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91Ó°ÊÓ

When testing whether there is a linear relation between the response variable and the explanatory variables, we use an \(F\) -test. If the \(P\) -value indicates that we reject the null hypothesis, \(H_{0}: \beta_{1}=\beta_{2}=\cdots=\beta_{k}=0,\) what conclusion should we come to? Is it possible that one of the \(\beta_{i}\) is zero if we reject the null hypothesis?

Short Answer

Expert verified
Rejecting the null hypothesis means at least one beta_{i} is not zero, indicating a significant linear relationship. However, some beta_{i} could still be zero.

Step by step solution

01

Understand the Hypothesis

The null hypothesis (H_{0}) for an Ftest in this context states that all the coefficients of the explanatory variables (beta_{1}, beta_{2}, ..., beta_{k}) are equal to zero. This means that none of the explanatory variables have a linear relationship with the response variable.
02

Interpret the P-value

If the P-value is less than the significance level (usually α = 0.05), we reject the null hypothesis. This indicates that at least one of the coefficients is not zero, suggesting that there is a significant linear relationship between the response variable and at least one of the explanatory variables.
03

Conclusion from Rejection

By rejecting the null hypothesis, we conclude that at least one of the beta_{i} is different from zero. This implies that there is a significant linear relationship between the response variable and at least one of the explanatory variables.
04

Possibility of Zero Coefficients

Even though we have rejected the null hypothesis, it is still possible that some (but not all) of the beta_{i} are zero. The Ftest only indicates that at least one coefficient is not zero, but it does not specify which coefficients are non-zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing in the context of linear regression helps us determine if there is a significant relationship between the response variable and the explanatory variables. We start with two hypotheses: the null hypothesis \(H_{0}\) and the alternative hypothesis \(H_{a}\). The null hypothesis \(H_{0}\) states that there is no linear relationship, meaning \(\beta_{1}=\beta_{2} = \cdots = \beta_{k}=0\). If the null hypothesis is true, it implies that the explanatory variables do not predict the response variable at all.

The alternative hypothesis \(H_{a}\), on the other hand, suggests that at least one of the coefficients is not zero, indicating a linear relationship between the response variable and at least one of the explanatory variables. Hypothesis testing allows us to make a decision regarding these hypotheses based on the data.

In practice, we use an F-test to compare the fits of different linear models and decide whether or not to reject the null hypothesis.
P-value Interpretation
The P-value plays a crucial role in hypothesis testing. It helps us decide whether to reject the null hypothesis. The P-value is the probability of obtaining an effect at least as extreme as the one observed in your data, assuming that the null hypothesis is true.

In the context of linear regression, if the P-value is less than a chosen significance level (commonly α = 0.05), it suggests that the observed data is unlikely under the null hypothesis. Thus, we would reject the null hypothesis and conclude that there is a significant linear relationship.

However, it is essential to note that a very small P-value does not tell us the magnitude or the practical importance of the relationship; it merely indicates statistical significance.
Linear Relationship Analysis
When we reject the null hypothesis in an F-test, it tells us that there is a significant linear relationship between the response variable and at least one of the explanatory variables. This conclusion is based on the fact that at least one coefficient \(\beta_{i}\) is different from zero.

Despite this conclusion, it is still possible for some coefficients to be zero. The F-test does not specify which coefficients are non-zero. Therefore, further analysis is often required to identify which specific explanatory variables have significant relationships.

Understanding which variables are significant helps in constructing a more precise and efficient model. This often involves looking at individual t-tests for each coefficient, which can pinpoint the variables that contribute meaningfully to the response variable.

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Most popular questions from this chapter

Putting It Together: Purchasing Diamonds The value of a diamond is determined by the four C's: carat weight, color, clarity, and cut. Carat weight is the standard measure for the size of a diamond. Generally, the more a diamond weighs, the more valuable it will be. The Gemological Institute of America (GIA) determines the color of diamonds using a 22 -grade scale from D (almost clear white) to \(Z\) (light yellow). Colorless diamonds are generally considered the most desirable. The clarity of a diamond refers to how "free" the diamond is of imperfections and is determined using an 11 -grade scale: flawless (FL), internally flawless (IF), very, very slightly imperfect (VVS1, VVS2), very slightly imperfect (VS1, VS2), slightly imperfect (SI1,SI2), and imperfect (I1, I2, I3). The cut of a diamond refers to the diamond's proportions and finish. Put simply, the better the diamond's cut is, the better it reflects and refracts light, which makes it more beautiful and thus more valuable. The cut of a diamond is rated using a five-grade scale: Excellent, Very Good, Good, Fair, and Poor. Finally, the shape of a diamond (which is not one of the four C's) refers to its basic form: round, oval, pear-shaped, marquis, and so on. A novice might confuse shape with cut, so be careful not to confuse the two. Go to www.pearsonhighered.com/sullivanstats to obtain the data file \(14_{-} 6_{-} 8\) using the file format of your choice for the version of the text you are using. The data represent a random sample of 40 unmounted, round-shaped diamonds. Use the data to answer the questions that follow: (a) Determine the level of measurement for each variable. (i) Carat weight (iv) Cut (ii) Color (v) Price (iii) Clarity (vi) Shape (b) Construct a correlation matrix. To do so, first convert the variables color, clarity, and cut to numeric values as follows: Color: \(\mathrm{D}=1, \mathrm{E}=2, \mathrm{~F}=3, \mathrm{G}=4, \mathrm{H}=5, \mathrm{I}=6, \mathrm{~J}=7\) Clarity: \(\mathrm{FL}=1, \mathrm{IF}=2, \mathrm{VVS} 1=3, \mathrm{VVS} 2=4, \mathrm{VS} 1=5\) \(\mathrm{VS} 2=6, \mathrm{SI} 1=7, \mathrm{SI} 2=8\) Cut: Excellent \(=1,\) Very Good \(=2,\) Good \(=3\) If price is to be the response variable in our model, is there reason to be concerned about multicollinearity? Explain. (c) Find the "best" model for predicting the price of a diamond. (d) Draw residual plots, a boxplot of the residuals, and a normal probability plot of the residuals to assess the adequacy of the "best" model. (e) For the "best" model, interpret each regression coefficient. (f) Determine and interpret \(R^{2}\) and the adjusted \(R^{2}\). (g) Predict the mean price of a round-shaped diamond with the following characteristics: 0.85 carat, E, VVS1, Excellent. (h) Construct a \(95 \%\) confidence interval for the mean price found in part (g). (i) Predict the price of an individual round-shaped diamond with the following characteristics: 0.85 carat, E, VVS1 Excellent. (j) Construct a \(95 \%\) prediction interval for the price found in \(\operatorname{part}(\mathrm{i})\) (k) Explain why the predictions in parts \((\mathrm{g})\) and (i) are the same, yet the intervals in parts \((\mathrm{h})\) and \((\mathrm{j})\) are different.

