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Refer to Exercise 5.18. Find the probability that

  1. x¯is less than 16.
  2. x¯is greater than 23.
  3. x¯is greater than 25.
  4. x¯falls between 16 and 22.
  5. x¯is less than 14.

Short Answer

Expert verified
  1. Probability that x¯is less than 16 is 0.0228.
  1. Probability that x¯is greater than 23 is 0.0668.
  1. Probability that x¯is greater than 15 is 0.0062.
  1. Probability that x¯falls between 16 and 22 is 0.8185.
  1. Probability that x¯is less than 14 is 0.00135.

Step by step solution

01

Given information

A random sample of n=64 observations is drawn from a population withμ=20 andσ=16 .

02

Computing the probability that x¯ is less than 16 

According to properties of the Sampling distribution of x¯μx¯=μ

andσx¯=σn

Therefore,

μx¯=20and σx¯=1664 i.e.σx¯=2

Now,

Px¯<16=Px¯μσln<16-μσn=Px¯-202<16-202=Pz<-2

Therefore, from z-score table,

Px¯<16=0.0228

Thus, probability that x¯is less than 16 is 0.0228.

03

Computing the probability that x¯ is greater than 23 

  1. x

According to properties of the Sampling distribution of localid="1660821731616" x¯μx¯=μ

andlocalid="1660821735110" σx¯=σn

Therefore,μx¯=20

μx¯=20and σx¯=1664i.e. σx¯=2

Now,

localid="1658202322115" P(x¯>23)=Px¯-μσln>23-μσln=Px¯-202>23-202=P(z>1.5)

Therefore, from z-score table,

Px>23=1-Pz<1.5=-0.9332=0.0668

Thus, probability that xis greater than 23 is 0.0668.

04

Computing the probability that x¯ is greater than 25 

According to properties of the Sampling distribution of x

localid="1660821743033" μx=μandlocalid="1660821747012" σx=σn

Therefore,

μx=20and σx=1664 i.e. σx=2

Now,

Px>25=Px-μσn>25-μσln=Px-202>25-202=Pz>2.5

Therefore, from z-score table,

Px>25=1-Pz<2.5=1-0.9937=0.0062

Thus, probability that xis greater than 15 is 0.0062.

05

Computing the probability that  falls between 16 and 22 

According to properties of the Sampling distribution of xμx=μ

andσx=σn

Therefore,

μx=20and σx=1664i.e.σx=2

Now,

Therefore, from z-score table,

Thus, probability that xfalls between 16 and 22 is 0.8185.

06

Computing the probability that is x¯ less than 14 

According to properties of the Sampling distribution of xμx=μ

andσx=σn

Therefore,μx=20

and σx=1664 i.e. σx=2

Now,

Px<14=Px-μσn<14-μσln=Px-202<14-202=Pz<-3

Therefore, from z-score table,

Px<14=Pz<-3=0.00135

Thus, probability that xis less than 14 is 0.00135.

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