/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Decide whether the problem requi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Decide whether the problem requires a confidence interval or hypothesis test, and determine the variable of interest. For any problem requiring a confidence interval, state whether the confidence interval will be for a population proportion or population mean. For any problem requiring a hypothesis test, write the null and alternative hypothesis. A researcher wanted to estimate the average length of time mothers who gave birth via Caesarean section spent in a hospital after delivery of the baby.

Short Answer

Expert verified
This problem requires a confidence interval for the population mean duration of hospital stay after Caesarean section.

Step by step solution

01

Determine the Objective

The researcher wants to estimate the average length of time mothers who gave birth via Caesarean section spent in a hospital after delivery.
02

Identify the Approach

Since the goal is to estimate an average, the exercise requires constructing a confidence interval.
03

Variable of Interest

The variable of interest is the average length of time mothers who gave birth via Caesarean section spend in a hospital after delivery.
04

Choose the Type of Confidence Interval

Because the variable of interest is an average (mean), the confidence interval will be for a population mean.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Test
A hypothesis test is a method used to decide whether there is enough evidence to reject a null hypothesis. This process involves comparing sample data against a statement or claim made about the population.

There are two types of hypotheses in this test:
  • Null hypothesis (\(H_0\)): It states that there is no effect or no difference. It's the assumption that the observed data is due to chance.
  • Alternative hypothesis (\(H_1\text{ or } H_A\)): It states the opposite of the null hypothesis. It suggests that there is an effect or a difference.
The test calculates a p-value, which indicates the probability of obtaining the observed data, assuming the null hypothesis is true. If the p-value is lower than a predetermined significance level (usually 0.05), the null hypothesis is rejected.
Population Mean
The population mean (\( \text{\textmu} \)) is the average of all the values in a population. It's a critical parameter in statistics, representing the central value around which data points tend to cluster.

In many real-world scenarios, like the average length of hospital stays after a Caesarean section, researchers often do not have access to the entire population. Instead, they collect a sample and use it to estimate the population mean.

To calculate the mean of a sample, use the formula:
\begin{align*} \text{Sample Mean} (\bar{X}) = \frac{\text{Sum of all sample values}}{\text{Number of sample values}} onumber onumber \bar{X} = \frac{\text{Total of sample values}}{n} onumber \text{Where } n \text{ is the sample size} onumber \text{\textmu} \text{ represents the population mean.} onumber \text{The sample mean } \bar{X} has a crucial role in estimating the population mean. onumber \text{The smaller the difference between } \bar{X} \text{ and } \text{\textmu}\text{, the more accurately the sample estimate represents the population.}
Population Proportion
The population proportion (\( p \)) represents the fraction of a population that has a specific characteristic.

Suppose you want to find out the proportion of mothers preferring Caesarean sections among all mothers in a hospital. You will look at the number of mothers who preferred Caesarean sections (x) divided by the total number of mothers surveyed (n).
The formula for calculating the sample proportion is:
\begin{align*} \text{Sample Proportion} (\frac{x}{n}) = \frac{x}{n} onumber onumber \text{where } x \text{ is the number of successes, and } n \text{ is the total number of trials}

\text{Suppose 20 out of 100 mothers preferred Caesarean sections. The sample proportion would be:} onumber \frac{20}{100} = 0.20

\text{To estimate the population proportion, researchers construct confidence intervals or conduct hypothesis tests.} onumber \text{This helps them make educated guesses about the unknown population proportions.}
Average Length of Stay
The average length of stay (ALOS) in a hospital indicates how long patients typically remain hospitalized.

This metric can measure hospital efficiency, resource utilization, and patient recovery times. In the given exercise, the interest is to find out the average days mothers spent in the hospital after giving birth via Caesarean section.

To estimate this, researchers use a sample of hospital stays and calculate the sample mean. They construct confidence intervals to estimate the population mean of the ALOS. This method provides a range of values in which the true average length of stay is likely to lie.
  • The smaller the confidence interval range, the more precise the estimate of the average length of stay is.
  • If the sample size increases, the confidence interval generally becomes narrower, thus offering a better estimate of the population mean.

  • The ALOS can help hospitals improve patient care and allocate resources more effectively. Understanding the ALOS is essential for health care planning and management.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

ACT, a college entrance exam used for admission, looked at historical records and established 21 as the minimum score on the ACT reading portion of the exam for a student to be considered prepared for social science in college. (Note: "Being prepared" means there is a \(75 \%\) probability of successfully completing a social science course in college.) An official with the Illinois State Department of Education wonders whether a majority of the students in her state who took the \(\mathrm{ACT}\) are prepared to take social science. She obtains a simple random sample of 500 records of students who have taken the \(\mathrm{ACT}\) and finds that 269 are prepared. Does this represent significant evidence that a majority (more than \(50 \%\) ) of the students in the state of Illinois are prepared for social science in college upon graduation? (a) What does it mean to make a Type II error for this test? (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, determine the probability of making a Type II error if the true population proportion is 0.52. What is the power of the test? (c) Redo part (b) if the true proportion is \(0.55 .\)

Explain what a \(P\) -value is. What is the criterion for rejecting the null hypothesis using the \(P\) -value approach?

To test \(H_{0}: p=0.30\) versus \(H_{1}: p<0.30,\) a simple random sample of \(n=300\) individuals is obtained and \(x=86\) successes are observed. (a) What does it mean to make a Type II error for this test? (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, compute the probability of making a Type II error if the true population proportion is \(0.28 .\) What is the power of the test? (c) Redo part (b) if the true population proportion is 0.25 .

Filling Bottles A certain brand of apple juice is supposed to have 64 ounces of juice. Because the penalty for underfilling bottles is severe, the target mean amount of juice is 64.05 ounces. However, the filling machine is not precise, and the exact amount of juice varies from bottle to bottle. The quality-control manager wishes to verify that the mean amount of juice in each bottle is 64.05 ounces so that she can be sure that the machine is not over- or underfilling. She randomly samples 22 bottles of juice, measures the content, and obtains the following data: $$ \begin{array}{llllll} \hline 64.05 & 64.05 & 64.03 & 63.97 & 63.95 & 64.02 \\ \hline 64.01 & 63.99 & 64.00 & 64.01 & 64.06 & 63.94 \\ \hline 63.98 & 64.05 & 63.95 & 64.01 & 64.08 & 64.01 \\ \hline 63.95 & 63.97 & 64.10 & 63.98 & & \\ \hline \end{array} $$ A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot does not show any outliers. (a) Should the assembly line be shut down so that the machine can be recalibrated? Use a 0.01 level of significance. (b) Explain why a level of significance of \(\alpha=0.01\) is more reasonable than \(\alpha=0.1 .\) [Hint: Consider the consequences of incorrectly rejecting the null hypothesis.

One aspect of queuing theory is to consider waiting time in lines. A fast-food chain is trying to determine whether it should switch from having four cash registers with four separate lines to four cash registers with a single line. It has been determined that the mean wait-time in both lines is equal. However, the chain is uncertain about which line has less variability in wait time. From experience, the chain knows that the wait times in the four separate lines are normally distributed with \(\sigma=1.2\) minutes. In a study, the chain reconfigured five restaurants to have a single line and measured the wait times for 50 randomly selected customers. The sample standard deviation was determined to be \(s=0.84\) minute. Is the variability in wait time less for a single line than for multiple lines at the \(\alpha=0.05\) level of significance?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.