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More Age Estimation In the article "Bigger Teeth for Longer Life? Longevity and Molar Height in Two Roe Deer Populations" (Biology Letters [June, 2007\(]\) vol. 3 no. 3 \(268-270)\), researchers developed a model to predict the tooth height (in \(\mathrm{mm}\) ), \(y\), of roe deer based on their age, \(x_{1}\), gender, \(x_{2}(0=\) female \(, 1=\) male \(),\) and location, \(x_{3}\) (Trois Fontaines deer, which have a shorter life expectancy, and Chizé, which have a longer life expectancy, \(x_{3}=0\) for Trois Fontaines, \(x_{3}=1\) for Chizé). The model is $$ \hat{y}=7.790-0.382 x_{1}-0.587 x_{2}-0.925 x_{3}+0.091 x_{2} x_{3} $$ (a) What is the expected tooth length of a female roe deer who is 12 years old and lives in Trois Fontaines? (b) What is the expected tooth length of a male roe deer who is 8 years old and lives in Chizé? (c) What is the interaction term? What does the coefficient of the interaction term imply about tooth length?

Short Answer

Expert verified
a) 3.206 mm, b) 3.313 mm, c) The coefficient 0.091 implies that males in Chizé have slightly longer teeth.

Step by step solution

01

Understanding the Model

The model provided is \[ \hat{y} = 7.790 - 0.382x_1 - 0.587x_2 - 0.925x_3 + 0.091x_2x_3 \]. To find the expected tooth length, substitute the values of age \(x_1\), gender \(x_2\), and location \(x_3\).
02

Solve Part (a)

For a female roe deer who is 12 years old and lives in Trois Fontaines: \[ x_1 = 12, \, x_2 = 0, \, x_3 = 0 \]. Substitute these values into the model: \[ \hat{y} = 7.790 - 0.382 \times 12 - 0.587 \times 0 - 0.925 \times 0 + 0.091 \times 0 \times 0 \]. Calculate: \[ \hat{y} = 7.790 - 4.584 = 3.206 \]. Thus, the expected tooth length is 3.206 mm.
03

Solve Part (b)

For a male roe deer who is 8 years old and lives in Chizé: \[ x_1 = 8, \, x_2 = 1, \, x_3 = 1 \]. Substitute these values into the model: \[ \hat{y} = 7.790 - 0.382 \times 8 - 0.587 \times 1 - 0.925 \times 1 + 0.091 \times 1 \times 1 \]. Calculate: \[ \hat{y} = 7.790 - 3.056 - 0.587 - 0.925 + 0.091 = 3.313 \]. Thus, the expected tooth length is 3.313 mm.
04

Solve Part (c)

The interaction term is \( 0.091x_2x_3 \). This term accounts for the interaction between gender and location. The coefficient 0.091 implies that for every unit increase in the interaction between being male (\(x_2 = 1\)) and living in Chizé (\(x_3 = 1\)), the expected tooth length increases by 0.091 mm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression Model
A linear regression model is a statistical method used to approximate the relationship between a dependent variable and one or more independent variables. In the given exercise, the dependent variable is the tooth height of roe deer, denoted as \(y\). The independent variables are age (\(x_1\)), gender (\(x_2\)), and location (\(x_3\)).

The general form of a linear regression model can be written as: \[ \hat{y} = \beta_0 + \beta_1x_1 + \beta_2x_2 + ... + \beta_nx_n \] where:
  • \( \hat{y} \) is the predicted value of the dependent variable,
  • \( \beta_0 \) is the y-intercept,
  • \( \beta_1, \beta_2, ..., \beta_n \) are the regression coefficients for the independent variables.
In this exercise, the model is given by: \[ \hat{y} = 7.790 - 0.382x_1 - 0.587x_2 - 0.925x_3 + 0.091x_2x_3 \].
This model can be used to predict the tooth height of a roe deer by substituting specific values for \(x_1\), \(x_2\), and \(x_3\).
Interaction Term
An interaction term in a regression model allows us to examine whether the effect of one independent variable on the dependent variable depends on the value of another independent variable.

In this exercise, the interaction term is \(0.091x_2x_3\). This term is a product of two independent variables: gender (\(x_2\)) and location (\(x_3\)). It helps us understand how the combined impact of gender and location affects tooth height.

The coefficient of the interaction term (0.091) implies that for every unit increase in the combined effect of a deer being male (\(x_2 = 1\)) and living in Chizé (\(x_3 = 1\)), the predicted tooth height increases by 0.091 mm.

This is important because it shows that the effect of gender on tooth height is different depending on the location of the deer. Such insights can be valuable in understanding the underlying biological or environmental interactions.
Variable Substitution
Variable substitution is a crucial step in the linear regression model when we want to predict the value of the dependent variable for specific cases.

To find the expected tooth length for a roe deer, you would substitute the values of the independent variables (age, gender, location) into the regression equation.

For example, to predict the tooth length for a female roe deer who is 12 years old and lives in Trois Fontaines, we use \(x_1 = 12\), \(x_2 = 0\), and \(x_3 = 0\). Substituting these values into the model:

\[ \hat{y} = 7.790 - 0.382(12) - 0.587(0) - 0.925(0) + 0.091(0)(0) = 3.206 \]

Similarly, for a male roe deer who is 8 years old and lives in Chizé, use \(x_1 = 8\), \(x_2 = 1\), and \(x_3 = 1\). Substituting these values:

\[ \hat{y} = 7.790 - 0.382(8) - 0.587(1) - 0.925(1) + 0.091(1)(1) = 3.313 \]
Therefore, variable substitution aids in deriving specific predictions from a statistical model.
Regression Coefficients
Regression coefficients are values that multiply the independent variables in a regression equation. They indicate the strength and direction of the relationship between the independent variables and the dependent variable.

