.84 \\ \hline 0.91 & 0.94 & 0.86 & 0.86 & 0.86 & 0.88 & 0.87 \\ \hline 0.89 & 0.91 & 0.86 & 0.87 & 0.93 & 0.88 & \\ \hline 0.83 & 0.95 & 0.87 & 0.93 & 0.91 & 0.85 & \\ \hline 0.91 & 0.91 & 0.86 & 0.89 & 0.87 & 0.84 & \\ \hline 0.88 & 0.88 & 0.89 & 0.79 & 0.82 & 0.83 & \\ \hline 0.90 & 0.88 & 0.84 & 0.93 & 0.81 & 0.90 & \\ \hline 0.88 & 0.92 & 0.85 & 0.84 & 0.84 & 0.86 & \\ \hline \end{array} $$

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