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According to the U.S. Census Bureau, the mean of the commute time to work for a resident of Boston, Massachusetts, is 27.3 minutes. Assume that the standard deviation of the commute time is 8.1 minutes to answer the following: (a) What minimum percentage of commuters in Boston has a commute time within 2 standard deviations of the mean? (b) What minimum percentage of commuters in Boston has a commute time within 1.5 standard deviations of the mean? What are the commute times within 1.5 standard deviations of the mean? (c) What is the minimum percentage of commuters who have commute times between 3 minutes and 51.6 minutes?

Short Answer

Expert verified
(a) At least 75% (b) At least 55.56%, 15.15 to 39.45 minutes (c) At least 88.89%

Step by step solution

01

Understand the Problem

The goal is to find the percentages of commuters within certain ranges of commute times, given the mean and standard deviation of commute times in Boston.
02

Recall Chebyshev's Theorem

Chebyshev's theorem states that for any distribution, at least \(\frac{1}{k^2}\) of the data values will lie within \(k\) standard deviations of the mean, where \(k\) is greater than 1.
03

Calculate for part (a)

For part (a), \(k = 2\). According to Chebyshev's theorem, at least \[1 - \frac{1}{2^2} = 1 - 0.25 = 0.75 = 75\text{%}\right\] of data lies within 2 standard deviations of the mean.
04

Calculate for part (b)

For part (b), \(k = 1.5\). According to Chebyshev's theorem, at least \[1 - \frac{1}{1.5^2} = 1 - \frac{1}{2.25} = 1 - 0.4444 \approx 0.5556 = 55.56\text{%}\right\] of data lies within 1.5 standard deviations of the mean.
05

Determine commute times for part (b)

The range of commute times within 1.5 standard deviations is: \[\text{Mean} \pm 1.5 \times \text{Standard Deviation} = 27.3 \pm 1.5 \times 8.1 = 27.3 \pm 12.15\] This gives a range of \[\text{from } 27.3 - 12.15 = 15.15 \text{ minutes to } 27.3 + 12.15 = 39.45 \text{ minutes}\right\]
06

Calculate for part (c)

For part (c), we need to find the percentage of commuters with commute times between 3 minutes and 51.6 minutes. This can be formulated as within a range based on the mean and standard deviation. Convert the times: \[51.6 - 27.3 = 24.3 \text{ minutes above the mean}\right\] and \[27.3 - 3 = 24.3 \text{ minutes below the mean}\right\]. This translates to: \[k = \frac{24.3}{8.1} = 3\]. According to Chebyshev's theorem: \[1 - \frac{1}{3^2} = 1 - \frac{1}{9} = 0.8889 = 88.89\text{%}\right\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Commute Time Calculations
Commute time calculations help us understand the variability in people's daily travel times. In our example with Boston, the average commute time is 27.3 minutes. This 'average' is called the mean. Knowing the mean alone isn’t very helpful because not everyone has the same commute time. Here's where calculations come in handy.
When we talk about commute times within certain ranges, we're essentially looking at how much most people's travel times vary around the average. Calculations like these are important for city planning, road traffic management, and even just for individuals to plan their day better. By considering these ranges, we can find out how many people spend roughly the same amount of time commuting. By using standard deviations, we can break down these times into more digestible and practical information.
Standard Deviations
A standard deviation is a measure of how spread out commute times—or any other data—are from the average. In simpler words, it tells us whether most people have commute times close to the mean (average) or if they vary widely. In the Boston example, the standard deviation is 8.1 minutes.
Here’s how we use it:
  • If you go 1 standard deviation away from the mean (plus or minus), you cover many commute times close to the average.
    That range covers from 27.3 - 8.1 = 19.2 to 27.3 + 8.1 = 35.4 minutes.
  • At 2 standard deviations away (from the mean), you capture even more—showing 27.3 - 16.2 = 11.1 to 27.3 + 16.2 = 43.5 minutes.
  • For 1.5 standard deviations, calculate 27.3 ± 1.5 * 8.1 to get around 15.15 to 39.45 minutes.
Standard deviations are used for consistency in analysis, and they can help identify unusual data points, like extremely long commute times.
Mean and Standard Deviation
To understand data properly, especially for something as variable as commute times, you need to know two basic things: the mean and the standard deviation. The mean (27.3 minutes in our case) tells us the average commute time. It's what most people experience.
However, the mean alone doesn't tell the whole story. Some people have commute times much shorter or longer.
Here's where the standard deviation (8.1 minutes) comes into play. It complements the mean by showing how much the commute times vary around this average. So, when you hear about distances from the mean like 'within 2 standard deviations' or '1.5 standard deviations,' they are simply referencing how much variation there is in the commute times.
Together, the mean and standard deviation help to paint a complete picture, allowing us to say things like 'at least 75% of people have commute times within 2 standard deviations of the mean' thanks to Chebyshev's Theorem. This helps in planning better routes, adjusting work schedules, and improving overall commuter satisfaction.

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Most popular questions from this chapter

One variable that is measured by online homework systems is the amount of time a student spends on homework for each section of the text. The following is a summary of the number of minutes a student spends for each section of the text for the fall 2014 semester in a College Algebra class at Joliet Junior College. $$ Q_{1}=42 \quad Q_{2}=51.5 \quad Q_{3}=72.5 $$ (a) Provide an interpretation of these results. (b) Determine and interpret the interquartile range. (c) Suppose a student spent 2 hours doing homework for a section. Is this an outlier? (d) Do you believe that the distribution of time spent doing homework is skewed or symmetric? Why?

A histogram of a set of data indicates that the distribution of the data is skewed right. Which measure of central tendency will likely be larger, the mean or the median? Why?

Mensa is an organization designed for people of high intelligence. One qualifies for Mensa if one's intelligence is measured at or above the 98 th percentile. Explain what this means.

True or False: Chebyshev's Inequality applies to all distributions regardless of shape, but the Empirical Rule holds only for distributions that are bell shaped.

The data on the following page represent the pulse rates (beats per minute) of nine students enrolled in a section of Sullivan's course in Introductory Statistics. Treat the nine students as a population. $$ \begin{array}{lc} \text { Student } & \text { Pulse } \\ \hline \text { Perpectual Bempah } & 76 \\ \hline \text { Megan Brooks } & 60 \\ \hline \text { Jeff Honeycutt } & 60 \\ \hline \text { Clarice Jefferson } & 81 \\ \hline \text { Crystal Kurtenbach } & 72 \\ \hline \text { Janette Lantka } & 80 \\ \hline \text { Kevin MeCarthy } & 80 \\ \hline \text { Tammy Ohm } & 68 \\ \hline \text { Kathy Wojdyla } & 73 \end{array} $$ (a) Determine the population standard deviation. (b) Find three simple random samples of size 3 , and determine the sample standard deviation of each sample. (c) Which samples underestimate the population standard deviation? Which overestimate the population standard deviation?

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