In the given model:
  • The coefficient for age \( -0.382 \) suggests that each additional year of age decreases the expected tooth height by 0.382 mm.
  • The coefficient for gender \( -0.587 \) implies that being male decreases the expected tooth height by 0.587 mm compared to being female (holding other factors constant).
  • The coefficient for location \( -0.925 \) indicates that living in Chizé (compared to Trois Fontaines) decreases the expected tooth height by 0.925 mm.
  • The coefficient for the interaction term \[ x_2 x_3 \] \(0.091\) indicates the combined effect of being male and living in Chizé increases the expected tooth height by 0.091 mm.
Therefore, regression coefficients explain how much and in what direction the dependent variable (tooth height) changes with each one-unit change in an independent variable.

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Most popular questions from this chapter

Life Cycle Hypothesis In the \(1950 \mathrm{~s}\), Franco Modigliani developed the Life Cycle Hypothesis. One tenet of this hypothesis is that income varies with age. The following data represent the annual income and age of a random sample of 15 adult Americans. $$ \begin{array}{cc|cc} \text { Age, } x & \text { Income, } y & \text { Age, } x & \text { Income, } y \\ \hline 25 & 25,490 & 47 & 41,398 \\ \hline 27 & 26,910 & 52 & 36,474 \\ \hline 32 & 32,141 & 54 & 38,934 \\ \hline 37 & 35,893 & 57 & 35,775 \\ \hline 42 & 36,451 & 62 & 30,629 \\ \hline 42 & 38,093 & 67 & 22,708 \\ \hline 47 & 36,266 & 72 & 20,506 \end{array} $$ (a) Draw a scatter diagram of the data. What type of relation appears to exist between \(x\) and \(y ?\) (b) Find the quadratic regression equation \(\hat{y}=b_{0}+b_{1} x+b_{2} x^{2}\). (c) Draw a residual plot against the fitted values, \(x,\) and \(x^{2}\). Also, draw a boxplot of the residuals. Are there any problems with the model? (d) Interpret the coefficient of determination. (e) Does the \(F\) -test indicate that we should reject \(H_{0}: \beta_{1}=\beta_{2}=0 ?\) Is either coefficient not significantly different from zero? (f) Construct and interpret \(95 \%\) confidence and prediction intervals incomes for an age of 45 years.

Suppose a least-squares regression line is given by \(\hat{y}=4.302 x-3.293 .\) What is the mean value of the response variable if \(x=20 ?\)

Explain the difference between the coefficient of determination, \(R^{2}\), and the adjusted coefficient of determination, \(R_{\text {adj. }}^{2}\) Which is better for determining whether an additional explanatory variable should be added to the regression model?

CEO Performance (Refer to Problem 31 in Section 4.1 ) The following data represent the total compensation for 12 randomly selected chief executive officers (CEOs) and the company's stock performance in \(2013 .\) $$ \begin{array}{lcc} \text { Company } & \begin{array}{l} \text { Compensation } \\ \text { (millions of dollars) } \end{array} & \begin{array}{l} \text { Stock } \\ \text { Return (\%) } \end{array} \\ \hline \text { Navistar International } & 14.53 & 75.43 \\ \hline \text { Aviv REIT } & 4.09 & 64.01 \\ \hline \text { Groupon } & 7.11 & 142.07 \\ \hline \text { Inland Real Estate } & 1.05 & 32.72 \\ \hline \text { Equity Lifestyles Properties } & 1.97 & 10.64 \\ \hline \text { Tootsie Roll Industries } & 3.76 & 30.66 \\ \hline \text { Catamaran } & 12.06 & 0.77 \\ \hline \text { Packaging Corp of America } & 7.62 & 69.39 \\ \hline \text { Brunswick } & 8.47 & 58.69 \\ \hline \text { LKQ } & 4.04 & 55.93 \\ \hline \text { Abbott Laboratories } & 20.87 & 24.28 \\ \hline \text { TreeHouse Foods } & 6.63 & 32.21 \end{array} $$ (a) Treating compensation as the explanatory variable, \(x\), determine the estimates of \(\beta_{0}\) and \(\beta_{1}\). (b) Assuming the residuals are normally distributed, test whether a linear relation exists between compensation and stock return at the \(\alpha=0.05\) level of significance. (c) Assuming the residuals are normally distributed, construct a \(95 \%\) confidence interval for the slope of the true leastsquares regression line. (d) Based on your results to parts (b) and (c), would you recommend using the least-squares regression line to predict the stock return of a company based on the CEO's compensation? Why? What would be a good estimate of the stock return based on the data in the table?

A multiple regression model has \(k=4\) explanatory variables The coefficient of determination, \(R^{2},\) is found to be 0.542 based on a sample of \(n=40\) observations. (a) Compute the adjusted \(R^{2}\). (b) Compute the \(F\) -test statistic. (c) If one additional explanatory variable is added to the model and \(R^{2}\) increases to \(0.579,\) compute the adjusted \(R^{2}\). Would you recommend adding the additional explanatory variable to the model? Why or why not?

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