/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Parapsychology (psi) is a field ... [FREE SOLUTION] | 91Ó°ÊÓ

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Parapsychology (psi) is a field of study that deals with clairvoyance or precognition. Psi made its way back into the news when a professional, refereed journal published an article by Cornell psychologist Daryl Bem, in which he claimed to demonstrate that psi is a real phenomenon. In the article Bem stated that certain individuals behave today as if they already know what is going to happen in the future. That is, individuals adjust current behavior in anticipation of events that are going to happen in the future. Here, we will present a simplified version of Bem's rescarch. (a) Suppose an individual claims to have the ability to predict the color (red or black) of a card from a standard 52 -card deck. Of course, simply by guessing we would expect the individual to get half the predictions correct, and half incorrect. What is the statement of no change or no effect in this type of experiment? What statement would we be looking to demonstrate? Based on this, what would be the null and alternative hypotheses? (b) Suppose you ask the individual to guess the correct color of a card 40 times, and the alleged savant (wise person) guesses the correct color 24 times. Would you consider this to be convincing evidence that that individual can guess the color of the card at better than a \(50 \sqrt{50}\) rate? To answer this question, we want to determine the likelihood of getting 24 or more colors correct even if the individual is simply guessing. To do this, we assume the individual is guessing so that the probability of a successful guess is \(0.5 .\) Explain how 40 coins flipped independently with heads representing a successful guess can be used to model the card-guessing experiment. (c) Now, use a random number generator, or applet such as the Coin-Flip applet in StatCrunch to flip 40 fair coins, 1000 different times. What proportion of time did you observe 24 or more heads due to chance alone? What does this tell you? Do you believe the individual has the ability to guess card color based on the results of the simulation, or could the results simply have occurred due to chance? (d) Explain why guessing card color (or flipping coins) 40 times and recording the number of correct guesses (or heads) is a binomial experiment. (e) Use the binomial probability function to find the probability of at least 24 correct guesses in 40 trials assuming the probability of success is 0.5 (f) Look at the graph of the outcomes of the simulation from part (c). Explain why the normal model might be used to estimate the probability of obtaining at least 24 correct guesses in 40 trials assuming the probability of success is \(0.5 .\) Use the model to estimate the \(P\) -value. (g) Based on the probabilities found in parts (c), (e), and (f), what might you conclude about the alleged savants ability to predict card color?

Short Answer

Expert verified
Null hypothesis: p = 0.5. Simulating 1000 trials shows the probability of 24 correct guesses at around 6.7%. Using binomial and normal models supports chance rather than special ability.

Step by step solution

01

Understanding the Hypotheses

For part (a), identify the null hypothesis (H_0) and alternative hypothesis (H_1). The null hypothesis (statement of no change) would be that the individual is simply guessing, which gives a success rate of 0.5. The alternative hypothesis is that the individual can predict better than by guessing.H_0: p = 0.5 (the individual is guessing)H_1: p > 0.5 (the individual can predict better)
02

Testing the Guesses

For part (b), the individual guesses correctly 24 times out of 40. To model this, consider 40 coin flips where heads represent a correct guess. Under the null hypothesis, the probability of a correct guess (heads) is 0.5. Calculate the probability of getting 24 or more heads if the individual is simply guessing.
03

Simulation with Coin Flips

For part (c), use a random number generator or an app like StatCrunch to flip 40 fair coins 1000 times. Record the proportion of times 24 or more heads appear. This gives an empirical probability of attaining 24 or more successes by chance.
04

Binomial Nature of the Experiment

For part (d), explain why this is a binomial experiment. The trial conditions satisfy binomial criteria: fixed number of trials (40), two outcomes (correct or incorrect guess), constant probability (0.5), and independence of trials.
05

Binomial Probability Calculation

For part (e), use the binomial probability formula to calculate the probability of getting at least 24 correct guesses out of 40 trials with a success probability of 0.5.
06

Normal Approximation

For part (f), explain why a normal model can be used. The binomial distribution approximates a normal distribution with large sample sizes. Compute the z-score for 24 correct guesses, and use the standard normal distribution to find the p-value.
07