Wanting to know if there is a linear relation among wind chill temperature, air temperature (in degrees Fahrenheit), and wind speed (in miles per hour), a researcher collected the following data for various days. $$ \begin{array}{ccc} \text { Air Temp. } & \text { Wind Speed } & \text { Wind Chill } \\ \hline 15 & 10 & 3 \\ \hline 15 & 15 & 0 \\ \hline 15 & 25 & -4 \\ \hline 0 & 5 & -11 \\ \hline 0 & 20 & -22 \\ \hline-5 & 10 & -22 \\\ \hline-5 & 25 & -31 \\ \hline-10 & 15 & -32 \\ \hline-10 & 20 & -35 \\\ \hline-15 & 25 & -44 \\ \hline-15 & 35 & -48 \\ \hline-15 & 50 & -52 \\\ \hline 5 & 40 & -22 \\ \hline 10 & 45 & -16 \\ \hline \end{array} $$ (a) Find the least-squares regression equation \(\hat{y}=b_{0}+b_{1} x_{1}+b_{2} x_{2},\) where \(x_{1}\) is air temperature, \(x_{2}\) is wind speed, and \(y\) is the response variable "wind chill." (b) Draw residual plots to assess the adequacy of the model. What might you conclude based on the plot of residuals against wind speed?

Concrete As concrete cures, it gains strength. The following data represent the 7 -day and 28 -day strength (in pounds per square inch) of a certain type of concrete: $$ \begin{array}{cc|cc} \begin{array}{l} \text { 7-Day } \\ \text { Strength, } x \end{array} & \begin{array}{l} \text { 28-Day } \\ \text { Strength, } y \end{array} & \begin{array}{l} \text { 7-Day } \\ \text { Strength, } x \end{array} & \begin{array}{l} \text { 28-Day } \\ \text { Strength, } \boldsymbol{y} \end{array} \\ \hline 2300 & 4070 & 2480 & 4120 \\ \hline 3390 & 5220 & 3380 & 5020 \\ \hline 2430 & 4640 & 2660 & 4890 \\ \hline 2890 & 4620 & 2620 & 4190 \\ \hline 3330 & 4850 & 3340 & 4630 \\ \hline \end{array} $$ (a) Treating the 7 -day strength as the explanatory variable, \(x\), determine the estimates of \(\beta_{0}\) and \(\beta_{1}\). (b) Compute the standard error of the estimate. (c) Determine \(s_{b_{1}}\). (d) Assuming the residuals are normally distributed, test whether a linear relation exists between 7 -day strength and 28 -day strength at the \(\alpha=0.05\) level of significance. (e) Assuming the residuals are normally distributed, construct a \(95 \%\) confidence interval for the slope of the true leastsquares regression line. (f) What is the estimated mean 28 -day strength of this concrete if the 7 -day strength is 3000 psi?

True or False: The value of \(R^{2}\) never decreases as more explanatory variables are added to a regression model.

(a) Draw a scatter diagram of the data. What type of relation appears to exist between \(x\) and \(y ?\) (b) Find the quadratic regression equation \(\hat{y}=b_{0}+b_{1} x+b_{2} x^{2}\) (c) Draw a residual plot against the fitted values, \(x,\) and \(x^{2}\). Also. draw a boxplot of the residuals. Are there any problems with the model? (d) Interpret the coefficient of determination. (e) Does the \(F\) -test indicate that we should reject \(H_{0}: \beta_{1}=\beta_{2}=0 ?\) Is either coefficient not significantly different from zero? (f) Construct and interpret \(95 \%\) confidence and prediction intervals for \(x=4\) $$ \begin{array}{cc} x & y \\ \hline 2.3 & 19.3 \\ \hline 2.7 & 14.8 \\ \hline 3.2 & 10.2 \\ \hline 4.1 & 4.8 \\ \hline 4.9 & 2.9 \\ \hline 5.6 & 3.9 \\ \hline 6.4 & 7.9 \\ \hline \end{array} $$

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