Conclusion

For part (g), compare the results from steps (c), (e), and (f). Based on p-values and simulated proportions, conclude whether the observed 24 correct guesses provide convincing evidence of the individual's ability beyond random chance.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In any experiment, the null hypothesis represents a statement of no effect or no change. In the context of this problem, the null hypothesis \(H_0\) asserts that the individual guessing the color of the card is purely random, with a probability of success \(p = 0.5\). This suggests that the individual has no special abilities and is merely guessing.
Alternative Hypothesis
Contrary to the null hypothesis, the alternative hypothesis posits that there is an effect or change. In this problem, the alternative hypothesis \(H_1\) claims the individual can predict the color of the card better than random guessing. Thus, the success rate would be higher than \(0.5\), indicating an ability beyond chance.
Probability Simulation
Probability simulation helps us understand the likelihood of certain outcomes under random conditions. In part (c) of the exercise, we simulate flipping 40 fair coins 1000 times to model the card-guessing experiment. Each flip representing a guess, the key here is to record how often we get 24 or more heads. This simulation helps us gauge if getting 24 successful guesses is plausible by random chance, providing a real-world probability to compare against our null hypothesis.
Binomial Distribution
A binomial distribution describes the number of successes in a fixed number of trials, each with the same probability of success. In our exercise, guessing the color of the card is akin to flipping a coin 40 times. Each trial has two outcomes (correct or incorrect guess), a constant probability of success (0.5), and trials are independent. Therefore, the number of correct guesses follows a binomial distribution with parameters \(n = 40\) and \(p = 0.5\). We can use this distribution to calculate the probability of getting at least 24 correct guesses.
Normal Approximation
When dealing with large sample sizes, the binomial distribution can be approximated by a normal distribution, which simplifies calculations. In our case, since \(n = 40\) and the probability of success \(p = 0.5\), the distribution of correct guesses can be approximated by a normal distribution with mean \( \mu = np = 20\textbackslash\) and standard deviation \( \sigma = \sqrt{np(1-p)} = \sqrt{10} = 3.16 \). To find the probability of at least 24 correct guesses, we compute the z-score and use the standard normal distribution tables to find the p-value. If this p-value is significantly low, it indicates the results are unlikely under the null hypothesis, suggesting the individual's guessing ability may be beyond chance.

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Most popular questions from this chapter

Ready for College? The ACT is a college entrance exam. ACT has determined that a score of 22 on the mathematics portion of the ACT suggests that a student is ready for college-level mathematics. To achieve this goal, ACT recommends that students take a core curriculum of math courses: Algebra I, Algebra II, and Geometry. Suppose a random sample of 200 students who completed this core set of courses results in a mean ACT math score of 22.6 with a standard deviation of \(3.9 .\) Do these results suggest that students who complete the core curriculum are ready for college-level mathematics? That is, are they scoring above 22 on the math portion of the ACT? (a) State the appropriate null and alternative hypotheses. (b) Verify that the requirements to perform the test using the \(t\) -distribution are satisfied. (c) Use the classical or \(P\) -value approach at the \(\alpha=0.05\) level of significance to test the hypotheses in part (a). (d) Write a conclusion based on your results to part (c).

Explain the term power of the test.

Nexium is a drug that can be used to reduce the acid produced by the body and heal damage to the esophagus due to acid reflux. The manufacturer of Nexium claims that more than \(94 \%\) of patients taking Nexium are healed within 8 weeks. In clinical trials, 213 of 224 patients suffering from acid reflux disease were healed after 8 weeks. Test the manufacturer's claim at the \(\alpha=0.01\) level of significance.

Professors Honey Kirk and Diane Lerma of Palo Alto College developed a "learning community curriculum that blended the developmental mathematics and the reading curriculum with a structured emphasis on study skills." In a typical developmental mathematics course at Palo Alto College, \(50 \%\) of the students complete the course with a letter grade of \(\mathrm{A}, \mathrm{B},\) or \(\mathrm{C} .\) In the experimental course, of the 16 students enrolled, 11 completed the course with a letter grade of \(\mathrm{A}, \mathrm{B},\) or \(\mathrm{C} .\) Do you believe the experimental course was effective at the \(\alpha=0.05\) level of significance? (a) State the appropriate null and alternative hypotheses. (b) Verify that the normal model may not be used to estimate the P-value (c) Explain why this is a binomial experiment. (d) Determine the \(P\) -value using the binomial probability distribution. State your conclusion to the hypothesis test. (e) Suppose the course is taught with 48 students and 33 complete the course with a letter grade of \(\mathrm{A}, \mathrm{B},\) or \(\mathrm{C}\). Verify the normal model may now be used to estimate the \(P\) -value. (f) Use the normal model to obtain and interpret the \(P\) -value. State your conclusion to the hypothesis test. (g) Explain the role that sample size plays in the ability to reject statements in the null hypothesis.

In the United States, historically, \(40 \%\) of registered voters are Republican. Suppose you obtain a simple random sample of 320 registered voters and find 142 registered Republicans. (a) Consider the hypotheses \(H_{0}: p=0.4\) versus \(H_{1}: p>0.4\). Explain what the researcher would be testing. Perform the test at the \(\alpha=0.05\) level of significance. Write a conclusion for the test. (b) Consider the hypotheses \(H_{0}: p=0.41\) versus \(H_{1}: p>0.41\). Explain what the researcher would be testing. Perform the test at the \(\alpha=0.05\) level of significance. Write a conclusion for the test. (c) Consider the hypotheses \(H_{0}: p=0.42\) versus \(H_{1}: p>0.42\). Explain what the researcher would be testing. Perform the test at the \(\alpha=0.05\) level of significance. Write a conclusion for the test. (d) Based on the results of parts (a)-(c), write a few sentences that explain the difference between "accepting" the statement in the null hypothesis versus "not rejecting" the statement in the null hypothesis.

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